Quantitative Aptitude
Problems on Trains
989 Questions
Problems on Trains Questions
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$36$ km/hr
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$56$ km/hr
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$44$ km/hr
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$51$ km/hr
A
Correct answer
Explanation
Speed = distance / time = 140 m / 14 sec = 10 m/sec. To convert m/sec to km/hr, multiply by 18/5: 10 * (18/5) = 36 km/hr.
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$120$ km/hr
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$140$ km/hr
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$160$ km/hr
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$180$ km/hr
A
Correct answer
Explanation
Speed = distance / time = 125 / 3.75 = 33.33 m/s. Convert to km/hr: 33.33 * (18/5) = 120 km/hr.
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30 km/hr
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45 km/hr
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60 km/hr
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75 km/hr
C
Correct answer
Explanation
Total distance = 100 + 100 = 200 m. Time = 8 s. Relative speed = 200/8 = 25 m/s. Let speeds be v and 2v. 3v = 25 m/s, so v = 25/3 m/s. Faster train = 50/3 m/s. Convert to km/hr: (50/3) * (18/5) = 60 km/hr.
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$5\ seconds$
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$6\ seconds$
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$8\ seconds$
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$7\dfrac {1}{3}seconds$
B
Correct answer
Explanation
Because the man walks in the opposite direction, the relative speed is 60 + 6 = 66 km/hr, or 55/3 m/s. The time to cover the train's 110 m length is 110 รท (55/3) = 6 seconds.
D
Correct answer
Explanation
The train speed is 120 km/h = 120 * 5/18 = 100/3 m/s. The train crosses the platform in 24s, so total distance (train + platform) = (100/3) * 24 = 800m. Platform length = 800 - 320 = 480m. The man crosses the 480m platform in 4 minutes (240 seconds). Speed = 480 / 240 = 2 m/s.
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$54$ km/hr
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$60$ km/hr
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$72$ km/hr
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$36$ km/hr
B
Correct answer
Explanation
Relative speed = (150+100)m / 10s = 25 m/s = 90 km/h. Relative speed = v1 + v2 = 30 + v2 = 90. v2 = 60 km/h.
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$100$ m
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$125$ m
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$150$ m
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$200$ m
D
Correct answer
Explanation
Relative speed = 96 - 60 = 36 km/h = 36 * (5/18) = 10 m/s. Length = speed * time = 10 m/s * 20 s = 200 m.
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$8\ s$
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$4\ s$
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$2\ s$
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$6.17\ s$
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$\dfrac {32}{9}$
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$\dfrac {33}{7}$
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$\dfrac {40}{9}$
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$\dfrac {49}{9}$
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50 km/h
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55 km /h
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57 km/h
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60 km/h
B
Correct answer
Explanation
The relative speed is (v + 5) km/h. Convert 100 meters to 0.1 km and 6 seconds to 6/3600 hours. Relative speed = distance/time = 0.1 / (6/3600) = 0.1 * 600 = 60 km/h. Since the train and man move in opposite directions, the train speed is 60 - 5 = 55 km/h.
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$9\sec$
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$8\sec$
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$7\sec$
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$6\sec$
D
Correct answer
Explanation
Relative speed = 60 + 6 = 66 km/hr. Convert to m/s: 66 * (5/18) = 55/3 m/s. Time = Distance / Speed = 110 / (55/3) = 110 * 3 / 55 = 6 seconds.
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$260 m$
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$440 m$
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$500 m$
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$352 m$
C
Correct answer
Explanation
Speed = 78 km/hr = 78 * 5/18 = 65/3 m/s. Distance = Speed * Time = (65/3) * 60 = 1300 m. Tunnel length = Total distance - Train length = 1300 - 800 = 500 m.
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$75km/hour$
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$85km/hour$
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$95km/hour$
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$105km/hour$
B
Correct answer
Explanation
The trains cover a combined length of 250 m in 6 seconds, so their relative speed is 250/6 m/s = 150 km/h. Since they move in opposite directions, the second speed is 150 - 65 = 85 km/h.
A
Correct answer
Explanation
The train speed is 36 km/hr, which is 10 m/s. Passing a man in 10 seconds means the train length is 10 m/s * 10 s = 100 m. Passing a platform in 18 seconds means the total distance (train + platform) is 10 m/s * 18 s = 180 m, so the platform length is 80 m. Since 100 m > 80 m, the statement is true.
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$155$ m
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$165$ m
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$275$ m
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$180$ m
C
Correct answer
Explanation
Distance = Speed * Time = 5 m/s * 80 s = 400 m. This distance represents the length of the train plus the length of the bridge. Train length = 400 - 125 = 275 m.