Tag: kinetic theory of gases

Questions Related to kinetic theory of gases

Multiple choice modelling gases - the kinetic model ideal gases kinetic theory of gases physics

The gas, which is present the most in air, is___

  1. oxygen

  2. nitrogen

  3. carbon dioxide

  4. water vapour

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

1) Nitrogen $-78$%

2) Oxygen $-21$%
3) Inert Nobel gases $-0.9$%
4) Several trace gases $-0.1$%
The above list the different number of gases in descending order. As per the list clearly Nitrogen is the gas present in most air.

Multiple choice modelling gases - the kinetic model ideal gases kinetic theory of gases physics

Heat is associated with 

  1. kinetic energy of random motion of molecules

  2. kinetic energy of orderly motion of molecules

  3. total kinetic energy of random and orderly motion of molecules

  4. kinetic energy of random motion in some cases and kinetic energy orderly motion in other.

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Heating up a substance excites the molecules of that substance making  the molecules moves vigorously thus giving velocity to the molecules and we know kinetic energy of a body is by the virtue of its motion.       

Multiple choice modelling gases - the kinetic model ideal gases kinetic theory of gases physics

The kinetic energy of translation of $20gm$ of oxygen at $47^oC$ is (molecule wt. of oxygen is $32gm/mol $and $R=8.3J/mol/K$)

  1. 2490 joules

  2. 2490 ergs

  3. 830 joules

  4. 124.5 joules

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Kinetic energy K = (3/2)nRT. For 20g of oxygen (molar mass 32g/mol), n = 20/32 = 0.625 mol. T = 47 + 273 = 320 K. K = (3/2) * 0.625 * 8.3 * 320 = 2490 J.

Multiple choice modelling gases - the kinetic model ideal gases kinetic theory of gases physics

Statement 1: The internal energy of a perfect gas is entirely kinetic and depends only on absolute temperature of the gas and not on its pressure or volume.
Statement 2: A perfect gas is heated keeping pressure constant and later at constant volume. For the same amount of heat the temperature of the gas at constant pressure is lower than that at constant volume.

  1. Statement 1 is true, statement 2 is true and statement 2 is correct explanation of statement 1

  2. statement 1 is true, statement 2 is false

  3. Statement 1 is true, Statement 2 is true but Statement 2 is not the correct explanation of Statement 1

  4. Statement 1 is false, Statement 2 is true

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Statement 1 is true as internal energy of an ideal gas depends only on temperature. Statement 2 is true because at constant pressure, some heat is used for work (expansion), leaving less for temperature rise compared to constant volume. However, Statement 2 does not explain Statement 1.

Multiple choice modelling gases - the kinetic model ideal gases kinetic theory of gases physics

The average pressure of an ideal gas is  

  1. $\rho = (1/3)\, mn \, V^2 _{av}$

  2. $\rho = (1/2)\, mn \, V _{av}$

  3. $\rho = (1/4)\, mn \, V^2 _{av}$

  4. $\rho = (1/3)\, mn \, V _{av}$

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

From the kinetic theory of gases, the pressure exerted by an ideal gas is given by P = (1/3) * rho * v_rms^2, where rho is density (m*n) and v_rms^2 is the mean square speed (V^2_av).

Multiple choice modelling gases - the kinetic model ideal gases kinetic theory of gases physics

The pressure of air increases by $100mm$ of Hg and the temperature decreases by $1^0C$. The change in the speed of sound in air at STP is

  1. $61ms^{-1}$

  2. $61mms^{-1}$

  3. $61 cms^{-1}$

  4. $0.61 cms^{-1}$

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Speed of sound v = sqrt(gamma * P / rho). Since P/rho is constant for an ideal gas at constant temperature, speed is independent of pressure. The change in speed depends only on temperature change: dv/dT = v / (2T). For air at 273K, v = 332 m/s. dv = (332 / (2 * 273)) * (-1) = -0.61 m/s = -61 cm/s. The magnitude is 61 cm/s.

Multiple choice modelling gases - the kinetic model ideal gases kinetic theory of gases physics

The equation of state of some gases can be expressed as (p+av2)(v−b)=RT Here p is pressure, v is volume , a,b,R are constants. The dimensions of ′a′ are

  1. $ML^{-5}T^{-2}$

  2. $ML^{-1} T^{-2}$

  3. $M^o L^3T^o$

  4. $M^B L^oT^o$

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Here $P$ and $a/{ V }^{ 2 }$ are added that means they have same dimensions.

Therefore,
$\left[ { M }^{ 1 }{ L }^{ -1 }{ T }^{ -2 } \right] =\dfrac { a }{ \left[ { M }^{ 0 }{ L }^{ 6 }{ T }^{ 0 } \right]  } $
$a=\dfrac { { M }^{ 1 }{ L }^{ -1 }{ T }^{ -2 } }{ { M }^{ 0 }{ L }^{ 6 }{ T }^{ 0 } } $
$a={ M }^{ 1 }{ L }^{ 5 }{ T }^{ -2 }$

Multiple choice modelling gases - the kinetic model ideal gases kinetic theory of gases physics

According to kinetic theory of gases,

  1. The velocity of molecules decreases for each collision

  2. The pressure exerted by a diatomic gas is proportional to teh mean velocity of the molecule

  3. The K.E of the gas decreases on expansion at constant temperature

  4. The mean translational KE of a diatomic gas increases with increase in absolute temperature

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Options:
(A): One can not say velocity of molecule decreases  in each collision.
(B): The pressure exerted by a diatomic gas is proportional to rms speed, not mean speed.
(C): Since temp is constant, KE will be constant.
(D): Mean translational KE is proportional to temp, hence will increase with increase in absolute temp.