Tag: maths

Quizzes (518) Questions (9324)

Questions Related to maths

Multiple choice maths equation reducing simple equations to simpler form solving linear equations solution of a linear equation in one variable

On a car trip Sam drove  $m$  miles, Kara drove twice as many miles as Sam, and Darin drove  $20$  fewer miles than Kara. In terms of  $m$ , how many miles did Darin drive?

  1. $2m+20$
  2. $2m-20$
  3. $\frac{m}{2}+20$
  4. $\frac{m+20}{2}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Given that

Number of miles driven by $Sam$ $=$ $m$
As $Kara$ drove twice as many miles as $Sam$,
Number of miles drove by $Kara$ $=$ $2m$
As $Darin$ drove 20 fewer miles than $Kara$,

Hence, Number of miles drove by $Darin$ $=$ Number of miles drove by $Kara$ $-$ $20$
$=$ $2m$ $-$ $20$ 
Therfore, $Darin$ drove $'2m$ $-$ $20'$ miles.

Multiple choice maths equation reducing simple equations to simpler form solving linear equations solution of a linear equation in one variable

If $\cfrac{37}{4\sqrt{j}-19} = \cfrac{37}{17}$, then find the value of $j$.

  1. $64$
  2. $72.25$
  3. $81$
  4. $90.25$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Given, $\dfrac {{ 37 }}{{ (4\sqrt { j }  }-19)}={ 37 }/{ 17 }$

Since the numerators are equal, we can equate the denominators.
$\Rightarrow { (4\sqrt { j }  }-19)={ 17 }$
$\Rightarrow 4\sqrt { j } =36$
$\Rightarrow \sqrt { j } =9$
So, $j=81$
Hence, option C is correct.

Multiple choice maths equation reducing simple equations to simpler form solving linear equations solution of a linear equation in one variable

If $\displaystyle \frac{a-b}{b}=\frac{3}{7}$, which of the following must also be true?

  1. $\displaystyle \frac{a}{b}=-\frac{4}{7}$
  2. $\displaystyle \frac{a}{b}=\frac{10}{7}$
  3. $\displaystyle \frac{a+b}{b}=\frac{10}{7}$
  4. $\displaystyle \frac{a-2b}{b}=-\frac{11}{7}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Given: $\displaystyle \frac {a-b}{b}=\frac 37$

Separating denominators,

$\Rightarrow \displaystyle \frac ab -1=\frac 37$
$\Rightarrow \displaystyle \frac ab=\frac 37+1=\frac {10}{7}$
$\Rightarrow \dfrac {a}{b}=\dfrac {10}{7}$
Therefore, option B is correct.