Temporary hardness can be removed by:
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boiling
-
clark's process
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calgon's process
-
permutit method
Reveal answer
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A,B
Correct answer
Explanation
By boiling : - On boiling, soluble $Mg{ \left( HC{ O } _{ 3 } \right) } _{ 2 }$ is converted to insoluble $Mg{ \left( OH \right) } _{ 2 }$ and $Ca{ \left( H{ CO } _{ 3 } \right) } _{ 2 }$ to insoluble ${ CaCO } _{ 3 }$. It is because high solubility of $Mg{ \left( OH \right) } _{ 2 }$ as compared to $Mg{ CO } _{ 3 }$, than $Mg{ \left( OH \right) } _{ 2 }$ is precipitated. Precipitates can be removed by filtration.
By Clark's Method : Calculated amount of lime is added to hard water $\rightarrow Ca{ CO } _{ 3 }$ precipitates out & $Mg{ \left( OH \right) } _{ 2 }$ can be filtered off.