Tag: common machines

Questions Related to common machines

Multiple choice physics simple machine common machines terms related to machines introduction to simple machines

Efficiency of machine is

  1. Ratio of velocity of effort to velocity of load

  2. Ratio of the load to its effort

  3. Ratio of useful work done by the machine to the work put to the machine by its effort

  4. All

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Mechanical advantage (MA) is the ratio of the load to its effort.
efficiency of machine (n) = MA/VR
Velocity Ratio (VR) is the ratio of the velocity of effort to velocity of load.

Multiple choice physics simple machine common machines terms related to machines introduction to simple machines

Relationship between the mechanical advantage and velocity ratio of an ideal machine is

  1. Velocity Ratio < mechanical advantage

  2. Velocity Ratio = Mechanical advantage

  3. Velocity ratio > Mechanical advantage

  4. All

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

For ideal machine, efficiency = 1

effeciency = Mechanical advantage/ velocity ratio
So, for ideal machine, Mechanical advantage = velocity ratio

Multiple choice physics simple machine common machines terms related to machines introduction to simple machines

It is difficult to climb the steps having greater inclination. Why?

  1. Less erect steps require less energy

  2. Greater inclination requires less effort because of the high mechanical advantage

  3. Greater inclination requires more effort because of the low mechanical advantage

  4. None of the above

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

A steeper incline (greater inclination) effectively acts as a shorter inclined plane for a given horizontal distance, which reduces the mechanical advantage. Consequently, more effort is required to climb it.

Multiple choice physics simple machine common machines terms related to machines introduction to simple machines

A pulley system of VR of 2 and efficiency of 50%. If the effort moves through a distance of 5m. Calculate the distance moved by the load.

  1. 2m

  2. 5.6m

  3. 10m

  4. 2.5m

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Given:  $VR=2$


From the relation $VR=\dfrac{\text{Distance moved by effort}}{\text{distance moved by load}}$


Using formula we get distance moved by the load is $2.5m$