Mathematics
Trigonometric Identities and Equations
223 Questions
Solve a variety of questions based on trigonometric identities and mathematical equations. Key areas covered include double angle formulas, the law of sines, and quadrant angles. This material helps students preparing for advanced mathematics exams, UPSC, and state public service commissions.
Double angle formulasLaw of sinesTrigonometric quadrantsLaplace transformSecant functionTaylor series
Trigonometric Identities and Equations Questions
Find all solutions of the equation (\tan^2\theta + \sec\theta - 1 = 0) in the interval ([0, 2\pi)).
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\(\theta = \frac{\pi}{4}, \frac{3\pi}{4}\)
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\(\theta = \frac{\pi}{3}, \frac{2\pi}{3}\)
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\(\theta = \frac{\pi}{6}, \frac{5\pi}{6}\)
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\(\theta = 0, \pi\)
A
Correct answer
Explanation
Using the identity (\sec^2\theta = 1 + \tan^2\theta), we can rewrite the equation as (1 + \tan^2\theta + \tan\theta - 1 = 0). Simplifying, we get (\tan^2\theta + \tan\theta = 0). Factoring, we find (\tan\theta(\tan\theta + 1) = 0). Solving each factor separately, we find (\tan\theta = 0) or (\tan\theta = -1). Using the unit circle or reference angles, we find the solutions (\theta = \frac{\pi}{4}, \frac{3\pi}{4}).
Solve the equation (\sin^2\theta + \cos^2\theta - \sin\theta - \cos\theta = 0) for (0 \le \theta \le 2\pi).
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\(\theta = \frac{\pi}{4}, \frac{3\pi}{4}\)
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\(\theta = \frac{\pi}{3}, \frac{2\pi}{3}\)
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\(\theta = \frac{\pi}{6}, \frac{5\pi}{6}\)
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\(\theta = 0, \pi\)
A
Correct answer
Explanation
Using the identity (\sin^2\theta + \cos^2\theta = 1), we can simplify the equation to (1 - \sin\theta - \cos\theta = 0). Rearranging, we get (\sin\theta + \cos\theta = 1). This suggests that (\sin\theta) and (\cos\theta) have the same sign. The only way this can happen is if both (\sin\theta) and (\cos\theta) are positive. Using the unit circle or reference angles, we find the solutions (\theta = \frac{\pi}{4}, \frac{3\pi}{4}).
Solve the equation (2\sin^2\theta - 3\sin\theta + 1 = 0) for (0 \le \theta \le 2\pi).
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\(\theta = \frac{\pi}{6}, \frac{5\pi}{6}\)
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\(\theta = \frac{\pi}{3}, \frac{2\pi}{3}\)
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\(\theta = \frac{\pi}{4}, \frac{3\pi}{4}\)
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\(\theta = 0, \pi\)
A
Correct answer
Explanation
Factoring the equation, we get ((2\sin\theta - 1)(\sin\theta - 1) = 0). Solving each factor separately, we find (\sin\theta = \frac{1}{2}) or (\sin\theta = 1). Using the unit circle or reference angles, we find the solutions (\theta = \frac{\pi}{6}, \frac{5\pi}{6}).
What is the value of (\sin 90^\circ) in Indian trigonometry?
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0
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1
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\(\frac{1}{2}\)
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\(\frac{\sqrt{2}}{2}\)
B
Correct answer
Explanation
In Indian trigonometry, the value of (\sin 90^\circ) is 1.
What is the value of (\cos 0^\circ) in Indian trigonometry?
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0
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1
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\(\frac{1}{2}\)
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\(\frac{\sqrt{2}}{2}\)
B
Correct answer
Explanation
In Indian trigonometry, the value of (\cos 0^\circ) is 1.
The reciprocal of the tangent of an angle is called the:
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Cosecant
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Secant
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Cotangent
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Cosine
C
Correct answer
Explanation
The cotangent of an angle is defined as the reciprocal of the tangent of the angle.
The trigonometric ratio that relates the length of the opposite side to the length of the hypotenuse is called the:
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Sine
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Cosine
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Tangent
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Secant
A
Correct answer
Explanation
The sine of an angle is defined as the ratio of the length of the opposite side to the length of the hypotenuse.
The trigonometric ratio that relates the length of the adjacent side to the length of the hypotenuse is called the:
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Sine
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Cosine
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Tangent
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Secant
B
Correct answer
Explanation
The cosine of an angle is defined as the ratio of the length of the adjacent side to the length of the hypotenuse.
The trigonometric ratio that relates the length of the hypotenuse to the length of the adjacent side is called the:
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Sine
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Cosine
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Tangent
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Secant
D
Correct answer
Explanation
The secant of an angle is defined as the ratio of the length of the hypotenuse to the length of the adjacent side.
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\(\frac{sin A}{a} = \frac{sin B}{b} = \frac{sin C}{c}\)
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\(\frac{sin A}{a} = \frac{cos B}{b} = \frac{tan C}{c}\)
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\(\frac{cos A}{a} = \frac{sin B}{b} = \frac{tan C}{c}\)
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\(\frac{cos A}{a} = \frac{cos B}{b} = \frac{sin C}{c}\)
A
Correct answer
Explanation
The sine rule states that in a triangle, the ratio of the sine of an angle to the length of the opposite side is the same for all angles.
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\(c^2 = a^2 + b^2 - 2ab cos C\)
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\(c^2 = a^2 + b^2 + 2ab cos C\)
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\(c^2 = a^2 - b^2 + 2ab cos C\)
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\(c^2 = a^2 - b^2 - 2ab cos C\)
A
Correct answer
Explanation
The cosine rule states that in a triangle, the square of the length of one side is equal to the sum of the squares of the lengths of the other two sides minus twice the product of the lengths of the other two sides and the cosine of the angle between them.
What is the double angle formula for sine?
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\(sin 2A = 2 sin A cos A\)
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\(sin 2A = sin A + sin A\)
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\(sin 2A = cos A + cos A\)
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\(sin 2A = 2 cos A sin A\)
A
Correct answer
Explanation
The double angle formula for sine states that (sin 2A = 2 sin A cos A).
What is the double angle formula for cosine?
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\(cos 2A = cos^2 A - sin^2 A\)
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\(cos 2A = cos A + cos A\)
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\(cos 2A = sin A + sin A\)
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\(cos 2A = 2 cos A sin A\)
A
Correct answer
Explanation
The double angle formula for cosine states that (cos 2A = cos^2 A - sin^2 A).
What is the half angle formula for sine?
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\(sin \frac{A}{2} = \pm \sqrt{\frac{1 - cos A}{2}}\)
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\(sin \frac{A}{2} = sin A + sin A\)
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\(sin \frac{A}{2} = cos A + cos A\)
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\(sin \frac{A}{2} = 2 sin A cos A\)
A
Correct answer
Explanation
The half angle formula for sine states that (sin \frac{A}{2} = \pm \sqrt{\frac{1 - cos A}{2}}).
What is the half angle formula for cosine?
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\(cos \frac{A}{2} = \pm \sqrt{\frac{1 + cos A}{2}}\)
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\(cos \frac{A}{2} = cos A + cos A\)
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\(cos \frac{A}{2} = sin A + sin A\)
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\(cos \frac{A}{2} = 2 cos A sin A\)
A
Correct answer
Explanation
The half angle formula for cosine states that (cos \frac{A}{2} = \pm \sqrt{\frac{1 + cos A}{2}}).