Tag: history of mathematics

Questions Related to history of mathematics

To find the square of $45$ by Ekadhikena Purvena method the digit $4$ should be multiplied by which number.

maths vedic mathematics square roots using vedic maths square and square roots using vedic mathematics history of mathematics

  1. By its previous number

  2. By zero

  3. By its next number

  4. By ten

Show answer
Correct Option: C
Explanation:

In ekadhikena purvena the first digit is multiplied by its next number.

$45^2\Rightarrow $ First 2 digits $=4\times 5$
and last two digits are$=5^2=25\ \Rightarrow 45^2=2025$

Square of $113$ by Upsutra Yavadunam Tavadunam Vargecha Yojayet is :

maths vedic mathematics square roots using vedic maths square and square roots using vedic mathematics history of mathematics

  1. $34569$

  2. $12769$

  3. $54639$

  4. $34359$

Show answer
Correct Option: B
Explanation:

To find the square of $113$,


This is closer to $100$ (base of 10). Write it as $100+13$.

From this method, we can write,

$\dfrac{(113+13)}{13^2}$  i.e., $\dfrac{Number+deficiency}{deficiency^2}$

$=\dfrac{126}{169}$

As we are using base $100$. Digit in hundred's place gets carryforwarded and added to $126$

ie., $(126+1)69=12769$

$12769$ is the square of $113$.

The Dvanda of 567 can be calculated as :- D(567)=$(x\times 5\times 7)$$+$$6^2$
What is the value of $x$?

maths vedic mathematics square roots using vedic maths square and square roots using vedic mathematics history of mathematics

  1. $2$

  2. $3$

  3. $4$

  4. $5$

Show answer
Correct Option: A
Explanation:

$D(567)=(2\times 5\times 7)+6^2\ \therefore x=2$

Find the square of the number $65$ using Vedic Mathematics.

maths vedic mathematics square roots using vedic maths square and square roots using vedic mathematics history of mathematics

  1. $4235$

  2. $4335$

  3. $4220$

  4. None of these

Show answer
Correct Option: D
Explanation:
To find $(65)^{2}$
Let's take $a=6$. So, $a5=10a+5$ 
Now, $a5$ square can be obtained as follows
$a5=a(a+1)|25$ where $a(a+1)$ is the left side of the number and right side will always be $25$ for the numbers ending with $5$.
Right side of $65$ will be $6\times 7=42$
and left side will be $25$.
So, the number is $4225$.
Hence, $65^{2}=4225$. 

Square root of $315$ by Dwandwa Yog method is?

maths vedic mathematics square roots using vedic maths square and square roots using vedic mathematics history of mathematics

  1. $17.84$

  2. $17.74$

  3. $17.54$

  4. $17.64$

Show answer
Correct Option: B

State the following statement is true or false
We can find the squares of all the numbers using dwandwa yog method

maths vedic mathematics square roots using vedic maths square and square roots using vedic mathematics history of mathematics

  1. True

  2. False

Show answer
Correct Option: A
Explanation:

The Vedic method of finding a square root is called the Vedic Duplex method also known as dvandva yog method. As the name implies, the method involves a concept called the duplex of a number.



Square root of $732108$ by Dwandwa Yog method is?

maths vedic mathematics square roots using vedic maths square and square roots using vedic mathematics history of mathematics

  1. $256.63$

  2. $896.25$

  3. $745.23$

  4. $855.63$

Show answer
Correct Option: D

Predict square root of $3136$ using Vilokanam method.

maths vedic mathematics square roots using vedic maths square and square roots using vedic mathematics history of mathematics

  1. $54$

  2. $56$

  3. $64$

  4. $66$

Show answer
Correct Option: B
Explanation:

We have to find the square root of $3136$ using Vilokanam method.

Its unit digit is $6$.
Therefore, the unit digit of the square root will be $4$ or $6$. 
Ignoring the last two digits (unit digit and ten’s digit) we get $31$. 
The greatest number whose square is less than or equal to $31$ is $5$.
Adjusting above obtained two unit digits $4$ or $6$ to the right of $5$, we get two numbers $54$ and $56$. 
The unique number with unit digit $5$ which lies between $54$ and $56$ is $55$. 
And  $(55)^2 = 3025$
Since, $3136>3025$, therefore, the required square root is $56$.
Thus $\sqrt{3136}=56$

Find square root of $9604$ using Vilokanam method.

maths vedic mathematics square roots using vedic maths square and square roots using vedic mathematics history of mathematics

  1. $98$

  2. $92$

  3. $88$

  4. $82$

Show answer
Correct Option: A
Explanation:

We have to find the square root of $9604$ using Vilokanam method.

Its unit digit is $4$.
Therefore, the unit digit of the square root will be $2$ or $8$. 
Ignoring the last two digits (unit digit and ten’s digit) we get $96$. 
The greatest number whose square is less than or equal to $96$ is $9$.
Adjusting above obtained two unit digits $2$ or $8$ to the right of $9$, we get two numbers $92$ and $98$. 
The unique number with unit digit $5$ which lies between $92$ and $98$ is $95$. 
And  $(95)^2 = 9025$
Since, $9604>9025$, therefore, the required square root is $98$.
Thus $\sqrt{9604}=98$

Find square root of $961$ using Vilokanam method.

maths vedic mathematics square roots using vedic maths square and square roots using vedic mathematics history of mathematics

  1. $29$

  2. $30$

  3. $31$

  4. $32$

Show answer
Correct Option: C
Explanation:

We have to find the square root of $961$ using Vilokanam method.

Its unit digit is $1$.
Therefore, the unit digit of the square root will be $1$ or $9$. 
Ignoring the last two digits (unit digit and ten’s digit) we get $9$. 
The greatest number whose square is less than or equal to $9$ is $3$.
Adjusting above obtained two unit digits $1$ or $9$ to the right of $2$, we get two numbers $31$ and $39$. 
The unique number with unit digit $5$ which lies between $31$ and $39$ is $35$. 
And  $(35)^2 = 1225$
Since, $961<1225$, therefore, the required square root is $31$.
Thus $\sqrt{961}=31$