Tag: maths

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Questions Related to maths

Multiple choice maths parts and whole multiplication of a fraction multiplication of a fractions multiplication of fraction finding the whole when a fraction is given

Reciprocal of $\displaystyle \frac{7}{5}$

  1. $\displaystyle 1\frac{2}{5}$
  2. $\displaystyle \frac{5}{7}$
  3. $\displaystyle 5\frac{2}{3}$
  4. $\displaystyle \frac{12}{5}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation
In the reciprocal, numerator and denominator interchanges
So, the reciprocal of $\dfrac{7}{5}$ is $\dfrac{5}{7}$.
Hence, the answer is $\dfrac{5}{7}$.
Multiple choice maths parts and whole multiplication of a fraction multiplication of a fractions multiplication of fraction finding the whole when a fraction is given

Find the product:

$\displaystyle 1\frac{1}{3}\times 3\frac{1}{4}\times \frac{7}{8}$

  1. $\displaystyle 3\frac{18}{24}$
  2. $\displaystyle 2\frac{19}{24}$
  3. $\displaystyle 3\frac{19}{24}$
  4. $\displaystyle 2\frac{18}{24}$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let's first convert the mixed fraction into simple fraction $\dfrac{4}{3},$ $\dfrac{13}{4},$ $\dfrac{7}{8}$ .

The product is 
$\dfrac{4}{3} \times \dfrac{13}{4}\times \dfrac{7}{8}=\dfrac{91}{24}$
This can also be written as $3\dfrac{19}{24}$.

Multiple choice maths parts and whole multiplication of a fraction multiplication of a fractions multiplication of fraction finding the whole when a fraction is given

If $\displaystyle 40-\frac{1}{5}\times $ ____ $= 0$, then the missing value is 

  1. $0$
  2. $\displaystyle \frac{1}{5} $
  3. $\displaystyle \frac{199}{5} $
  4. $200$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation
Let missing value is $x$

$40$ $-\dfrac{1}{5}\times x=0$

$40$ $=\dfrac{1}{5}\times x$

$x=200$

Hence, the answer is $200$.
Multiple choice maths principle of mathematical induction implications proofs in mathematics different forms of theoretical statements

Solve it:-
$\left( {p \to q} \right) \to [\left( { \sim p \to q} \right) \to q]$

  1. Tautology

  2. Contradiction

  3. Contingent

  4. Not statement
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
$Y=\left( p\longrightarrow q \right) \longrightarrow \left[ \left( \sim p\longrightarrow q \right) \longrightarrow q \right]$
Method : TRUTH TABLE [  ALWAYS PREFERABLE]

 $p$  $q$  $p\longrightarrow q$  $\left( \sim p\longrightarrow q \right) $  $\left[ \left( \sim p\longrightarrow q \right) \longrightarrow q \right]$  $Y$
 $1$  $0$  $0$  $1$  $1$ $1$ 
 $1$  $1$  $1$  $1$  $1$  $1$
 $0$  $0$  $1$  $0$  $1$  $1$
 $0$  $1$  $1$  $1$  $1$  $1$
As the result is always TRUE $\left(i.e. 1\right)$;
$\left( p\longrightarrow q \right)\longrightarrow \left[ \left( \sim p\longrightarrow q \right) \longrightarrow q \right]$ is Tautology.

A. Tautology



















Multiple choice maths principle of mathematical induction implications proofs in mathematics different forms of theoretical statements

Let $p$ and $q$ be two propositions given by
$p$ : The sky is blue.
$q$ : The milk is white.
Then $p\wedge q$ will be

  1. The sky if blue or milk is white

  2. The sky is blue and milk is white

  3. The sky is white and milk is blue

  4. If the sky is blue then milk is white
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

$p \wedge q$ means statement p and q
=> The sky is blue and  milk is white.