Tag: maths

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Questions Related to maths

Multiple choice maths use of brackets order operations and algebra using brackets in algebraic expressions order of operations

$\frac{1}{3}(-2p+6q-9r)-\frac{1}{6}(-4p -18q +24r) = $

  1. $-\frac{4}{3}p$

  2. 5q

  3. -7r

  4. 5q-7r
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

$\frac{1}{3}(-2p+6q-9r)-\frac{1}{6}(-4p -18q +24r) = \frac{1}{3}(-2p+6q-9r)-\frac{1}{3}(-2p -9q +12r) $
$=\frac{1}{3} [\left (-2p+6q-9r)-(-2p -9q +12r) \right]$
$=\frac{1}{3} (-2p + 6q - 9r + 2p + 9q -12r)$
$=\frac{1}{3} (15q - 21r)$
$=(5q - 7r)$

Multiple choice maths use of brackets order operations and algebra using brackets in algebraic expressions order of operations

$ \frac{3}{4}(a+y) \left [ y + a - \frac{1}{3} \left ( y + a -\frac{1}{4}(a+y) \right )\right ]$

  1. $(a+y)^{2}$
  2. $\frac{3a}{16}$
  3. $\frac{9}{16}(a+y)^{2}$

  4. 1
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

$ \frac{3}{4}(a+y) \left [ y + a - \frac{1}{3} \left ( y + a -\frac{1}{4}(a+y) \right )\right ]$
= $ \frac{3}{4}(a+y) \left [ y + a - \frac{1}{3} \left (\frac{3}{4}(a+y) \right) \right ]$
= $ \frac{3}{4}(a+y) \left [ y + a - \frac{1}{4}(a+y)\right ]$
= $ \frac{3}{4}(a+y) \left [ \frac{3}{4}(a+y)\right ]$
= $ \frac{9}{16}(a+y)^2$

Multiple choice maths place value, ordering and rounding order operations and algebra using brackets in algebraic expressions order of operations

In a class, there are 18 boys who are over 160 em tall. If these constitute three-fourths of the boys and the total number of boys is two-third of the total number of students in the class, what is the number of girls in the class?

  1. 6

  2. 12

  3. 18

  4. 24
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Total number of boys $\displaystyle=18\div\frac{3}{4}=24$

Total number of students $\displaystyle=24\times\frac{3}{2}=36$

$\therefore$ Number of girls $=36-24=12$

Multiple choice maths place value, ordering and rounding order operations and algebra using brackets in algebraic expressions order of operations

$9+\cfrac { 3 }{ 4 } +7+\cfrac { 2 }{ 17 } -\left( 9+\cfrac { 1 }{ 15 }  \right) =$?

  1. $7+\cfrac { 719 }{ 1020 } $
  2. $9+\cfrac { 817 }{ 1020 } $
  3. $9+\cfrac { 719 }{ 1020 } $
  4. $7+\cfrac { 817 }{ 1020 } $

  5. None of these
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Given the sum $=9+\cfrac { 3 }{ 4 } +7+\cfrac { 2 }{ 17 } -\left( 9+\cfrac { 1 }{ 15 }  \right) $
$=(9+7-9)+\left( \cfrac { 3 }{ 4 } +\cfrac { 2 }{ 17 } -\cfrac { 1 }{ 15 }  \right) $
$=7+\cfrac { 765+120-68 }{ 1020 } $
$=7+\cfrac { 817 }{ 1020 } $

Multiple choice maths how much does it weigh? define weight and units of weight conversion of length measurement (length) basic operations with same units operations involving units of length

${\rm{1}}\,{\rm{g/c}}{{\rm{m}}^{\rm{3}}}$ is equal to____________.

  1. ${\rm{1}}\,{\rm{kg/c}}{{\rm{m}}^{\rm{3}}}$
  2. ${\rm{1}}{{\rm{0}}^3}\,{\rm{kg/}}{{\rm{m}}^{\rm{3}}}$
  3. ${\rm{1}}{{\rm{0}}^{ - 2}}\,{\rm{kg/c}}{{\rm{m}}^{\rm{3}}}$
  4. ${\rm{1}}{{\rm{0}}^{ - 3}}\,{\rm{kg/c}}{{\rm{m}}^{\rm{3}}}$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

We have,

$1\ g/cm^3$

Since,
$1000\ g=1\ kg$
$1\ g=10^{-3} \ kg$

So,

$1\ g/cm^3 =10^{-3}\ kg/cm^3$

Hence, this is the answer.

Multiple choice maths how much does it weigh? define weight and units of weight conversion of length measurement (length) basic operations with same units operations involving units of length

A spherical bowl  with diameter  $24$ m. How much it weigh  (approx. in kg)  (if $1$ gm $= 1$ cubic cm).

  1. $7216473.6 kg$
  2. $216473.6 kg$
  3. $721473.6 kg$

  4. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Volume of sphere = 4/3 pi r^3 = 4/3 pi 12^3 = 7238.2 cubic m = 7238230000 cubic cm. Weight in kg = 7238230000 kg. This matches option A closest.

Multiple choice maths how much does it weigh? define weight and units of weight conversion of length measurement (length) basic operations with same units operations involving units of length

Weight of $1$ mango is $250$ gms. Then identify the weight of $16$ mangos. (Write your answer in kilograms)

  1. $1$
  2. $2$
  3. $3$
  4. $4$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation
the weight of $1$ mango $=250 $  $gram$

weight of $16$ mangoes $=250 \times 16 = 4000$  $gram$

We know that

$1$  $kg =1000$  $gram$

$1$  $gram =\dfrac1{1000}$  $kg$

Given That, we have to convert $4000$  $gram$  to   $kg$

$4000$  $gm =\dfrac{1}{1000} \times 4000$  $kg$

                    $ =\dfrac{4000}{1000} $  $kg$

                   $=4$  $kg$

So, option $D$ is correct