Tag: mathematics and statistics

Quizzes (38) Questions (955)

Questions Related to mathematics and statistics

Multiple choice mathematics and statistics banks and simple interest introduction to interests introduction to interest introduction to interest payments

Peter invests $ $5,000$ at $4$% simple annual interest. How much in his investment worth after $2$ months?

  1. 5323.66

  2. 5033.33

  3. 5066.33

  4. 5343.67
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

If the principal amount is $p$, annual interest is $r$ $\%$ then for simple interest after $n$ years the amount will be $p\left (1+\dfrac {nr}{100}\right)$.
Here $p=5000$, $n=\dfrac {1}{6}$, $r=4$ $\%$
So, the amount after $2$ months is $5000\left (1+\dfrac {2}{300}\right) = 5000\left (\dfrac {151}{150}\right) = 5033.33$

Multiple choice mathematics and statistics banks and simple interest introduction to interests introduction to interest introduction to interest payments

The difference between compound interest and simple interest on an amount of Rs. $15,000$ for $2$ years is Rs. $96$. What is the rate of interest per annum?

  1. $8$
  2. $10$
  3. $12$

  4. Cannot be determined

  5. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

$\left [15000\times \left (1 + \dfrac {R}{100}\right )^{2} - 15000\right ] - \left (\dfrac {15000\times R\times 2}{100}\right ) = 96$
$\Rightarrow 15000 \left [\left (1 + \dfrac {R}{100}\right )^{2} - 1 - \dfrac {2R}{100}\right ] = 96$
$\Rightarrow 15000 \left [\dfrac {(100 + R)^{2} - 10000 - (200\times R)}{10000}\right ] = 96$
$\Rightarrow R^{2} = \left (\dfrac {96\times 2}{3}\right ) = 64$
$\Rightarrow R = 8$.
$\therefore Rate = 8$%.

Multiple choice mathematics and statistics banks and simple interest introduction to interests introduction to interest introduction to interest payments

Ramesh borrowed $Rs \ 14000$ from a bank on simple interest for a period of $5$ years. He returned $Rs \ 6000$ to the bank at the end of three years and $Rs \ 10,900$ at the end of the five years and closed the account. Find the rate of interest per annum.

  1. $4 \%$
  2. $4.14 \%$
  3. $6 \%$
  4. $9 \%$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

We have,

$P=Rs.\ 14000$

Ramesh returned $Rs.\ 6000$ to the bank at the end of $3$ years.

And returned $Rs.\ 10, 900$ to the bank at the end of $5$ years.

So, the total amount returned by Ramesh is $6000+10,900=Rs.\ 16, 900$

$T=5\ years$
$R=?$

We know that
$A-P=\dfrac{PRT}{100}$ 

So,

$16900-14000=\dfrac{14000\times R\times 5}{100}$ 

$2900=140\times R\times 5$ 

$R=4.14\%$

Hence, this is the answer.

Multiple choice mathematics and statistics banks and simple interest introduction to interests introduction to interest introduction to interest payments

Find the simple interest rate applied to a principal over $8$ years if the total interest paid equals the borrowed principal.

  1. $10\%$
  2. $20\%$
  3. $12.5\%$
  4. $15\%$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

We have given that interest and principal are equal.

Let Rs. $x$ be the interest and principal.
Here $T=8$ years
We know $S.I.=\dfrac{P\times R\times T}{100}$
$\Rightarrow$ $x=\dfrac{x\times R\times 8}{100}$
$\Rightarrow$ $R=\dfrac{100}{8}=12.5\%$
Simple interest rate is $12.5\%$.

Multiple choice mathematics and statistics banks and simple interest introduction to interests introduction to interest introduction to interest payments

Find the simple interest rate applied to a principal over $5$ years if the total interest paid equals the borrowed principal.

  1. $10\%$
  2. $20\%$
  3. $30\%$
  4. $40\%$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

We have given that interest and borrowed principal are same.

Let $x$ be the interest and borrowed principal.
We know $S.I.=\dfrac{P\times R\times T}{100}$
$\Rightarrow$ $x=\dfrac{x\times R\times 5}{100}$
$\therefore$ $R=\dfrac{100}{5}=20\%$

Multiple choice mathematics and statistics banks and simple interest introduction to interests introduction to interest introduction to interest payments

What is the simple interest rate applied to a principal over $2.5$ years if the total interest paid equals the borrowed principal?

  1. $20\%$
  2. $30\%$
  3. $40\%$
  4. $50\%$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

We have given that interest and principal are equal.

Let Rs. $x$ be the interest and principal.
Here $T=2.5$ years
We know $S.I.=\dfrac{P\times R\times T}{100}$
$\Rightarrow$ $x=\dfrac{x\times R\times 2.5}{100}$
$\Rightarrow$ $R=\dfrac{100}{2.5}=40\%$
Therefore, simple interest rate is $40\%$.

Multiple choice mathematics and statistics banks and simple interest introduction to interests introduction to interest introduction to interest payments

Jenn borrowed Rs. $5,000$ for $5$ years and had to pay Rs. $1,500$ simple interest at the end of that time. What rate of interest did she pay?

  1. $5$
  2. $6$
  3. $7$
  4. $8$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

$\Rightarrow$  $P=Rs.5000,\,T=5\,years $ and $S.I.=Rs.1500$

$\Rightarrow$  $S.I.=\dfrac{P\times R\times T}{100}$

$\Rightarrow$  $1500=\dfrac{5000\times R\times 5}{100}$

$\Rightarrow$  $R=\dfrac{1500}{250}$

$\therefore$    $R=6\%$

Multiple choice mathematics and statistics banks and simple interest introduction to interests introduction to interest introduction to interest payments

Joshita borrowed Rs. $3,000$ for $3$ years and had to pay Rs.$ 1,000$ simple interest at the end of that time. What rate of interest did she pay?

  1. $11.11$
  2. $22.22$
  3. $33.33$
  4. $44.44$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

$\Rightarrow$  $P=Rs.3000,\,T=3\,years$ and $S.I.=Rs.1000$.

$\Rightarrow$  $S.I.=\dfrac{P\times R\times T}{100}$

$\Rightarrow$  $1000=\dfrac{3000\times R\times 3}{100}$

$\Rightarrow$  $R=\dfrac{1000}{90}$

$\therefore$    $R=11.11\%$

Multiple choice mathematics and statistics banks and simple interest introduction to interests introduction to interest introduction to interest payments

What rate will amount to Rs. $1,331$ in three years (compounded annually), if the principal amount was Rs $1,000$ respectively? 

  1. $10$%
  2. $11$%
  3. $12$%
  4. $13$%
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

We have,

$A=Rs.\ 1331$
$P=Rs.\ 1000$
$T=3\ years$
$R=?$

We know that
$A=P\left(1+\dfrac{R}{100}\right)^T$

Therefore,
$1331=1000\left(1+\dfrac{R}{100}\right)^3$

$\dfrac{1331}{1000}=\left(1+\dfrac{R}{100}\right)^3$

$\dfrac{11}{10}=1+\dfrac{R}{100}$

$\dfrac{R}{100}=\dfrac{1}{10}$

$R=10\%$

Hence, this is the answer.

Multiple choice mathematics and statistics banks and simple interest introduction to interests introduction to interest introduction to interest payments

If the simple interest on a certain sum of money is $\displaystyle \frac{1}{100}$th of the sum and the rate per cent equals 4 times the number of years, then the rate of interest per annum is

  1. $1$%
  2. $2$%
  3. $3$%
  4. $4$%
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

$SI=P/100; r=4t \implies t=r/4$

$SI=\cfrac { P\times r\times t }{ 100 } $
$\implies (P/100)=\cfrac { P\times r\times (r/4) }{ 100 } $
$\implies r\times (r/4)=1\ \implies r=2\%$