Tag: perimeter and area

Questions Related to perimeter and area

Consider the railway platform which is in square shape having side length $2\ km$. Then area of the platform is $4$ ____.

maths perimeter and area converting between units of areas the metric system metric system

  1. $m$

  2. $km$

  3. $km^{2}$

  4. $m^{2}$

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Correct Option: C
Explanation:

Area of square platform$=2\times 2=4 km^2$

The area of a square field is $30\dfrac {1}{4}m^2$. Calculate the length of the side of the square.

maths perimeter and area converting between units of areas the metric system metric system

  1. $5\dfrac {1}{3}m$

  2. $5\dfrac {1}{2}m$

  3. $5\dfrac {2}{5}m$

  4. $5\dfrac {1}{4}m$

Show answer
Correct Option: B
Explanation:

Let side of square field be $x$.


Then area of square field $= x^2$


According to question

$x^2 = 30 \dfrac{1}{4} m^2$

$x^2 = \dfrac{121}{4} m^2$

$x = \dfrac{\sqrt{121}}{\sqrt{4}} m$

$x = \dfrac{11}{2}$

Hence side of square field is $5 \dfrac{1}{2} m$

Option (B)

The area of a square field is $80\dfrac {244}{729}$ square metres. Find the length of each sides field.

maths perimeter and area converting between units of areas the metric system metric system

  1. $8\dfrac {25}{27}m$

  2. $8\dfrac {24}{27}m$

  3. $8\dfrac {26}{27}m$

  4. $8\dfrac {22}{27}m$

Show answer
Correct Option: C
Explanation:

Given area of square field $= 80 \dfrac{244}{729} m^2$


Let us assume that side of square field is x 


Then area of field $= x^2$

According to question

$x^2 = 80 \dfrac{244}{729} m^2$

$x^2 = \dfrac{58,564}{729} m^2$

$x = \dfrac{\sqrt{58,564}}{\sqrt{729}} m$

$x = \dfrac{242}{27} m$

Hence side of field is $8 \dfrac{26}{27} m$.

Option (C)

The area of a square field is $325\ m^2$. Find the approximate length of one side of the field. (upto 2 places of decimals) (in $m^2$)

maths perimeter and area converting between units of areas the metric system metric system

  1. $19.03$

  2. $18.02$

  3. $18.03$

  4. $17.03$

Show answer
Correct Option: C
Explanation:

We know area of any square is its side x side 

Let us assume that side of square field is x 
Then area of square field $= x^2$
According to question

$x^2 = 325 m^2$

$\Rightarrow x^2 = 325$

$x = \sqrt{325}$

So $x = 18.03$

Hence side of square field is $18.03 m$

option (C)

The area of a square playground is $256.6404$ square metres. Find the length of one side of the playground.

maths perimeter and area converting between units of areas the metric system metric system

  1. $16.04$ metres

  2. $16.02$ metres

  3. $16.06$ metres

  4. $16.08$ metres

Show answer
Correct Option: B
Explanation:

Let side of square play ground be x

Then area of square play ground will be $x^2$
According to question

$x^2 = 256.6404 m^2$

$x = \sqrt{256.6404} m$

$x = \dfrac{\sqrt{2566404}}{\sqrt{10000}} m$

$= \dfrac{1602}{100}$

Hence side of square is $16.02 m$

Option (B)

By converting the $5.6 m^2$ into the $cm^2$, the answer will be

maths perimeter and area converting between units of areas the metric system metric system

  1. $0.0056cm^2$

  2. $5600cm^2$

  3. $56000cm^2$

  4. $560cm^2$

Show answer
Correct Option: B