Tag: matter around us

Questions Related to matter around us

Which of the following has the highest numeric value?

  1. $100$ Tm

  2. $1000$ Gm

  3. $10^4$ mm

  4. $10^6$ nm


Correct Option: A
Explanation:

$100\ Tm=100000\ Gm$

$1000\ Gm$
$10^4\ mm=1\times10^{-10}\ Gm$
$10^6\ nm=1\times10^{-12}\ Gm$

Which of the following is the correct value of $R$ in $SI$ units?

  1. $0.083$ $bar$ $dm^{3}K^{-1}mol^{-1}$

  2. $1.98\ cal K^{-1}mol^{-1}$

  3. $8.314\times 10^{7} erg K^{-1}mol^{-1}$

  4. $8.314 J\ K^{-1}mol^{-1}$


Correct Option: D
Explanation:

$R$ is called as universal gas constant or molar gas constant.

              $R=0.0821\quad L\quad atm\quad { mol }^{ -1 }{ k }^{ -1 }\ R=0.0831\quad { dm }^{ 3 }bar\quad { mol }^{ -1 }{ k }^{ -1 }\ R=8.314\quad J\quad { mol }^{ -1 }{ k }^{ -1 }\ R=8.314\times { 10 }^{ 7 }erg\quad { mol }^{ -1 }{ k }^{ -1 }\ R=1.98\quad Cal\quad { mol }^{ -1 }{ k }^{ -1 }$
The $S.I$ units of molar gas constant $(R)$ is $J\quad { mol }^{ -1 }{ k }^{ -1 }$.
$\therefore \quad R=8.314\quad J\quad { mol }^{ -1 }{ k }^{ -1 }$ is the correct answer.

The prefix zepto stands for:

[Note : unit in m]

  1. $10^9$

  2. $10^{-12}$

  3. $10^{-15}$

  4. $10^ {-21}$


Correct Option: D
Explanation:

Zepto = $10^{-21}m$ .

$1^{\circ}C$ rise in temperature is equal to rise of:

  1. ${ 1 }^{ 0 }F$

  2. ${ 9/5 }^{ 0 }F$

  3. ${ 5/9 }^{ 0 }F$

  4. ${ 33 }^{ 0 }F$


Correct Option: B
Explanation:

Solution:- (B) $\cfrac{9}{5} ℉$

As we now that,
$F  = \cfrac{9}{5} C + 32$
As the temperature is risen by $1 ℃$-
$C' = C + 1$
Therefore,
$F' = \cfrac{9}{5} \left( C + 1 \right) + 32$
$F' = \cfrac{9}{5}C + \cfrac{9}{5} + 32$
$\Rightarrow F' = \left( \cfrac{9}{5}C + 32 \right) + \cfrac{9}{5}$
$\Rightarrow F' = F + \cfrac{9}{5}$
Hence $1 ℃$ rise in temperature is equal to the rise in $\cfrac{9}{5} ℉$.

If the temperature of a water bath is $104^{0}\ F$ then its value in degree Celsius scale will be?

  1. $35^{0}C$

  2. $45^{0}C$

  3. $50^{0}C$

  4. $40^{0}C$


Correct Option: D
Explanation:

Conversion from Fahrenheit to Celsius



$(T\ °F − 32) \times \dfrac{5}{9} = t\ °C$

Substituting it, we get,

$(104\ °F − 32) \times \dfrac{5}{9} = 40\ °C$


Hence, the correct option is $D$

Thermometer $(A) & (B)$ have ice points marked at $15^oC & 25^oC$ and steam points at $75^oC & 125^oC$ respectively. When thermometer A measures the temperrature of a bath as $60^oC$ the reading of B for the same bath is :-

  1. $60^oC$

  2. $75^oC$

  3. $90^oC$

  4. $100^oC$


Correct Option: B

Weight of a body is:

  1. constant

  2. not constant

  3. does not change from place to place

  4. both A and C


Correct Option: B
Explanation:

Mass of a body is constant whereas weight of a body depends on the acceleration due to gravity at that point. Therefore, weight of body is not constant & varies from place to place.