Tag: optics

Questions Related to optics

A points object at 15 cm from a concave mirror of radius of curvature 20 cm is made to oscillate along the pressure axis with amplitude 2 mm. The amplitude of its image will be 

  1. 2 mm

  2. 4 mm

  3. 8 mm

  4. 16 mm


Correct Option: D

The diameter of the sun is $1.4 \times 10 ^ { 9 } \mathrm { m }$ and its distance from the earth is $1.5 \times 10 ^ { 11 } \mathrm { m } .$ The radius of the image of the sun formed by a lens of focal length $20 \mathrm { cm }$ is

  1. $93 mm$

  2. $0.093mm$

  3. $9.3 mm$

  4. $0.93 mm$


Correct Option: D

An object of length 2.0 cm is placed perpendicular to the principal axis of a convex lens of focal length 12 cm. Find the size of the image if the object is at a distance of 8.0 cm from the lens.

  1. $6 cm$

  2. $4 cm$

  3. $5 cm$

  4. $1 cm$


Correct Option: A

A man wearing glasses of focal length  $+ 1 \mathrm { m }$  cannot clearly see beyond  $1\mathrm { m }$

  1. if he is farsighted

  2. if he is nearsighted

  3. if his vision is normal

  4. in each of these case


Correct Option: D
Explanation:
That is the person is near-sighted.
And the condition is known as myopia.
Ans. (b)

A thin lens produces an image of the same size as the object. Then from the optical centre of the lens, the distance of the object is

  1. zero

  2. $4f$

  3. $2f$

  4. $f/2$


Correct Option: C

Optical axis of a thin equi-convex lens  is the X-axis. The co-ordinate of a point object and its image are (-20 cm, 1 cm) and (25 cm, -2 cm) respectively:-

  1. The lens is located at X = 5 cm

  2. The lens is located at X = -5 cm

  3. The focal length of the lens is 10 cm

  4. The focal length of the lens is 15 cm


Correct Option: B,C

A point object $O$ is placed on the principle axis of a convex lens of focal length $20\ cm$ at a distance of $40\ cm$ to the left of it. The diameter of the lens is $10\ cm$. If the eye is placed $60\ cm$ to the right of the lens at a distance $h$ below the principle axis, then the maximum value of $h$ to see the image will be

  1. $2.5\ cm$

  2. $5\ cm$

  3. $0\ cm$

  4. $10\ cm$


Correct Option: A

For two position of lens, the images are obtained on a fixed screen. If the size of the object is 2 cm and size of diminished image is 0.5 cm, the size of the other image will be

  1. 1 cm

  2. 4 cm

  3. 8 cm

  4. 16 cm


Correct Option: C
Explanation:

$height^{2} _{object}=height _{image1}\times height _{image2}$


$2 \times 2=0.5 \times h$

$h=8$

option $C$ is correct

A lens is placed between the source of light and a wall. It forms images of area $ { A } _{ 1 }$ and  ${ A } _{ 2 }$ on the wall for its two different positions. The area of the source of light is :

  1. $ \sqrt { { A } _{ 1 }{ A } _{ 2 } } $

  2. $ \dfrac { { A } _{ 1 }+{ A } _{ 2 } }{ 2 } $

  3. $ { \left( \dfrac { \sqrt { { A } _{ 1 } } +\sqrt { { A } _{ 2 } } }{ 2 } \right) }^{ 2 } $

  4. $None\ of\ these$


Correct Option: A
Explanation:

$height^{2} _{object}=height _{image1} \times height _{image2}$


$r^{2} _{source}=r _{image1} \times r _{image2}$

$\pi r^{2} _{source}=\pi r _{image1} \times r _{image2}$

$A _{source}=\sqrt{\pi^{2} r^{2} _{image1}r^{2} _{image2}}$

$A _{source}=\sqrt{A _{1}A _{2}}$

option $A$ is correct 

A student focused the image of a candle flame on a white screen using a convex lens. He noted down the position of the candle, screen and the lens as under position of candle $=12.0\ cm$position of convex lens $=50.0\ cm$position of the screen $=88.0\ cm$. Where will the image be formed, if he shifts the candle towards the lens at a position of $31.0\ cm$?

  1. 19cm

  2. 48cm

  3. Infinity

  4. at center of curvature


Correct Option: C