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Multiple choice chemistry water too little to waste pollution of water water pollution planet earth

Biochemical Oxygen Demand (BOD) is a measure of organic material present in water. BOD value less than 5 ppm indicates a water to be ________.

  1. rich in dissolved oxygen

  2. poor in dissolved oxygen

  3. highly polluted

  4. not suitable for aquatic life

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Clean water has BOD which is less than 5 ppm. If it is equal to or more than 12 ppm, then the water is considered as polluted. So this indicates water be rich in dissolved oxygen, that helps the microorganisms to oxidize inorganic and organic materials. 

Multiple choice chemistry water too little to waste pollution of water water pollution planet earth

Pollution of lakes and rivers affects aquatic life. Fish cannot live in water that has oxygen less than $4$ milligrams per liter. Other freshwater aquatic life (including anaerobic bacteria) also cannot survive without adequate oxygen. 'BOD' stands for:

  1. Biological oxygen demand

  2. Bacterial oxygen deficit

  3. Basic oxygen demand

  4. Building oxygen deposits

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
BOD stands for Biological Oxygen Demand is the amount of dissolved oxygen needed by aerobic biological organisms to break down organic material present in a given water sample at a certain temperature over a specific time period.
Multiple choice chemistry water too little to waste pollution of water water pollution planet earth

Clean water would have Biochemical oxygen demand (BOD) value of less than:

  1. 17 ppm

  2. 5 ppm

  3. 200,000 ppm

  4. 10 ppm

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation
A water supply with a BOD level of 3-5 ppm is considered moderately clean. In water with a BOD level of 6-9 ppm, the water is considered somewhat polluted because there is usually organic matter present and bacteria are decomposing this waste.
Hence, clean water would have a BOD value of less than 5.

Hence, the correct option is $\text{B}$
Multiple choice chemistry water too little to waste pollution of water water pollution planet earth

Biological Oxygen Demand (BOD) can be defined as:

  1. the amount of oxygen required by bacteria to break down the organic matter of a sample of water

  2. the amount of chemicals required to break down the organic matter of a sample of water

  3. the amount of phosphate required to oxidise the organic matter of a sample of water

  4. the amount of organic matter present in the given sample of water

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

BOD refers to the dissolved oxygen that the microorganisms like bacteria need to oxidize, means to break down inorganic and organic matter in water. It is a measure of water quality. 

Multiple choice chemistry water too little to waste pollution of water water pollution planet earth

What does $BO{D} _{5}$ represent?

  1. Biological oxygen demand in five days

  2. Dissolved oxygem left after five days

  3. Dissolved oxygen consumed in five days

  4. Microorganisms killed by ozone in sewage treatment plants in five hours

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

$BO{ D } _{ 5 }$ stands for 5-day Biochemical Oxygen Demand. The BOD test measures, oxygen is used as microbes breathe as they eat the contaminants  in wastewater.

Multiple choice chemistry water too little to waste pollution of water water pollution planet earth

10 mL of water required 1.47 mg of $K _{2}Cr _{2}O _{7}$ (M. wt. = 294) for oxidation of dissolved organic matter in presence of acid. Then the C.O.D of water sample is:

  1. 2.44 ppm

  2. 24 ppm

  3. 32 ppm

  4. 1.6 ppm

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

$ Number \  of   \ milliequivalent $ = $\dfrac{weight \ in \ mg}{Equivalent\  weight}$


= $\dfrac{1.47}{294/6}$ = $0.03meq$

$\therefore$COD of sample is:

$\dfrac{0.03}{10}\times 1000$ =  $3meq/L$

In terms of Oxygen COD is :

$3 meq/L \times  (8 mg O _2/meq)$ = $24 mg/L= 24ppm$

Option B is correct.