Tag: maths

Questions Related to maths

If the exponent of a negative integer is even then the result is a ............ integer.

maths indices negative indices law of indices laws of indices

  1. Positive

  2. Negative

  3. 0

  4. None

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Correct Option: A
Explanation:

  If the exponent of a negative integer is even, then the result is a $positive$ integer.

$\Rightarrow$  $(-2)^{4}=(-2)\times (-2)\times (-2)\times(-2)=16$
$\Rightarrow$  Here, $-2$ is negative base and $4$ is even power.
$\Rightarrow$  Then result  $16$ is a positive integer.

Evaluate : $(-4)^{-2}$---

maths indices negative indices law of indices laws of indices

  1. $\displaystyle \frac{1}{-16}$

  2. $\displaystyle \frac{1}{16}$

  3. $-16$

  4. $16$

Show answer
Correct Option: B
Explanation:
$(-4)^{-2}=\dfrac{1}{(-4)^2}$            $\because a^{-m}=\dfrac{1}{a^m}$

$=\dfrac{1}{-4*-4}$

$=\dfrac1{16}$

$\therefore(-4)^{-2}=\dfrac1{16}$

Which of the following has an exponent with negative index?

maths indices negative indices law of indices laws of indices

  1. $-3^{4}$

  2. $4^{3}$

  3. $\dfrac {1}{3^{4}}$

  4. $-3$

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Correct Option: C
Explanation:

$\dfrac {1}{3^{4}} = 3^{-4}$

$\therefore \dfrac {1}{3^{4}}$ has a negative index.
So, option $C$ is correct.

Simplify: $1 \div 7 \div 7$

maths indices negative indices law of indices laws of indices

  1. $7^{-2}$

  2. $7^{-1}$

  3. $0.7$

  4. $0.777$

Show answer
Correct Option: A
Explanation:

$1 \div 7 \div 7 = \dfrac 17 \div 7 = \dfrac 17 \times \dfrac 17$


$=\dfrac {1}{7^2} = 7^{-2}$

So, option $A$ is correct.

Which of the following has a negative index?

maths indices negative indices law of indices laws of indices

  1. ${ x }^{ 5 }$

  2. $\dfrac { 1 }{ x } $

  3. ${ (x) }^{ \tfrac { 3 }{ 2 } }$

  4. ${ (-x) }^{ \tfrac { 3 }{ 2 } }$

Show answer
Correct Option: B
Explanation:

$\dfrac{1}{x} = x^{-1}$. Index of $x$ is $(-1)$, which is negative.


Hence, option $B$ is correct

Which of the following has a negative index?

maths indices negative indices law of indices laws of indices

  1. $ \dfrac { 1 }{ { x }^{ -3 } } $

  2. ${ x }^{ 3 }$

  3. ${ -x }^{ 3 }$

  4. $\dfrac { 1 }{ { x }^{ 3 } } $

Show answer
Correct Option: D
Explanation:

$\dfrac{1}{x^3}=x^{-3}$ . Index of $x$ is  $(-3)$, which is negative.


Hence, option $D$ is correct.

Which of the following has a negative index?

maths indices negative indices law of indices laws of indices

  1. $\dfrac { 1 }{ { x }^{ 2 } } $

  2. ${ (x) }^{ \tfrac { 1 }{ 4 } }$

  3. ${ (-x) }^{ 2 }$

  4. $\dfrac { 1 }{ { x }^{ -2 } } $

Show answer
Correct Option: A
Explanation:

$\dfrac { 1 }{ { x }^{ 2 } } $ = ${ x }^{ -2 }$
Thus ${ x }^{ -2 }$ has a negative index
Therefore option $A$ is the correct answer.

Which of the following has a negative index?

maths indices negative indices law of indices laws of indices

  1. ${ (x) }^{ \tfrac{ 1 }{4 } }$

  2. ${ (x) }^{ \tfrac { 2 }{ 3 } }$

  3. $\dfrac { 1 }{ { x }^{ 2 } } $

  4. ${ (-x) }^{\tfrac { 2 }{ 3 } }$

Show answer
Correct Option: C
Explanation:
Option A has positive index i.e. $\dfrac {1}{4}$.
Option B also has positive index i.e., $\dfrac {2}{3}$
In option C, $\dfrac{1}{x^2} = x^{-2}$.  
Index of $x$ is $(-2)$, which is negative.
Hence, option C is correct

If $\dfrac {p}{q} = \left (\dfrac {2}{3}\right )^{3} \div \left (\dfrac {3}{2}\right )^{-3}$, then the value of $\left (\dfrac {p}{q}\right )^{10}$ is _______.

maths indices negative indices law of indices laws of indices

  1. $1$

  2. $0$

  3. $-1$

  4. Cannot be determined

Show answer
Correct Option: A
Explanation:
Given, $\dfrac {p}{q} = \left (\dfrac {2}{3}\right )^{3} \div \left (\dfrac {3}{2}\right )^{-3}$
We see that, $\left (\dfrac{3}{2}\right )^{-3}$=$\left (\dfrac{2}{3}\right)^{3}$
So, $\left (\dfrac{2}{3}\right)^{3}$ / $\left (\dfrac{2}{3}\right)^{3}$ $= 1$ 
Thus, $\left(\dfrac {p}{q}\right)^{10}=1$
Hence, A is the right answer.

$\left { \left (\dfrac {3}{4}\right )^{-1} - \left (\dfrac {1}{4}\right )^{-1}\right }^{-1} = ?$

maths indices negative indices law of indices laws of indices

  1. $\dfrac {3}{8}$

  2. $\dfrac {-3}{8}$

  3. $\dfrac {8}{3}$

  4. $\dfrac {-8}{3}$

Show answer
Correct Option: B
Explanation:

We need to find value of $\left { \left (\dfrac {3}{4}\right )^{-1} - \left (\dfrac {1}{4}\right )^{-1}\right }^{-1} $
It can be written as $\left (\dfrac {4}{3} - 4\right)^{-1}$ $=$ $\left (\dfrac {-8}{3}\right)^{-1}$ $=$ $-\dfrac {3}{8}$