Tag: types of angle

Questions Related to types of angle

Find the angles in each of the following.
The angles whose supplement is four times its complement

  1. $60^{\circ}$

  2. $30^{\circ}$

  3. $120^{\circ}$

  4. None of these


Correct Option: A
Explanation:

Let the angle be $x^0$.


Supplement angle $=(180^0-x)$

Complement angle $=(90^0-x)$

According to the question,
$180^0-x=4(90^0-x)$

$180^0-x=360^0-4x$

$3x=180^0$

$x=60^0$


Hence, this is the answer.

Find the supplement of each of the following angles.
$148^{\circ}$

  1. $32^{\circ}$

  2. $122^{\circ}$

  3. $148^{\circ}$

  4. None of these


Correct Option: A
Explanation:

We know that the supplement angle

$=180^0-\theta$

So,
The supplement angle of $148^0$ will be
$=180^0-148^0=32^0$ 

Hence, this is the answer.

Find the supplement of each of the following angles.
$120^{\circ}$

  1. $60^{\circ}$

  2. $150^{\circ}$

  3. $20^{\circ}$

  4. None of these


Correct Option: A
Explanation:

We know that the supplement angle

$=180^0-\theta$

So,
The supplement angle of $120^0$ will be
$=180^0-120^0=60^0$ 

Hence, this is the answer.

Find the complement of each of the following angles $35^{\circ}$

  1. $55^{\circ}$

  2. $145^{\circ}$

  3. $35^{\circ}$

  4. None of these


Correct Option: A
Explanation:

We know that the complement angle

$=90^0-\theta$

So,
The complement angle of $35^0$ will be
$=90^0-35^0=55^0$ 

Hence, this is the answer.

Find the supplement of the given angle.
$100^{\circ}$

  1. $80^{\circ}$

  2. $40^{\circ}$

  3. $30^{\circ}$

  4. None of these


Correct Option: A
Explanation:

We know that the sum of the supplement angles

$=180^0$

So,
The supplement angle of $100^0$ will be
$=180^0-100^0=80^0$ 

Hence, this is the answer.

Find the complement of each of the following angles $20^{\circ}$

  1. $70^{\circ}$

  2. $60^{\circ}$

  3. $110^{\circ}$

  4. None of these


Correct Option: A
Explanation:

We know that the complement angle

$=90^0-\theta$

So,
The complement angle of $20^0$ will be
$=90^0-20^0=70^0$ 

Hence, this is the answer.

Find the angles in each of the following.
The angle which is two times its complement

  1. $60^{\circ}$

  2. $120^{\circ}$

  3. $30^{\circ}$

  4. None of these


Correct Option: A
Explanation:

Let the angle be $x^0$.


According to the question,
Complement angle $=(90^0-x)\times 2$

So,

$x=180^0-2x$

$3x=180^0$

$x=60^0$


Hence, this is the answer.

Find the complement of each of the following angles $48^{\circ}$

  1. $42^{\circ}$

  2. $52^{\circ}$

  3. $132^{\circ}$

  4. None of these


Correct Option: A
Explanation:

We know that the complement angle

$=90^0-\theta$

So,
The complement angle of $48^0$ will be
$=90^0-48^0=42^0$ 

Hence, this is the answer.

Find the angles in each of the following.
Two complementary angles are in the ratio $3 : 2$

  1. $54^{\circ}, 36^{\circ}$

  2. $44^{\circ}, 36^{\circ}$

  3. $54^{\circ}, 46^{\circ}$

  4. None of these


Correct Option: A
Explanation:

Let the angles be $3x$ and $2x$.


So,
$3x+2x=90^0$

$5x=90^0$

$x=18^0$

Therefore, the angle are
$54^0, 36^0$


Hence, this is the answer.

If $\angle A$ is complement to $30^o$ and $\angle B $ is supplement to $120^o$ then:

  1. $\angle A > \angle B$

  2. $\angle A < \angle B$

  3. Incomparable

  4. $\angle A = \angle B$


Correct Option: D
Explanation:

Sum of complementary angles is $90^{\circ}$

$\Rightarrow \angle A+{ 30 }^{ \circ  }={ 90 }^{ \circ  }\ \Rightarrow \angle A={ 60 }^{ \circ  }$
Sum of supplementary angles is $180^{\circ}$
$\Rightarrow \angle B+{ 120 }^{ \circ  }={ 180 }^{ \circ  }\ \Rightarrow \angle B={ 60 }^{ \circ  }$
$\Rightarrow \angle A=\angle B$