Multiple choice

Two trains are running in the same directions at the speed of $60$ km/hr and $96$ km/hr. If the faster train passes a man in the slower train in $20$ seconds, then the length of the faster train is

  1. $100$ m
  2. $125$ m
  3. $150$ m
  4. $200$ m
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D Correct answer
Explanation

Relative speed = 96 - 60 = 36 km/h = 36 * (5/18) = 10 m/s. Length = speed * time = 10 m/s * 20 s = 200 m.

AI explanation

When two objects move in the same direction, the relative speed is the difference of their speeds: 96 km/hr - 60 km/hr = 36 km/hr. We convert this relative speed to meters per second by multiplying by 5/18, yielding 36 * 5/18 = 10 m/s. Using the formula Distance = Speed * Time, the length of the faster train is the relative speed multiplied by the passing time: 10 m/s * 20 s = 200 m. The length of the faster train is 200 m.

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