Tag: electric current and its effects

Questions Related to electric current and its effects

A lamp of $100\ W$ and a heater of $1\ kW$ are in simultaneous use for $10\ hrs$. The units of electricity consumed according to the meter in the house is:

  1. $10$

  2. $9$

  3. $11$

  4. $1$


Correct Option: C
Explanation:

For lamp, electrical energy consumed is $E _L = P _Lt =100\times 10 = 1\ kWh$

For heater, electrical energy consumed is $E _H = P _Ht =1000\times 10 = 10\ kWh$
Hence, total electrical energy consumed is: $E = E _L+E _H=11\ kWh$

A motor of $50\ W$ runs for $20\ hrs$. How many 'units' ($kWh$) of electrical energy are consumed?

  1. $5\ kWh$

  2. $2\ kWh$

  3. $1\ kWh$

  4. $2.5\ kWh$


Correct Option: C
Explanation:

Given :       $P = 0.050\ kW$ 

                   $t = 20\ h$

Energy consumed,      
$E = Pt =0.050\times 20 = 1\ kWh$

A heater is marked 1000 W. The energy consumed by it in ten hours is

  1. 10 J

  2. 10 KJ

  3. 10 kWh

  4. 100 KJ


Correct Option: C
Explanation:

Given :    $P = 1000$ W $=1$ kW              $t = 10$ h

$\therefore$ Energy consumed in 10 h       $E = Pt = 1\times 10 =10$ kWh

Which of these will consume most units of energy in a day?

  1. A $60\ W$ bulb used for $6\ hrs$.

  2. A $30\ W$ bulb used for $12\ hrs$.

  3. A $20\ W$ bulb used for $24\ hrs$.

  4. A $100\ W$ bulb used for $2\ hrs$.


Correct Option: C
Explanation:

Energy consumed per day is: $E = Pt$

(A) :     $E _A = 0.06\times 6 = 0.36\ kWh$
(B) :     $E _B = 0.03\times 12 = 0.36\ kWh$ 

(C) :     $E _C = 0.02\times 24 = 0.48\ kWh$ 
(D) :     $E _D = 0.10\times 2 = 0.2\ kWh$ 

Thus bulb of option C will consume more energy.

A current of $4  A$ flows through a $12  V$ car headlight bulb for $10$ minutes, how much energy is consumed?

  1. $8 \times {10}^{-3} kwh$

  2. $48 kwh$

  3. $8 kwh$

  4. $8 \times {10}^{3} kwh$


Correct Option: A
Explanation:

$E = VIt$
  $= 12 \times 4 \times \dfrac{1}{6}$
  $= 8 \times {10}^{-3}   kwh$

Calculate the monthly bill if a heater of 100 watt is used at the rate of rs. 1 per unit for 1 hour daily.

  1. Rs. 200

  2. Rs. 6000

  3. Rs. 100

  4. Rs. 3


Correct Option: D
Explanation:

Given :       $P=0.1$ kW           $t = 1$ hour per day

Energy consumed per day     $E = Pt = 0.1\times 1 = 0.1$ kWh per day
Total energy consumed per month  $E _T = 30\times 0.1 = 3$ kWh per month
Cost of electricity  $ =Re$ $ 1 $ per unit i.e per kWh
$\therefore$  Monthly bill $ = Re.$ $1\times 3   =$Rs. $3$ per month

What should be the bill for the month of March for a heater of resistance $\displaystyle $ connector to 220V mains. The cost of energy is Rs.1 kWh and the heater is used 1 hour daily.

  1. Rs. 144

  2. Rs. 60

  3. Rs. 72

  4. Rs. 50


Correct Option: C

Calculate the total power of 2 fans, if each of them draws a current of $5   A$ at a p.d of $200   V$.

  1. $2000 \omega$

  2. $1000 V$

  3. $250 \omega$

  4. $2 \omega$


Correct Option: A
Explanation:

$I = 5A,   p.d = 200   V$
Power $= V \times I = 200 \times 5 = 1000   \omega$
For 2 fans $= 2 \times 1000 = 2000   \omega$.

A current of $0.5  A$ flows through a resistance of $10  \Omega$ for $\dfrac{1}{2}$ hour. Find the amount of electrical energy consumed by resistance.

  1. $450 J$

  2. $4500 J$

  3. $45 J$

  4. $45000 J$


Correct Option: B
Explanation:

$E = {I}^{2}RT = {0.5}^{2} \times 10 \times 1800$
       $= 4500  J$

Calculate the energy transferred by a $5  A$ current flowing through a resistor of $20   \ ohms$ for $30$ minutes.

  1. $25 kwh$

  2. $50 kwh$

  3. $2.5 \times {10}^{-2} kwh$

  4. $5 \times {10}^{-2} kwh$


Correct Option: C
Explanation:

$E = {I}^{2}Rt$
$= {5}^{2} \times 2 \times \dfrac{1}{2}$
$= 2.5 \times {10}^{-2}  kwh$