Tag: banking and taxation

Questions Related to banking and taxation

The graph of $\dfrac {7x}{2}=18+\dfrac {4}{5}x-45$ is line____

  1. Parallel to $x-$axis at a distance of $10$ units from the origin

  2. Parallel to $y-$axis at a distance of $10$ units from the origin

  3. Parallel to $x-$axis at a distance of $20$ units from the origin

  4. Parallel to $y-$axis at a distance of $20$ units from the origin

  5. None of these


Correct Option: B
Explanation:

$\cfrac { 7x }{ 2 } =18+\cfrac { 4 }{ 5 } x-45\ \Rightarrow \cfrac { 7x }{ 2 } -\cfrac { 4x }{ 5 } =-27\ \Rightarrow \cfrac { 35x-8x }{ 10 } =-27\ \cfrac { 27x }{ 10 } =-27\ \Rightarrow x=-10$

Therefore graph is a straight line parallel to y-axis at a distance of $10$ units from the origin.

Find $c$ if the line $cx+5y-3=0$ passes through $(2,1)$

  1. -1

  2. -2

  3. 3

  4. 4


Correct Option: A
Explanation:

Point is $(2,1)$

Equation is $cx+5y-3=0\c(2)+5(1)-3=0\2c+2=0\c=-1$

The graph of the equation y = mx is line which always passes through

  1. (0, m)

  2. (x, 0)

  3. (0, x)

  4. (0, 0)


Correct Option: D
Explanation:

The graph is shown in image 

$y=mx$
Given lines always passes through $(0,0)$ for any value of $m$ 
Because $(0,0)$ always satisfied the equation $y=mx$

Equation y = 2x + 5 has

  1. unique solution

  2. no solution

  3. only two solutions

  4. infinitely many solution


Correct Option: D
Explanation:

$ y=2x+5$ is an equation of line which satisfied many value of $x$ and $y$ 


Hence this equation has infinitely many solutions 

The equation  of a line is given by $3x - 2y = 9$ has how many possible solution?

  1. One solution

  2. No solution

  3. Two solution

  4. Infinitely many solution


Correct Option: D

Which of the following is TRUE regarding the graphs of the equations of a linear quadratic system?

  1. the graphs may intersect in two locations

  2. the graphs may intersect in one location

  3. the graphs may not intersect

  4. all three choices are true

  5. none of these


Correct Option: D
Explanation:

Option D is correct.

The number of triangles that the four lines $y=x+3$, $y=2x+3$, $y=3x+2$, and $y+x=3$ form is?

  1. $4$

  2. $2$

  3. $3$

  4. $1$


Correct Option: A
Explanation:

The given lines are $y=x+3, y=2x+3, y=3x+2$ Vand $y+x=3$ and $y+x=3$

Slopes of these lines are different from each other 
So, combinations of $3$ lines form a triangle 
$\therefore$ Number of triangles formed $=\, ^4C _3$
                                                   $=4$

If sum of distance of a point from two perpendicular lines in a plane is $1$, then its locus is ?

  1. Square

  2. Circle

  3. A straight line

  4. An intersecting line


Correct Option: A
Explanation:

Let x axis & y axis are the perpendicular lines. The sum of the distances from point $p(x, y)$ is $1$ 

i.e.,$|x| + |y| = 1$

The locus of the point 'p' which is the rhombus whose sides are $x + y = 1 ; -x + y = 1 ; x - y = 1 ; -x - y = 1$

$\bot r$ lines other than coordinate axis gives same result so locus is a square. 

The nearest point on the line $3x-4y=25$ from the origin is

  1. $(-4,5)$

  2. $(3,-4)$

  3. $(3,4)$

  4. $(3,5)$


Correct Option: B
Explanation:

Distance of the line $3x-4y-25=0$ from the origin is 
$\displaystyle d=\frac{|-25|}{\sqrt{25}}$
$\Rightarrow d=5$
Only the point given in option B lies on the given line .
Also, its distance from origin is 5.
So, (3,-4) is the nearest point on the line from the origin.

Consider the lines $2x+3y=0$,    $5x+4y=7$. Find the intersection point.

  1. $(3,-2)$

  2. $(3,2)$

  3. $(-3,2)$

  4. $(2,3)$


Correct Option: A
Explanation:

The lines are $2x+3y=0$......(1)


$x=\dfrac{-3y}{2}$

$5x+4y=7$........(2)

$5\left(\dfrac{-3y}{2}\right)+4y=7$

$-15y+8y=14$

$-7y=14$

$y=-2$

$x=\dfrac{-3(-2)}{2}=3$

$(x,y)=(3,-2)$