Questions Related to maths

Multiple choice maths introduction of probability theory types of events some more terms in probability events and its algebra

A bag contains $4$ red balls, $6$ blue balls and $3$ black balls. A ball is draw at random from the bag. What is the probability that the ball drawn is not blue?

  1. $\displaystyle\frac{6}{13}$
  2. $\displaystyle\frac{3}{13}$
  3. $\displaystyle\frac{7}{13}$
  4. None

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Total no. of balls$=4+6+3=13$

Total no. of ways one ball out of 7,n(S)$=13C _1$
No.of ways of drawing 1 ball,none of then is blue,n(E)$=13- 6=7C _1$
$\therefore  probability=\dfrac{n(E)}{n(S)}=\frac{7}{13}$

Multiple choice maths introduction of probability theory types of events some more terms in probability events and its algebra

The probability of a certain event is 

  1. $0$
  2. $1$
  3. greater than $1$
  4. less than $0$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation
An event which always happens is called a sure event or a certain event. So the probability of a certain event is $1$. 
For example, when we throw a die, then the event "getting a number less than $7$" is a certain event.
Multiple choice maths introduction of probability theory types of events some more terms in probability events and its algebra

If P(E) = 0 then E is a/an

  1. sure event

  2. impossible event

  3. equally likely event

  4. none of these

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

$P(E)=\frac{number  of   outcomes  favorable}{Total   numbers  of  possible  outcomes}$

If P(E)=0 then the event is called impossible event.
For example -
When a dice is thrown the possible outcomes are 1,2,3,4,5 and 6.
then  the probability is to getting the number 7  in a single throw of a dice is 0 then this is called impossible event.
$P(E)=\frac{0}{6}=0$    

Multiple choice maths introduction of probability theory types of events some more terms in probability events and its algebra

Which one of the following is an impossible event?

  1. Rolling a die to get $4$
  2. Tossing a coin to get tail

  3. Choosing $4$ face cards of spades.
  4. Rolling a die for $7$.
Reveal answer Fill a bubble to check yourself
C,D Correct answer
Explanation

Choosing $4$ face cards in spades as well as rolling a die for $7$ are both impossible events.
The number of face cards in spades $= 3$ (king, queen, jack)

Rolling a die gives outcomes as $= {1, 2, 3, 4, 5, 6}$.

Multiple choice maths introduction of probability theory types of events some more terms in probability events and its algebra

Choosing a queen from a deck of cards is an example of

  1. compound event

  2. complementary event

  3. simple event

  4. impossible event

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Choosing a queen from a deck of cards is an example of compound event.
Because the total number of card $= 52$
Choosing a queen card $= 4$ (spade, diamond, heart, club)
So, more than one element of the sample space in the set representing an event, then this event is called a compound event.