Tag: maths

Questions Related to maths

Construct a parallelogram $ABCD$, with adjacent sides $AB=4$ cm, $BC = 5$ cm and height corresponding to  (base) $BC = 3.5$ cm. Find the area of parallelogram ABCD in sq. cm.

  1. $21.5$

  2. $14.5$

  3. $17.5$

  4. None of these


Correct Option: C
Explanation:

Area of parallelogram ABCD

$=BC\times \left( altitude\quad associated\quad with\quad BC \right) \ =5\times 3.5\ =17.5$
So, correct answer is option C.

State whether the following statement is True or False.
The length of diagonal of rectangle is more than any side of rectangle.

  1. True

  2. False


Correct Option: A
Explanation:

Length diagonal having sides $a$ and $b$ $=\sqrt{a^2+b^2}$ 

Which is greater than any of its side that is $a$ and $b$.

Construct a rectangle $ABCD$, where $AB=10$ cm and $BC=8$ cm.Steps for its construction is given in a jumbled form. Identify its correct sequence.
1) Join these cuts with a line $CD$ and rectangle $ABCD$ is formed
2) Draw a straight line $AB$ of length $10$ cm
3) Draw perpendicular lines at $A$ and $B$ using protractor.
4) Using compass cut arc at the perpendicular from $A$ and $B$ of lengths $8$ cm

  1. $2,4,3,1$

  2. $2,3,4,1$

  3. $3,2,4,1$

  4. $3,4,2,1$


Correct Option: B
Explanation:

Correct sequence for constructing rectangle $ABCD$ is:

Draw a straight line $AB$ of $10 $ cm.
Draw perpendicular lines at $A$ and $B$ using proctor.
Using compass cut arc at the perpendicular from $A$ and $B$ of lengths $8$ cm.
Join these cuts with a line $CD$ and rectangle $ABCD$ is formed.
Correct sequence is $2,3,4,1$.

Let $ABCD$ be a square in which $A$ lies on the positive y-axis and $B$ lies on the positive x-axis. If $D$ is the point $(12, 17)$ the coordinates of $C$ are.

  1. $(17, 12)$

  2. $(17, 5)$

  3. $(14, 16)$

  4. $(15, 3)$


Correct Option: A

Construct a parallelogram $ABCD$ with $AB=24$ cm and $AD=16$ cm. The distance between AB and DC is $10$ cm. Find the distance between AD and BC.

  1. $25 $ cm

  2. $15 $ cm

  3. $13 $ cm

  4. None of these


Correct Option: B
Explanation:

The distance between AB and DC is the height (DE).
Area of the parallelogram ABCD = base x height = $24\times 10$ = $240$ sq cm
This is also the area of the same parallelogram with AD as the base and AH as the height.
height= $13$ width= $15$
Area of ABCD = ADx AH = $16 \times AH$
But area = $240$sqcm
I.e. AH = $\dfrac{240}{16} = 15$ cm

Simplify : $4 \times 4 - 2 \times 3 + 16 + 4 =$

  1. $20$

  2. $13/2$

  3. $30$

  4. None of these


Correct Option: C
Explanation:
$ 4\times 4-2\times 3+16+4 $
Using BODMAS Rule (BBracket, O of D Diviion,
M Multiplication, A Addition, S Subtraction) we get 
$ = 16-6+16+4 $
$ = 16-6+20 $
$ = 36-6 $
$ = 30 $ 

Divide $4\ kg\ 64\ g$ by $4$.

  1. $1.16\ kg$

  2. $10.16\ kg$

  3. $1.016\ kg$

  4. $101.6\ kg$


Correct Option: C
Explanation:

$1\ \ kg=1000g$

$\Rightarrow 1\ \ g=\dfrac{1}{1000}\ \ kg$
$4\ \ kg\ \ 64\ \ g=4+\dfrac{64}{1000}=4.064\ \ kg$
$\dfrac{4.064}{4}=1.016\ \ kg$
Option $C$ is correct.

Vineet packed $\dfrac {3}{4} kg$ of sugar each into $42$ plastic bags. Find the total weight of sugar Vineet packed.

  1. $34.5\ kg$

  2. $3.45\ kg$

  3. $31.5\ kg$

  4. $345\ kg$


Correct Option: C
Explanation:

Weight of sugar in $1\ bag = \dfrac {3}{4} kg$
$\therefore$ Weight of sugar in $42$ bags
$= \left (\dfrac {3}{4}\times 42\right ) kg = \dfrac {63}{2} kg = 31.5\ kg$.

What is $2:15+2:00$ in minutes and hours?

  1. $2$ hrs $15$ minutes

  2. $2$ hrs $45$ minutes

  3. $4$ hrs $45$ minutes

  4. $4$ hrs $15$ minutes


Correct Option: D
Explanation:

$2:15+2:00$

$=4:15$
So it is $4$ hours and $15$ minutes.

What is $3:13 A.M.+1:15 A.M. =$ ?

  1. $4:28 A.M.$

  2. $3:28 A.M.$

  3. $5:08A.M.$

  4. $1:15A.M.$


Correct Option: A
Explanation:

$3:13 A.M.+1:15A.M.$

$=4:28 A.M.$
Option $A$ is correct.