Quantitative Aptitude

Time, Speed and Distance

2,165 Questions
All Core formulas and unit conversion 441 Boats and streams effective speed 396 Relative speed, meetings, and overtaking 375 Average speed 362 Early and late arrival 321 Proportional relationships 202 Stoppage time per hour 35 Train and stationary or moving object crossing 17 Races and dead heats 16

Time, Speed and Distance Questions

Multiple choice maths unitary method time speed and distance problems involving speed word problems on speed time and distance time and distance word problems on simultaneous equations applications of simultameous equations unitary method idea of speed distance and time speed math time work and distance ratio and proportions linear equations in two variables maths

A cyclist, after riding a certain distance, stopped for half an hour to repair his bicycle, after which he completes the whole journey of 30km at half speed in 5 hours. If the breakdown had occurred 10 km farther off, he would have done the whole journey is 4 hours. Find where the breakdown occurred and his original speed.

  1. 5km/hr,10km

  2. 10km/hr,10km

  3. 10km/hr,5km

  4. 5km/hr,5km
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let original speed be v and distance to breakdown be x. The equations derived from the two scenarios (30km total) lead to v = 10 km/hr and x = 10 km.

Multiple choice ime speed and distance problems involving speed word problems on speed time and distance time and distance word problems on simultaneous equations applications of simultameous equations unitary method idea of speed distance and time speed math time work and distance ratio and proportions linear equations in two variables maths

The time taken by a person to cover 150 km was 2.5 hrs more than the time taken in the return journey. If he returned at a speed of 10km/hr more than the speed of going, what was the speed per hour in each direction?

  1. going speed =−30km/hr, returning=−20km/hr

  2. going speed =20km/hr, returning=30km/hr

  3. going speed =30km/hr, returning=40km/hr

  4. going speed =30km/hr, returning=20km/hr
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Letting the going speed be $v$, the returning speed is $v+10$. The time equation $150/v - 150/(v+10) = 2.5$ simplifies to $v^2 + 10v - 600 = 0$, yielding $v = 20$ km/hr going and 30 km/hr returning. Distractors either list incorrect speed combinations or physically impossible negative speeds.

Multiple choice time speed and distance problems involving speed word problems on speed time and distance time and distance word problems on simultaneous equations applications of simultameous equations unitary method idea of speed distance and time speed math time work and distance ratio and proportions linear equations in two variables maths

A train is running at a uniform speed of 60km/h. How much time it will take to cover a distance of 300km?

  1. 5 h

  2. 4.5 h

  3. 6 h

  4. 7 h
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

$$speed=\frac{distance}{time}$$ $$time=\frac{distance}{speed}$$ $$time=\frac{300}{60}h$$ $$time=5 hr$$

Multiple choice time speed and distance problems involving speed word problems on speed time and distance time and distance word problems on simultaneous equations applications of simultameous equations unitary method idea of speed distance and time speed math time work and distance ratio and proportions linear equations in two variables maths

Two boys P and Q walk at 6 km/hr and 6 km/hr respectively. If Q covers a certain distance in 10 minutes less than P. What is the time taken by Q to cover the same distance (in minutes)?

  1. 40

  2. 60

  3. 30

  4. 70
Reveal answer Fill a bubble to check yourself
A Correct answer
Multiple choice

In a cycling race, a cyclist maintains a constant speed of 30 km/h for 2 hours. What is the total distance covered by the cyclist?

  1. 60 km

  2. 90 km

  3. 120 km

  4. 150 km
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The total distance covered by the cyclist can be calculated using the formula: distance = speed * time. Plugging in the values, we get: distance = 30 km/h * 2 hours = 60 km.

Multiple choice

A runner completes a marathon in 3 hours and 30 minutes. If the runner's average speed is 10 km/h, what is the total distance of the marathon?

  1. 30 km

  2. 42 km

  3. 54 km

  4. 66 km
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The total distance of the marathon can be calculated using the formula: distance = speed * time. First, we need to convert the runner's time to hours: 3 hours and 30 minutes = 3.5 hours. Then, we can plug in the values: distance = 10 km/h * 3.5 hours = 42 km.

Multiple choice

A swimmer swims a distance of 1500 meters in 20 minutes. What is the swimmer's average speed in meters per second?

  1. 1.25 m/s

  2. 1.5 m/s

  3. 1.75 m/s

  4. 2 m/s
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The swimmer's average speed can be calculated using the formula: speed = distance / time. First, we need to convert the swimmer's time to seconds: 20 minutes = 1200 seconds. Then, we can plug in the values: speed = 1500 meters / 1200 seconds = 1.25 m/s.

Multiple choice

A train leaves New York at 10:00 AM and travels at a speed of 60 mph. Another train leaves Chicago at 11:00 AM and travels towards New York at a speed of 70 mph. If the distance between New York and Chicago is 1000 miles, at what time will the two trains meet?

  1. 1:00 PM

  2. 2:00 PM

  3. 3:00 PM

  4. 4:00 PM
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The relative speed of the two trains is 70 mph + 60 mph = 130 mph. Therefore, it will take (1000 miles) / (130 mph) = 7.69 hours for the two trains to meet. Since the first train leaves at 10:00 AM and the second train leaves at 11:00 AM, the two trains will meet at 10:00 AM + 7.69 hours = 2:00 PM.

Multiple choice

A train leaves Mumbai at 10:00 AM and travels at a speed of 60 miles per hour. Another train leaves Delhi at 11:00 AM and travels towards Mumbai at a speed of 70 miles per hour. If the distance between Mumbai and Delhi is 800 miles, at what time will the two trains meet?

  1. 2:00 PM

  2. 3:00 PM

  3. 4:00 PM

  4. 5:00 PM
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The first train travels for 1 hour before the second train leaves. Therefore, the second train has to cover a distance of 800 - 60 = 740 miles in order to meet the first train. The relative speed of the two trains is 70 + 60 = 130 miles per hour. Therefore, the two trains will meet in 740 / 130 = 6 hours. Since the second train leaves at 11:00 AM, the two trains will meet at 11:00 AM + 6 hours = 5:00 PM.

Multiple choice

A train leaves a station at 10:00 AM and travels at a speed of 60 kilometers per hour. Another train leaves the same station at 11:00 AM and travels in the same direction at a speed of 70 kilometers per hour. At what time will the second train overtake the first train?

  1. 12:00 PM

  2. 12:30 PM

  3. 1:00 PM

  4. 1:30 PM
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

To find the time when the second train overtakes the first train, we can calculate the time it takes for the second train to cover the distance between the two trains. The distance between the two trains is equal to the speed of the first train multiplied by the time difference between the two trains. Once we know the distance, we can divide it by the speed of the second train to find the time it takes for the second train to cover that distance.

Multiple choice

A train leaves a station at 10:00 AM and travels at a speed of 60 miles per hour. Another train leaves the same station at 11:00 AM and travels in the opposite direction at a speed of 70 miles per hour. At what time will the two trains be 300 miles apart?

  1. 12:00 PM

  2. 12:30 PM

  3. 1:00 PM

  4. 1:30 PM
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

To solve this problem, we can use the formula: Distance = Speed * Time. Let x be the time at which the two trains are 300 miles apart. The distance traveled by the first train is 60 * x, and the distance traveled by the second train is 70 * x, since they are traveling in opposite directions. The total distance between the two trains is 300 miles. Therefore, we can set up the equation: 60 * x + 70 * x = 300. Solving for x, we get x = 2. Therefore, the two trains will be 300 miles apart at 1:00 PM.

Multiple choice

A train travels from City A to City B, a distance of 200 miles, at a speed of 50 miles per hour. On the return trip, the train travels at a speed of 60 miles per hour. What is the average speed of the train for the round trip?

  1. 52 miles per hour

  2. 54 miles per hour

  3. 56 miles per hour

  4. 58 miles per hour
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

To find the average speed for the round trip, we need to calculate the total distance traveled and the total time taken. The total distance is 200 miles (from City A to City B) + 200 miles (from City B to City A) = 400 miles. The time taken for the first trip is 200 miles / 50 miles per hour = 4 hours. The time taken for the return trip is 200 miles / 60 miles per hour = 3.33 hours. The total time taken for the round trip is 4 hours + 3.33 hours = 7.33 hours. Therefore, the average speed for the round trip is 400 miles / 7.33 hours = 54.54 miles per hour, which is approximately 56 miles per hour.

Multiple choice

A train leaves Beijing at 10:00 AM and travels at a speed of 60 km/h. Another train leaves Shanghai at 11:00 AM and travels at a speed of 70 km/h. If the distance between Beijing and Shanghai is 1200 km, at what time will the two trains meet?

  1. 1:00 PM

  2. 2:00 PM

  3. 3:00 PM

  4. 4:00 PM
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

To find the time at which the two trains will meet, we can use the formula (t = \frac{d}{s_1 + s_2}), where (t) is the time, (d) is the distance, and (s_1) and (s_2) are the speeds of the two trains. Plugging in the values of (d = 1200) km, (s_1 = 60) km/h, and (s_2 = 70) km/h, we get (t = \frac{1200}{60 + 70} = \frac{1200}{130} = 9.23) hours. Since the first train leaves at 10:00 AM and the second train leaves at 11:00 AM, the two trains will meet at 10:00 AM + 9.23 hours = 7:18 PM.

Multiple choice

A train leaves a station at 10:00 AM and travels at a speed of 60 km/hr. Another train leaves the same station at 11:00 AM and travels in the same direction at a speed of 75 km/hr. At what time will the second train be 15 km ahead of the first train?

  1. 12:00 PM

  2. 12:30 PM

  3. 1:00 PM

  4. 1:30 PM
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The relative speed of the second train with respect to the first train is (\$75 - 60 = 15) km/hr. Therefore, the second train will be 15 km ahead of the first train in (\$15/15 = 1) hour. Since the second train leaves at 11:00 AM, it will be 15 km ahead of the first train at 11:00 AM + 1 hour = 12:00 PM + 30 minutes = 12:30 PM.