Mathematics
Trigonometric Identities and Equations
223 Questions
Solve a variety of questions based on trigonometric identities and mathematical equations. Key areas covered include double angle formulas, the law of sines, and quadrant angles. This material helps students preparing for advanced mathematics exams, UPSC, and state public service commissions.
Double angle formulasLaw of sinesTrigonometric quadrantsLaplace transformSecant functionTaylor series
Trigonometric Identities and Equations Questions
What is the product-to-sum identity for sine and cosine?
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sin(x)cos(y) = (sin(x+y) + sin(x-y))/2
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sin(x)cos(y) = (sin(x+y) - sin(x-y))/2
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sin(x)cos(y) = (cos(x+y) + cos(x-y))/2
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sin(x)cos(y) = (cos(x+y) - cos(x-y))/2
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Correct answer
Explanation
The product-to-sum identity for sine and cosine is sin(x)cos(y) = (sin(x+y) + sin(x-y))/2.
Which of the following is the product-to-sum identity for cosine and sine?
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cos(x)sin(y) = (sin(x+y) - sin(x-y))/2
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cos(x)sin(y) = (sin(x+y) + sin(x-y))/2
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cos(x)sin(y) = (cos(x+y) + cos(x-y))/2
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cos(x)sin(y) = (cos(x+y) - cos(x-y))/2
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Correct answer
Explanation
The product-to-sum identity for cosine and sine is cos(x)sin(y) = (sin(x+y) - sin(x-y))/2.
What is the power-reducing identity for sine?
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sin^2(x) = (1 - cos(2x))/2
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sin^2(x) = (1 + cos(2x))/2
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sin^2(x) = (1 - sin(2x))/2
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sin^2(x) = (1 + sin(2x))/2
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Correct answer
Explanation
The power-reducing identity for sine is sin^2(x) = (1 - cos(2x))/2.
Which of the following is the power-reducing identity for cosine?
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cos^2(x) = (1 + cos(2x))/2
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cos^2(x) = (1 - cos(2x))/2
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cos^2(x) = (1 + sin(2x))/2
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cos^2(x) = (1 - sin(2x))/2
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Correct answer
Explanation
The power-reducing identity for cosine is cos^2(x) = (1 + cos(2x))/2.
Brahmagupta's formula for calculating the sine of an angle is given by:
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$\sin A = \frac{\sin \frac{A}{2}}{\cos \frac{A}{2}}$
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$\sin A = \frac{\sin A}{\cos A}$
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$\sin A = \frac{\tan A}{\sec A}$
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$\sin A = \frac{\cos A}{\sec A}$
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Correct answer
Explanation
Brahmagupta's formula for sine is derived from the half-angle formula for sine.
Brahmagupta's formula for calculating the cosine of an angle is given by:
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$\cos A = \frac{\cos \frac{A}{2}}{\sin \frac{A}{2}}$
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$\cos A = \frac{\cos A}{\sin A}$
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$\cos A = \frac{\tan A}{\csc A}$
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$\cos A = \frac{\sin A}{\csc A}$
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Correct answer
Explanation
Brahmagupta's formula for cosine is derived from the half-angle formula for cosine.
Brahmagupta's formula for calculating the secant of an angle is given by:
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$\sec A = \frac{1}{\cos A}$
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$\sec A = \frac{\cos A}{\sin A}$
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$\sec A = \frac{\sin A}{\cos A}$
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$\sec A = \frac{\cos A}{\sec A}$
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Correct answer
Explanation
Brahmagupta's formula for secant is derived from the definition of secant.
Brahmagupta's formula for calculating the sine of the sum of two angles is given by:
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$\sin(A + B) = \sin A \cos B + \cos A \sin B$
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$\sin(A + B) = \sin A \sin B + \cos A \cos B$
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$\sin(A + B) = \tan A \sec B + \cot A \csc B$
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$\sin(A + B) = \cos A \sec B + \sin A \csc B$
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Correct answer
Explanation
Brahmagupta's formula for the sine of the sum of two angles is derived from the angle addition formula for sine.
Brahmagupta's formula for calculating the cosine of the sum of two angles is given by:
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$\cos(A + B) = \cos A \cos B - \sin A \sin B$
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$\cos(A + B) = \cos A \sin B + \sin A \cos B$
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$\cos(A + B) = \tan A \sec B - \cot A \csc B$
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$\cos(A + B) = \sin A \sec B + \cos A \csc B$
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Correct answer
Explanation
Brahmagupta's formula for the cosine of the sum of two angles is derived from the angle addition formula for cosine.
Brahmagupta's formula for calculating the cotangent of the sum of two angles is given by:
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$\cot(A + B) = \frac{\cot A \cot B - 1}{\cot A + \cot B}$
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$\cot(A + B) = \frac{\cot A \cot B + 1}{\cot A - \cot B}$
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$\cot(A + B) = \frac{\sin A - \sin B}{\cos A - \cos B}$
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$\cot(A + B) = \frac{\cos A - \cos B}{\sin A - \sin B}$
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Correct answer
Explanation
Brahmagupta's formula for the cotangent of the sum of two angles is derived from the angle addition formula for cotangent.
Brahmagupta's formula for calculating the sine of the difference of two angles is given by:
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$\sin(A - B) = \sin A \cos B - \cos A \sin B$
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$\sin(A - B) = \sin A \sin B + \cos A \cos B$
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$\sin(A - B) = \tan A \sec B - \cot A \csc B$
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$\sin(A - B) = \cos A \sec B + \sin A \csc B$
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Correct answer
Explanation
Brahmagupta's formula for the sine of the difference of two angles is derived from the angle difference formula for sine.
Brahmagupta's formula for calculating the cosine of the difference of two angles is given by:
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$\cos(A - B) = \cos A \cos B + \sin A \sin B$
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$\cos(A - B) = \cos A \sin B - \sin A \cos B$
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$\cos(A - B) = \tan A \sec B + \cot A \csc B$
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$\cos(A - B) = \sin A \sec B + \cos A \csc B$
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Correct answer
Explanation
Brahmagupta's formula for the cosine of the difference of two angles is derived from the angle difference formula for cosine.
What is the value of the sine of 30 degrees according to Aryabhata?
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Correct answer
Explanation
Aryabhata calculated the sine of 30 degrees to be 0.5, which is an accurate approximation.