Tag: electronic devices

Questions Related to electronic devices

 If the series resistance decreases in an unloaded zener regulator, the zener current

  1. Decreases

  2. Stays the same

  3. Increases

  4. Equals the voltage divided by the resistance


Correct Option: C
Explanation:

current increases as the resistance decreases, as zener current is inversely proportional to the series resistance

Zener diodes with breakdown voltage ranging over 2V- 200 V are commercially available. Breakdown voltage of a zener diode

  1. Increases with increasing doping concentration

  2. Decreases with increasing doping concentration

  3. Does not depend on doping concentration

  4. May increases or decreases with increasing doping concentration


Correct Option: B
Explanation:

For Zener Diodes, the breakdown voltage decreases with increasing doping concentration.

The load voltage is approximately constant when a zener diode is

  1. Forward-biased

  2. Reverse-biased

  3. Operating in the breakdown region

  4. Unbiased


Correct Option: C
Explanation:

The zener voltage will be a constant only when it is operating in the breakdown region

A zener diode is specified as having a breakdown voltage of $9.1 V$, with a maximum power dissipation of $364 \ mW$. What is the maximum current the diode can handle? 

  1. $40 \ mA$

  2. $60 \ mA$

  3. $50 \ mA$

  4. $45 \ mA$


Correct Option: B

In a zener regulated power supply of a zener diode with $V _z$ = 6V is used for regulation. The load current is to be 4 mA and the unregulated input is 10 V. The value of series resistor $R _s$ is

  1. less than $ 5 \ \Omega$

  2. Infinite

  3. greater than 100 $\Omega$

  4. zero


Correct Option: C

If the revers bias voltage applied  to a p-n junction diode is increased, its barrier capacitance would:

  1. increase

  2. decrease

  3. remain constant

  4. first increase then decrease


Correct Option: A

In a zener diode, break down occurs in reverse bias due to

  1. Impact ionisation

  2. Internal field emission

  3. High doping concentration

  4. All of these


Correct Option: D

Two capacitors each having capacitance C and breakdown voltage V are joined in series. The capacitance and the breakdown voltage of the combination will be 

  1. 2 C and 2 V

  2. C/2 and V/2

  3. 2 C and V/2

  4. C/2 and 2 V.


Correct Option: D
Explanation:

We know that the charge on a capacitor is 
$\begin{array}{l} Q=CV \\ C\propto \dfrac { 1 }{ V }  \\ in\, \, series\, \, combination \\ { C _{ net } }=\dfrac { { { C _{ 1 } }{ C _{ 2 } } } }{ { { C _{ 1 } }+{ C _{ 2 } } } }  \\ Hence, \\ { C _{ eq } }=\dfrac { C }{ 2 }  \\ { V _{ combination } }=2V \end{array}$

$\therefore$ option $D$ is correct.

What is the order of the reverse saturation current before breakdown in a Zener diode

  1. ampere

  2. milli-ampere

  3. it depends on the applied voltage

  4. micro-ampere


Correct Option: C

The number of minority carriers crossing the junction of a diode depends primarily on the :

  1. concentration of doping impurities

  2. magnitude of potential barrier

  3. magnitude of the forward bias voltage

  4. rate of thermal generation of electron-hole pair


Correct Option: C