Tag: angle and its measurement

Questions Related to angle and its measurement

In a $\Delta$PQR, if $\angle P - \angle Q = 42^{\circ}$ and $\angle Q - \angle R = 21^{\circ}$, find $\angle P, \angle Q$ and $\angle R$.

  1. $\angle P = 105^{\circ} \angle Q = 53^{\circ} \angle R = 32^{\circ}$

  2. $\angle P = 25^{\circ} \angle Q = 53^{\circ} \angle R = 32^{\circ}$

  3. $\angle P = 95^{\circ} \angle Q = 53^{\circ} \angle R = 32^{\circ}$

  4. $\angle P = 75^{\circ} \angle Q = 53^{\circ} \angle R = 32^{\circ}$


Correct Option: C
Explanation:

Given,
$\angle P - \angle Q = 42$ (I)
$\angle Q - \angle R = 21$ (II)
Sum of angles = 180
$\angle P + \angle Q + \angle R = 180$ (III)
Add all the three equations:
$2 \angle P + \angle Q = 180 + 42 + 21$
$2 \angle P + \angle Q = 243$ (IV)

Add I and IV,
$2 \angle P + \angle P = 243 + 42$
$3 \angle P = 285$
$\angle P = 95^{\circ}$
From IV, $\angle Q = 243 - 2\times 95$
$\angle Q = 53^{\circ}$
From II,
$\angle R = 53 - 21 = 32^{\circ}$

An exterior angle of a triangle is less than either of its interior opposite angles.

  1. True

  2. False

  3. Ambiguous

  4. Data Insufficient


Correct Option: B
Explanation:

Answer is option B (False)
In any triangle, if one of the sides is produced, then the exterior angle is greater than either of the interior and opposite angles.
Hence the above statement is false

When an arm of an angle is extended to double its length, then the measure of the angle:

  1. Doubles

  2. Triples

  3. Remains the same

  4. Becomes half


Correct Option: C
Explanation:

Angle remains the same if we extend the arms.

So option $C$ is correct.

When an arm of an angle is extended then the measure of angle: 

  1. doubles

  2. triples

  3. remains the same

  4. none of these


Correct Option: C
Explanation:

When an arm of an angle is extended then the measure of angle remains the same.

An angle which measures $\displaystyle 0^{\circ}$ is called

  1. Obtuse angle

  2. Straight angle

  3. Zero angle

  4. Right angle


Correct Option: C
Explanation:

An angle which measures $ {0}^{o} $ is a zero angle.

Compare the areas of the right angled triangles ABC and DEF in which $\displaystyle \angle A=30^{\circ},\angle B=90^{\circ},AC=4cm,\angle D=60^{\circ},\angle E=90^{\circ}: : and: : DE=4cm $

  1. $\displaystyle Ar\left ( \Delta ABC \right )> Ar\left ( \Delta DEF \right )$

  2. $\displaystyle Ar\left ( \Delta ABC \right )< Ar\left ( \Delta DEF \right )$

  3. $\displaystyle Ar\left ( \Delta ABC \right )= Ar\left ( \Delta DEF \right )$

  4. Can't say


Correct Option: B

If two triangles are congruent, then they are

  1. Symmetrical

  2. Identical

  3. Equilateral

  4. Isosceles


Correct Option: A
Explanation:
Two triangles are congruent but they may not be equilateral or isosceles. (Hence option C and D are wrong)

For two objects to be symmetrical, they must be the same size and shape, with one object having a different orientation from the first.

Identical shapes are the shapes that have exact same shape, size, and position.

Congruent triangles are symmetrical but they may not be identical (as orientation can be different)

Hence option A is correct.

The opening between two lines is called:

  1. angle

  2. point

  3. line

  4. transversal


Correct Option: A
Explanation:

An $angle$ is a combination of two rays (half-lines) with a common endpoint. The latter is known as the vertex of the $angle$ and the rays as the sides, sometimes as the legs and sometimes the arms of the $angle.$

The angle at a point is

  1. $90^\circ$

  2. $180^\circ$

  3. $300^\circ$

  4. $360^\circ$


Correct Option: D
Explanation:

An angle is measured with reference to a circle with its centre at the common endpoint of the rays. Hence, the sum of angles at a point is always 360 degrees.

So option D is the correct answer.

The sum of exterior angles of a triangle is

  1. $180^\circ$

  2. $270^\circ$

  3. $360^\circ$

  4. $540^\circ$


Correct Option: C
Explanation:

The sum of exterior angle of a triangle is $ { 360 } $
the interior angle of a triangle add upto  $ { 180 } $, For any given corner exterior angle is $ { 180 } $ minus interior angle.
So sum of exterior angle is (180-a)+(180-b)+(180-c)=3*180-(a+b+c)=540-180=$360^0$