Tag: measurements and experimentation

Questions Related to measurements and experimentation

Which one of the following is not a unit of British system of units?

standardized measurement measurement of physical quantities need of unit for measurement measurements and experimentation physics

  1. Foot

  2. Metre

  3. Pound

  4. Second

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Correct Option: B
Explanation:

Among the given units metre is not a unit of British system whereas all other units belong to this system.

The dimensions of the quantities in one (or more) of the following pairs are the same. Identify the pair(s).

standardized measurement measurement of physical quantities need of unit for measurement measurements and experimentation physics

  1. Torque and work

  2. Angular momentum and work

  3. Energy and Young's modulus

  4. Light year and wavelength

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Correct Option: A,D
Explanation:

Torque$={ M }^{ 1 }{ L }^{ 2 }{ T }^{ -2 }$

Work$={ M }^{ 1 }{ L }^{ 2 }{ T }^{ -2 }$
angular momentum(L)=${ M }^{ 1 }{ L }^{ 2 }{ T }^{ -1 }$
Energy$={ M }^{ 1 }{ L }^{ 2 }{ T }^{ -2 }$
Young's Modulus $(Y)$$={ M }^{ 1 }{ L }^{ 2 }{ T }^{ -2 }$
Light year$=L$
Wavelength$=L$

1 Me V$=$

standardized measurement measurement of physical quantities need of unit for measurement measurements and experimentation physics

  1. $1.6\times 10^{-12} Joules$

  2. $1.6\times 10^{-10} Joules$

  3. $1.6\times 10^{-13} Joules$

  4. $1.6\times 10^{-11} Joules$

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Correct Option: A

As compared to cumulative average-time learning model, learning model which predicts more cumulative total time to produce more units is known as ____________.

standardized measurement measurement of physical quantities need of unit for measurement measurements and experimentation physics

  1. incremental unit time learning model

  2. incremental price learning model

  3. incremental unit average model

  4. incremental cost learning model

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Correct Option: A

The unit of universal gas constant is

standardized measurement measurement of physical quantities need of unit for measurement measurements and experimentation physics

  1. ${Dymes}/{C}$

  2. $Ergs$ ${cm}/{mole} K$

  3. ${Watt}/{K}$

  4. ${Joule}/{mole} K$

Show answer
Correct Option: D
Explanation:

Gas equation,
$PV=nRT$

$R=\dfrac{PV}{nT}$

$[R]=\left[ \dfrac{PV}{nT}\right]$

$[R]=\dfrac{Joule}{mole \ K}$

Option D

The SI unit of amplitude of oscillation is

standardized measurement measurement of physical quantities need of unit for measurement measurements and experimentation physics

  1. cm

  2. m

  3. km

  4. none of these

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Correct Option: B
Explanation:

SI unit of amplitude of oscillation is metre  $(m)$

The wavelength of light is expressed in

standardized measurement measurement of physical quantities need of unit for measurement measurements and experimentation physics

  1. Metre

  2. Micron

  3. Light year

  4. Angstrom

Show answer
Correct Option: D
Explanation:

Angstrom $(\dot A)$ unit of length used chiefly in measuring wavelengths of light, equal to $10^{-10}$ metre, or $0.1$ nanometer.  It is used to express wavelengths of visible light, ultraviolet (UV) light, X rays, and gamma rays.

State whether given statement is True or False.
The SI unit of mass is milligram.

standardized measurement measurement of physical quantities need of unit for measurement measurements and experimentation physics

  1. True

  2. False

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Correct Option: B
Explanation:

SI unit of mass is kilogram i.e.  $Kg$.
Thus the above statement is false.

If the displacement, velocity and acceleration of a particle at time t be x, v and f respectively, then which one is true?

standardized measurement measurement of physical quantities need of unit for measurement measurements and experimentation physics

  1. $f=v^3\dfrac{d^2t}{dx^2}$

  2. $f=-v^3\dfrac{d^2t}{dx^2}$

  3. $f=v^2\dfrac{d^2t}{dx^2}$

  4. $f=-v^2\dfrac{d^2t}{dx^2}$

Show answer
Correct Option: B
Explanation:

We know that the velocity can be written as:
$v=\dfrac{dx}{dt}$

Therefore, $\dfrac1v=\dfrac{dt}{dx}$

Now, expressing $f$ in terms of velocity.

$\dfrac{d^2t}{dx^2}=\dfrac{d\begin{pmatrix}\dfrac{dt}{dx}\end{pmatrix}}{dx}=\dfrac{d\begin{pmatrix}\frac{1}{v}\end{pmatrix}}{dx}=-\dfrac{1}{v^2}\dfrac{dv}{dt}\times\dfrac{1}{v}$
$\Rightarrow\;f=-v^3\dfrac{d^2t}{dx^2}$


A __________ unit does not change with respect to space and time.

standardized measurement measurement of physical quantities need of unit for measurement measurements and experimentation physics

  1. derived

  2. standard

  3. regular

  4. large

Show answer
Correct Option: B
Explanation:

A unit is said to be a standard unit of does not change with respect to space and time.