Tag: banking and taxation

Questions Related to banking and taxation

Examine whether the point (2, 5) lies on the graph of the equation $3x\, -\, y\, =\, 1$.
State true or false.

maths banking and taxation reading graphs describing different situations using equations to plot lines basics of a straight line

  1. True

  2. False

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Correct Option: A
Explanation:

Put x = 2 and y = 5 in the equation,
3x - y = 1
6 - 5 = 1
1 = 1
Hence, the point lies on the equation.


$y=2x+3$
Which of the following statements is true about the given line?

maths banking and taxation reading graphs describing different situations using equations to plot lines basics of a straight line

  1. The line passes through $(0,3)$ and $m=-2$

  2. The line passes through $(3,0)$ and $m=-2$

  3. The line passes through $(0,3)$ and $m=2$

  4. The line passes through $(3,0)$ and $m=2$

Show answer
Correct Option: C
Explanation:

Comparing the given equation $y=2x+3$ with $y = mx+c$, we get

Hence, $m=2$ and $c=3$.
So, options A and B are incorrect.

Option C:
Substitute $(0,3)$ in the given equation, we get
RHS: $=2(0)+3 = 3$
LHS: $y=3$
$LHS =  RHS$, Hence option C is correct.

Option D:
Substitute $(3,0)$ in the given equation, we get
RHS: $=2(3)+3 = 9$
LHS: $y=0$

$LHS \neq RHS$. Hence, option D is incorrect.

Consider the equation of the line :$\displaystyle \frac{x-1}{3}-\frac{y+2}{2}=0$

maths banking and taxation reading graphs describing different situations using equations to plot lines basics of a straight line

  1. The line passes through $(4,0)$  and $m=2/3$

  2. The line passes through $(4,0)$  and $m=-2/3$

  3. The line passes through $(4,0)$  and $m=3/2$

  4. The line passes through $(4,0)$  and $m=-3/2$

Show answer
Correct Option: A
Explanation:
Given line 
$\dfrac{x-1}{3}-\dfrac{y+2}{2}=0$

$\dfrac{x-1}{3}=\dfrac{y+2}{2}$

$2(x-1)=3(y+2)$

$2x-2=3y+6$

$y=\dfrac{2x}{3}-\dfrac{8}{3}$

on comparing above eq with $y=mx+c$

$slope(m)=\dfrac{2}{3}$

y-intercept$=-\dfrac{8}{3}$

when $y=0,x=4$

Hence it passes through $(4,0)$ with $m=\dfrac{2}{3}$

Consider the line: y= -x +4

Which of the following is correct.

maths banking and taxation reading graphs describing different situations using equations to plot lines basics of a straight line

  1. The line passes through (0,4) and m=1.

  2. The line passes through (0,4) and m=-1.

  3. The line passes through (0,0) and m=-1.

  4. The line passes through (4,0) and m=-1.

Show answer
Correct Option: B
Explanation:
Given line 
$y=-x+4$
on comparing above eq with $y=mx+c$
$slope(m)=-1$
y-intercept$=4$
Hence it passes through (0,4) with $m=-1$

Draw the graph for each linear equation:
$\displaystyle y=\frac{3}{2}x+\frac{2}{3}$

maths banking and taxation reading graphs describing different situations using equations to plot lines basics of a straight line

  1. The line passes through $(4/9,0)$ and $m=-\dfrac32$

  2. The line passes through $(-0.4/9,0)$ and $m=\dfrac32$

  3. The line passes through $(-4/9,0)$ and $m=\dfrac32$

  4. The line passes through $(-0.9/4,0)$ and $m=-\dfrac32$

Show answer
Correct Option: C
Explanation:

The given line equation is $\frac{3}{2}x-y+\frac{2}{3}$

The slope of given line is $-(\frac { \frac { 3 }{ 2 }  }{ -1 } )=\frac { 3 }{ 2 } $
If we put $y=0$ , then the value of $x= -\frac{4}{9}$
Therefore line passes through $(-\frac{4}{9},0)$ and slope is $\frac{3}{2}$
So the correct option is $C$

Consider the equation of the line $\displaystyle x-3=\frac{2}{5}\left ( y-1 \right )$. Which of the following is correct?

maths banking and taxation reading graphs describing different situations using equations to plot lines basics of a straight line

  1. The line passes through $(6,5)$  and $m=-2/5$.

  2. The line passes through $(5,6)$  and $m=-5/2$.

  3. The line passes through $(6,5)$  and $m=2/5$.

  4. The line passes through $(5,6)$  and $m=5/2$.

Show answer
Correct Option: D
Explanation:
Given line 
$x-3=\dfrac{2}{5}(y-1)$
$5(x-3)=2(y-1)$
$5x-15=2y-2$
$2y=5x-13$
$y=\dfrac{5x}{2}-\dfrac{13}{2}$
on comparing above eq with $y=mx+c$
$slope(m)=\dfrac{5}{2}$

when $x=5$
$2y=25-13$
$2y=12$
$y=6$
Hence it passes through (5,6) with $m=\dfrac{5}{2}$

For the pair of linear equations given below, draw graph and then state, whether the lines drawn are,
$\displaystyle y=3x-1$
$\displaystyle \frac{x}{2}+\frac{y}{3}=1$

maths banking and taxation reading graphs describing different situations using equations to plot lines basics of a straight line

  1. Perpendicular

  2. Parallel

  3. Intersecting but not at right angles

  4. Options B & C

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Correct Option: C

For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are 
$\displaystyle 3x+4y=24$
$\displaystyle \frac{x}{4}+\frac{y}{3}=1$

maths banking and taxation reading graphs describing different situations using equations to plot lines basics of a straight line

  1. intersecting but not at right anglesl

  2. Options B & D

  3. perpendicular

  4. parallel

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Correct Option: D

The straight lines given by the equations $\displaystyle x+y=2 , x-2y=5 \ and \ \frac{x}{3}+y=0$ are?

maths banking and taxation reading graphs describing different situations using equations to plot lines basics of a straight line

  1. concurrent

  2. intersecting to make a right triangle.

  3. intersecting to make an isosceles triangle.

  4. parallel to each other.

Show answer
Correct Option: A
Explanation:
Given lines
$x+y=2$------(1)
$x-2y=5$----(2) and $\dfrac{x}{3}+y=0$----(3)
Solving eq (1) and (2)
$x-2(2-x)=5$
$x-4+2x=5$
$x=3$ and $y=2-3=-1$
Point of intersection of line (1) and (2) is $P(3,-1)$
Solving eq (2) and (3)
$-3y-2y=5$
$-5y=5$
$y=-1$ and $x=-3y=3$
Point of intersection of line (2) and (3) is $Q(3,-1)$
Solving eq (1) and (3)
$-3y+y=2$
$-2y=2$
$y=-1$ and $x=-3y=3$
Point of intersection of line (1) and (3) is $R(3,-1)$
Here point of intersection of all line is same Hence line is concurrent

If the line ax + by + c = 0 is such that  a = 0 and b, $\displaystyle c\neq 0$ then the line is perpendicular to 

maths banking and taxation reading graphs describing different situations using equations to plot lines basics of a straight line

  1. x-axis

  2. y-axis

  3. x + y =1

  4. x = y

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Correct Option: B
Explanation:

When $ a= 0 $ then the line equation becomes $ by + c = 0 $ or $ y = -\frac {c}{b} $

Equations of the form $ y =k $ are parallel to x-axis. This also means that they are perpendicular to $ y - $ axis as $ x-$ axis and $ y- $axis are perpendicular to each other.