Tag: maths

Quizzes (518) Questions (9324)

Questions Related to maths

Multiple choice polyhedrons visualising solid shapes maths

Can a polyhedra have $10$ faces, $20$ edges and $15$ vertices?

  1. Yes

  2. No

  3. Depends on dimension

  4. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Euler's formula for polyhedra is V - E + F = 2. For F = 10, E = 20, V = 15: 15 - 20 + 10 = 5. Since 5 is not equal to 2, such a polyhedron cannot exist.

Multiple choice polyhedrons visualising solid shapes maths

State true or false
Cube is a regular polyhedron where cuboid is not.

  1. True

  2. False
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

A cube is a regular polyhedron because all its faces are congruent regular polygons (squares) and the same number of faces meet at each vertex. A cuboid is not regular because its faces are not necessarily congruent squares.

Multiple choice polyhedrons visualising solid shapes maths

State true or false
Cube ,cuboid have same number of edges, vertices and faces?

  1. True

  2. False
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Both a cube and a cuboid have 6 faces, 12 edges, and 8 vertices.

Multiple choice polyhedrons visualising solid shapes maths

Which of the following is not a polyhedron?

  1. Cone

  2. Pyramid

  3. Prism

  4. Cylinder
Reveal answer Fill a bubble to check yourself
A,D Correct answer
Explanation

Cone is not a polyhedron as it has a curved surface. Similarly cylinder also not a polyhedron.

Multiple choice polyhedrons visualising solid shapes maths

Is it possible to have a polyhedron with more than 4 faces? 

  1. Possible

  2. Not possible

  3. Either

  4. Neither
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

It is possible, only if the number of faces are greater than or equal to 4

Multiple choice polyhedrons visualising solid shapes maths

O ABC is a tetrahedron such that OA$=$OB$=$CO$=$K and $\angle AOB=\angle BOC =\angle COA =\theta$.

  1. $\left[\dfrac{\pi}{3}, \dfrac{2\pi}{3}\right]$
  2. $\left[0, \dfrac{2\pi}{3}\right]$
  3. $\left[\dfrac{\pi}{4}, \dfrac{\pi}{3}\right]$
  4. $\left[0, \dfrac{\pi}{2}\right]$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

In a tetrahedron OABC with OA=OB=OC=K and equal face angles theta at O, the dihedral angles and face angles are constrained by the geometry of the solid. The range of the face angle theta for such a tetrahedron is [pi/3, 2pi/3].

Multiple choice polyhedrons visualising solid shapes maths

A shuttle cock used for playing badminton has the shape of the combination of: 

  1. a cylinder and a sphere

  2. a sphere and a cone

  3. a cylinder and a hemisphere

  4. a hemisphere and frustum cone
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

A shuttle cock has the shape of the combination of a hemisphere and a frustum cone. 

Multiple choice maths measurement (length) conversion of length using decimals in units of length define weight and units of weight how much does it weigh?

A train $280 m$ long, running with a speed of 63$\mathrm { km } /$ hr will pass a tree in 

  1. $15 sec$
  2. $16 sec$
  3. $18 sec$
  4. $20 sec$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

$Speed\>of\>train\>=\>63(\dfrac{Km}{hr})\\=(\dfrac{63\cdot100m}{3600s})\\=17.5(\dfrac{m}{s})\\By\>passing\>a\>tree,\>train\>will\>have\>to\>cross\>its\>own\>length\\\therefore\>Time\>taken\>=\>(\dfrac{280}{17.5})=16sec$

Multiple choice maths measurement (length) conversion of length using decimals in units of length define weight and units of weight how much does it weigh?

Convert the following :
$27$ km $241$ m $319$ mm into $m$

  1. $27241.319\ m$
  2. $27000.319\ m$
  3. $27219.241\ m$
  4. $27319.241\ m$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

We have,

$27\ km\ 241\ m\ 319\ mm$

We know that
$1\ km =1000\ m$
$1\ mm=10^{-3}\ m$

Therefore,

$\Rightarrow 27\times 10^3\ m+241\ m+ 319\times 10^{-3}\ m$

$\Rightarrow 27000\ m+241\ m+ 0.319\ m$

$\Rightarrow 27241.319\ m$

Hence, this is the answer.