Tag: waves

Questions Related to waves

The light waves from two independent monochromatic light sources are given by-
${y _1} = 2\sin  {\omega t }$ and ${y _2} = 2\cos  {\omega t }$,
then the following statement is correct 

  1. Both the waves are coherent

  2. Both the waves are incoherent

  3. Both the waves have different time periods

  4. None of the above


Correct Option: B
Explanation:

${y _1} = 2\sin \left( {\omega t - kx} \right)$
${y _2} = 2\cos \left( {\omega t - kx} \right) = 2\sin \left( {\omega t - kx + \frac{\pi }{2}} \right)$
So, Phase difference = $\frac{\pi}{2}$
Hence sources are incoherent.

The phase difference between two points is $\pi/3$. If the frequency of wave is 50 Hz, then what is the distance between two points? (given v = 330 m/s)

  1. 2.2 m

  2. 1.1 m

  3. 0.6 m

  4. 1.7 m


Correct Option: B
Explanation:

Phase difference $= \dfrac{2\pi}{\lambda}\times$path difference. 
The phase difference between any two particles in a wave determines lack of harmony in the vibrating state of two particles ie, how far one particle leads the other or lags behind the other. 
From relation 
$\Delta \phi =\dfrac{2\pi}{\lambda}\times \delta x$


$\Rightarrow \Delta x = \dfrac{\lambda}{2\pi}\times \Delta \phi$    ...(i)

Also, $\lambda = \dfrac{v}{n}$      ...(ii)
Now, from Eqs. (i) and (ii), we get
$\Delta x=\dfrac{v}{2\pi n}\times \Delta \phi$

$\Rightarrow \Delta x=\dfrac{330}{2\pi\times 50}\times \dfrac{pi}{3}$
or $\Delta x = 1.1m$ 

When a transverse wave on a string is reflected from the free end, the phase change produced is ___________.

  1. Zero rad

  2. $\dfrac { \pi }{ 2 } $ rad

  3. $\dfrac { 3\pi }{ 4 } $ rad

  4. $\pi$ rad


Correct Option: A
Explanation:

For a transverse wave, a phase change of $\pi$ occurs when it is reflected from a denser medium.

When reflected from a free end, however, there is no change of phase.
Hence the correct answer is option A.

When a transverse plane wave traverses a medium, individual particles execute periodic motion given by the equation  $y=0.25\cos(2\pi t-\pi x)$. The phase difference for two positions of same particle which are occupied by time intervals $0.4 second$ apart is

  1. $144^{o}$

  2. $135^{o}$

  3. $72^{o}$

  4. $108^{o}$


Correct Option: A
Explanation:

$\omega =\dfrac{2\pi}{T}$
$T=\dfrac{2\pi}{\omega}$
$T=1sec$
$\therefore 2\pi \ rad \ in \   1 sec$
$in \ 0.4 sec \  2\pi\times 0.9$
$=144^o$

The phase difference between the particle at one compression and another particle in third compression is

  1. $\pi $ radians

  2. $2\pi $ radians

  3. $3\pi $ radians

  4. $4\pi $ radians


Correct Option: D
Explanation:

phase difference between two successive compression is $2\pi $
$\therefore $ phase difference between a particle at one compression and in third compression is $2(2\pi)= 4\pi $

Reflection of a light wave at a fixed point results in a phase difference between incident and reflected wave of

  1. $\dfrac {3\pi}{2}$

  2. $2\pi $

  3. $\pi$ 

  4. $\dfrac {\pi}{2}$


Correct Option: B,D
Explanation:

Reflections of light at the interface between media often produce phase differences. The phase difference between incident and reflected wave is $2\pi$ and $\pi / 2$ radians.

Phase difference between a particle at a compression and a particle at the next rarefaction is

  1. Zero

  2. $\dfrac{\pi}{2}$

  3. $\pi$

  4. $\dfrac{\pi}{4}$


Correct Option: C
Explanation:

Phase difference between two successive compression of rarefaction is $2\pi $
As  rarefaction appears between two compression, phase difference is $\pi $.

Which of the following is wrong about infrared rays?

  1. Infrared rays have wavelength higher than that of microwaves

  2. Infrared rays have wavelength lower than that of visible light

  3. Wavelength of these rays is of the order of $10^{-4}$ m

  4. The sources of infrared rays are always natural


Correct Option: C

The phase difference between two waves represented by 
${y _1} = {10^{ - 6}}\sin \left[ {100t + \frac{x}{{50}} + 0.5} \right]m$
${y _2} = {10^{ - 6}}\cos \left[ {100t + \frac{x}{{50}}} \right]m$
where x is expressed in metres and t is expressed in seconds is approximately

  1. 1.07 rad

  2. 2.07 rad

  3. 0.5 rad

  4. 1.5 rad


Correct Option: A
Explanation:
$y _{1}=10^{-6} \sin \left[100 t + \dfrac{x}{50}+ 0.5\right] m$
$y _{2}=10^{-6} \cos \left[100 t + \dfrac{x}{50}\right] m$
So,$y^{1}=10^{-6} \cos\left[\dfrac{\pi}{2}-\left(100 t + \dfrac{x}{50}+0.5\right)\right]$
$y^{1}=10^{-6} \cos \left[\dfrac{-\pi}{2}+100 t+\dfrac{x}{50}+0.5\right]$
$\triangle \phi =\phi _{2}-\phi _{1}$
$\phi _{2}=0$ where as $\phi _{1}=0.5-\dfrac{\pi}{2}$
So,
$\triangle \phi=\phi _{2}-\phi _{1}=\dfrac{\pi}{2}-0.5=1.07 \ rad$
option $-A$ is correct.

































Two waves of the same amplitude and frequency arrive at a point simultaneously. what should the phase difference between the waves so that amplitude of the resultant wave is double(2A) 

  1. $\dfrac {\pi}{2} radian$

  2. $\dfrac {2\pi}{3} radian$

  3. $\dfrac {3\pi}{4} radian$

  4. zero


Correct Option: D