Questions Related to maths

Multiple choice maths calculations and mental strategies 1 equations from statements forming equations from statements writing mathematical statements

20 years ago when my parents got married their average age was 23 years, now the average age of my family consisting of my self and my parents is 34 years, then my present age is?

  1. 14 years

  2. 16 years

  3. 18 years

  4. 36 years

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

20 years ago, the average age of the parents was 23, so their total age then was 46. Today, 20 years later, the sum of their present ages is 46 + 2 * 20 = 86 years. The current average age of the family of three (parents + child) is 34, meaning the total family age is 3 * 34 = 102 years. Subtracting the parents' total age from the family total gives the child's present age as 102 - 86 = 16 years.

Multiple choice maths calculations and mental strategies 1 equations from statements forming equations from statements writing mathematical statements

If  $12$  years hence of Ravi will he  $9$  times his age  $12$  years ago, find the present age of Ravi

  1. $12 years$
  2. $15 years$
  3. $18 years$
  4. $20 years$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let Ravi's present age be R. 12 years hence, his age will be R + 12, and 12 years ago, his age was R - 12. According to the problem, R + 12 = 9(R - 12). Expanding this gives R + 12 = 9R - 108, which simplifies to 8R = 120, resulting in R = 15 years.

Multiple choice maths calculations and mental strategies 1 equations from statements forming equations from statements writing mathematical statements

$A$  is  $3$ times as old as  $B$  and  $C$  together. If after  $10$  years  $A's$  age would be equal sum of the ages of  $B$  and  $C .$  find the present age of  $A$

  1. $15$ years
  2. $20$ years
  3. $21$ years
  4. $25$ years
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let A = 3(B + C). After 10 years, (A + 10) = (B + 10) + (C + 10). A + 10 = B + C + 20, so A = B + C + 10. Substituting B + C = A/3, we get A = A/3 + 10. 2A/3 = 10, so A = 15.

Multiple choice maths calculations and mental strategies 1 equations from statements forming equations from statements writing mathematical statements

Three times a number is equal to two times of the other. Find the ratio of 3 times the sum and 5 times the difference of the two numbers.

  1. 2

  2. 4

  3. 1

  4. 3

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let the two numbers be x and y. We are given 3x = 2y, which implies x/y = 2/3, or let x = 2k and y = 3k. The sum of the numbers is 5k, so 3 times the sum is 3(5k) = 15k. The difference is y - x = k, so 5 times the difference is 5(1k) = 5k. The ratio of 3 times the sum to 5 times the difference is 15k / 5k = 3.

Multiple choice maths calculations and mental strategies 1 equations from statements forming equations from statements writing mathematical statements

There are m men and two women participating in a chess tournament. Each participate plays two games with every other participant. If the number of games played by the men between themselves exceeds the number of games played between the men and the women by $84$, then the value of m is?

  1. $9$
  2. $7$
  3. $11$
  4. $12$
Reveal answer Fill a bubble to check yourself
A Correct answer
Multiple choice maths calculations and mental strategies 1 equations from statements forming equations from statements writing mathematical statements

x years ago, the difference between the ages of Hari and Sadu was y years. Then after z years what will be the difference between their ages?

  1. x years

  2. y years

  3. z years

  4. $(x+y+z)$ years
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The difference between the ages of two people remains constant over time regardless of past or future years. Therefore, if the difference was y years x years ago, it will still be y years after z years.