Tag: history of mathematics

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Questions Related to history of mathematics

Multiple choice maths vedic mathematics square roots using vedic maths square and square roots using vedic mathematics history of mathematics

To find the square of $45$ by Ekadhikena Purvena method the digit $4$ should be multiplied by which number.

  1. By its previous number

  2. By zero

  3. By its next number

  4. By ten
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

In ekadhikena purvena the first digit is multiplied by its next number.

$45^2\Rightarrow $ First 2 digits $=4\times 5$
and last two digits are$=5^2=25\ \Rightarrow 45^2=2025$

Multiple choice maths vedic mathematics square roots using vedic maths square and square roots using vedic mathematics history of mathematics

Square of $113$ by Upsutra Yavadunam Tavadunam Vargecha Yojayet is :

  1. $34569$
  2. $12769$
  3. $54639$
  4. $34359$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

To find the square of $113$,


This is closer to $100$ (base of 10). Write it as $100+13$.

From this method, we can write,

$\dfrac{(113+13)}{13^2}$  i.e., $\dfrac{Number+deficiency}{deficiency^2}$

$=\dfrac{126}{169}$

As we are using base $100$. Digit in hundred's place gets carryforwarded and added to $126$

ie., $(126+1)69=12769$

$12769$ is the square of $113$.

Multiple choice maths vedic mathematics square roots using vedic maths square and square roots using vedic mathematics history of mathematics

Find the square of the number $65$ using Vedic Mathematics.

  1. $4235$
  2. $4335$
  3. $4220$

  4. None of these
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation
To find $(65)^{2}$
Let's take $a=6$. So, $a5=10a+5$ 
Now, $a5$ square can be obtained as follows
$a5=a(a+1)|25$ where $a(a+1)$ is the left side of the number and right side will always be $25$ for the numbers ending with $5$.
Right side of $65$ will be $6\times 7=42$
and left side will be $25$.
So, the number is $4225$.
Hence, $65^{2}=4225$. 
Multiple choice maths vedic mathematics square roots using vedic maths square and square roots using vedic mathematics history of mathematics

State the following statement is true or false
We can find the squares of all the numbers using dwandwa yog method

  1. True

  2. False
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The Vedic method of finding a square root is called the Vedic Duplex method also known as dvandva yog method. As the name implies, the method involves a concept called the duplex of a number.



Multiple choice maths vedic mathematics square roots using vedic maths square and square roots using vedic mathematics history of mathematics

Predict square root of $3136$ using Vilokanam method.

  1. $54$
  2. $56$
  3. $64$
  4. $66$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

We have to find the square root of $3136$ using Vilokanam method.

Its unit digit is $6$.
Therefore, the unit digit of the square root will be $4$ or $6$. 
Ignoring the last two digits (unit digit and ten’s digit) we get $31$. 
The greatest number whose square is less than or equal to $31$ is $5$.
Adjusting above obtained two unit digits $4$ or $6$ to the right of $5$, we get two numbers $54$ and $56$. 
The unique number with unit digit $5$ which lies between $54$ and $56$ is $55$. 
And  $(55)^2 = 3025$
Since, $3136>3025$, therefore, the required square root is $56$.
Thus $\sqrt{3136}=56$

Multiple choice maths vedic mathematics square roots using vedic maths square and square roots using vedic mathematics history of mathematics

Find square root of $9604$ using Vilokanam method.

  1. $98$
  2. $92$
  3. $88$
  4. $82$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

We have to find the square root of $9604$ using Vilokanam method.

Its unit digit is $4$.
Therefore, the unit digit of the square root will be $2$ or $8$. 
Ignoring the last two digits (unit digit and ten’s digit) we get $96$. 
The greatest number whose square is less than or equal to $96$ is $9$.
Adjusting above obtained two unit digits $2$ or $8$ to the right of $9$, we get two numbers $92$ and $98$. 
The unique number with unit digit $5$ which lies between $92$ and $98$ is $95$. 
And  $(95)^2 = 9025$
Since, $9604>9025$, therefore, the required square root is $98$.
Thus $\sqrt{9604}=98$

Multiple choice maths vedic mathematics square roots using vedic maths square and square roots using vedic mathematics history of mathematics

Find square root of $961$ using Vilokanam method.

  1. $29$
  2. $30$
  3. $31$
  4. $32$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

We have to find the square root of $961$ using Vilokanam method.

Its unit digit is $1$.
Therefore, the unit digit of the square root will be $1$ or $9$. 
Ignoring the last two digits (unit digit and ten’s digit) we get $9$. 
The greatest number whose square is less than or equal to $9$ is $3$.
Adjusting above obtained two unit digits $1$ or $9$ to the right of $2$, we get two numbers $31$ and $39$. 
The unique number with unit digit $5$ which lies between $31$ and $39$ is $35$. 
And  $(35)^2 = 1225$
Since, $961<1225$, therefore, the required square root is $31$.
Thus $\sqrt{961}=31$