Tag: mapping your way

Questions Related to mapping your way

Maps must have a ......... and a .......... .

  1. legend, scale

  2. scale, map

  3. Scale, legend

  4. none


Correct Option: C
Explanation:

Maps must have a scale and a legend

Milli starts from A and travels $2$ km and then come back for $280$ m. Then, the distance between point A and Milli is ?

  1. $2$ km

  2. $1$ km $720$ m

  3. $1$ km $200$ m

  4. $1$ km $100$ m


Correct Option: B
Explanation:

Let us take the point of start A and point at a distant $2$km be B.

$AB=2$km=$2000$m
As she come back 280m , we assume that point be C.
We have to find out the distance AC
$AC=AB-BC \therefore AC= 2000-280 = 1720= 1 $ km   $720$ m 

In a ground, the distance between two consecutive trees is $4$ m and distance between next $2$ trees is $5$ m. Then calculate the distance between first and third tree.

  1. $9$ m

  2. $5$ m

  3. $4$ m

  4. $3$ m


Correct Option: A
Explanation:

Let the first Tree be at point A, second at point B and  third one a C.

$AB=4$ m and $BC=5$ m.
$AC= AB+BC$
$\therefore AC = 9$ m.

Distance between two houses is $40$ m. If a new house with area $4\times 4$ is constructed in the middle of $2$ houses, then find the distance between middle house and one of the corner house.

  1. $20$ m

  2. $19$ m

  3. $18$ m

  4. $17$ m


Correct Option: C
Explanation:
The distance of middle point of middle house from the corner house is $\dfrac { 40 }{ 2 } =20$ and house to house distance will be $\therefore 20-2=18$
The distance between he Middle house and Corner house will be $18$ m.

In an Atlas a map occupies $\displaystyle \frac{2}{5}$th of a page with dimensions 25 cm and 30 cm respectively If the real area of the map is 10800 sq. m the scale to which the map is drawn is

  1. 1 cm = 36 m

  2. 1 cm = 26 m

  3. 1 cm = 33 m

  4. 1 cm = 6 m


Correct Option: D
Explanation:

Area occupies by the map=$(2/5)*25*30cm^{2}=300cm^{2}$
Area of $300cm^{2}$ on the map represent $10800 m^{2}$ real area of the map.
So,Area of $1cm^{2}$ on the map represent =$10800m^{2}/300cm^{2} 
                                                                       =  36m^{2}:1 cm^{2}$
Ratio of length=
$R=\sqrt { \frac { Real\quad area\quad  }{ Map\quad area } \quad  } =\sqrt { \frac { 36m^{2} }{ 1cm^{2} }  } =\frac { 6m }{ 1cm } $
Scale =1cm=6m
Answer (D) 1 cm = 6 m

$ \Delta ABC ~ \Delta PQR $ for the correspondence $ABC \leftrightarrow PQR $ . If the perimeter of $ \Delta ABC $ is $12$ and the perimeter of $ \Delta PQR $ is $20 $ , then $AB : PQ = $ ______

  1. $\dfrac {6}{5}$

  2. $\dfrac {2}{5}$

  3. $\dfrac {3}{5}$

  4. $\dfrac {1}{5}$


Correct Option: C
Explanation:
$ABC\leftrightarrow PQR$
$\dfrac{AB}{PQ}=\dfrac{AC}{PR}=\dfrac{BC}{QR}=k(say)$

$AB=k(PQ);AC=k(PR);BC=k(QR)$
$[AB+BC+AC]=k[PQ+RQ+PR]$
Perimeter $(\Delta ABC)$ = perimeter $(\Delta PQR)\times k$
$12=20\times k$

$k=\dfrac{12}{20}=\dfrac{3}{5}$

$\therefore \dfrac{AB}{PQ}=k=\dfrac{3}{5}$

Perpendicular AL, BM are drawn from the vertices A,B of a triangle ABC to meet BC, AC at L, M. by proving the triangles ALC, BMC similar, or otherwise, then CM.CA=CL.CB

  1. True

  2. False


Correct Option: A

A model of an aeroplane is made to a scale of $1:400$. Calculate the length, in cm, of the model; if the length of the aeroplane is $40$ m.

  1. $10$ cm

  2. $20$ cm

  3. $140$ cm

  4. none of the above


Correct Option: A
Explanation:

Scale $= k =$ $\dfrac{1}{400}$
Now, $\dfrac{\text{Length of model}}{\text{Length of aeroplane}} = k$
$\text{Length of model }= \dfrac{40 \times 100}{400}$
$\text{Length of model} =10$ cm

A model of an aeroplane is made to a scale of $1:400$. Calculate the length, in m, of the aeroplane, if the length of its model is $16$ cm.

  1. $68$ m

  2. $64$ m

  3. $54$ m

  4. none of the above


Correct Option: B
Explanation:

Scale $= k =$ $\dfrac{1}{400}$
Now, $\dfrac{\text{Length of model}}{\text{Length of aeroplane}} = k$
$\text{Length of aeroplace} = 400 \times 16$
$\text{Length of model }= 6400$ cm
$\text{Length of model }= 64$ m