Quantitative Aptitude

Time, Speed and Distance

2,165 Questions
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Time, Speed and Distance Questions

Multiple choice maths surface area and volume of cube and cuboid length of the diagonal diagonal of cube and cuboid surface area of cubes and cuboids

Two cars are travelling along two roads which cross each other at right angles at $A$. One car is travelling towards A at $21\ kmph $ and the other is travelling towards $A$ at $28\ kmph$.If initially, their distance from $A$ are $1500\ km$ and $2100\ km$ respectively,then the nearest distance between them is ,

  1. $30$
  2. $45$
  3. $60$
  4. $75$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation
Nearest distance
$=\dfrac{2100-1500}{10}$
$\dfrac{600}{10}=60$







Multiple choice physics study of sound conditions for hearing echo echo reflection of sound and echo ultrasound and its applications

A man, standing between two cliffs, claps his hands and starts hearing a series of echoes at intervals of one second. If the speed of sound in air is $340ms^{-1}$, the distance between the cliffs is?

  1. $680$m
  2. $1700$m
  3. $340$m
  4. $1620$m
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let the distance between the two cliffs be d. Since, the man is standing midway between the two cliffs, then the distance of man from either end is $d/2$.
The distance travelled by sound (in producing an echo)
$2\times \displaystyle\frac{d}{2}=v\times t\Rightarrow d=340\times 1=340$m.

Multiple choice physics study of sound conditions for hearing echo echo reflection of sound and echo ultrasound and its applications

A boy shouts while standing in front of a hill. He hears an echo after $6s$. If the speed of sound  in air is $340 m/s$, what is the distance of the hill from the position of the body?

  1. $519 m$
  2. $1020 m$
  3. $2040 m$

  4. None
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let distance of hill from the position of the body be $d$.

Echo is heard after $6s$

Speed of sound, $v=340m/s$

So, $d=v \times {\dfrac{t}{2}}$
or, $d=340 \times {\dfrac{6}{2}}=1020m$

Multiple choice maths calculations and mental strategies 1 equations from statements forming equations from statements writing mathematical statements

A thief escaped from police custody. Since he was sprinter he could clock $40\ km/hr$. The police realized it after $3$ hr and started chasing him in the same direction at $50\ km/hr$. The police had a dog which could run at $60\ km/hr$. The dog could run to the thief and then return to the police and then would turn back towards the thief. If kept on doing so till the police caught the thief. Find the total distance travelled by the dog in the direction of the thief.

  1. $720 km$
  2. $600 km$
  3. $660 km$
  4. $360 km$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation
Speed of thief $=40 \  km \ per\ hr=v _{t}$
Speed of police $=50 \ km\ per\ hr=v _{p}$
Police started after 3hrs of start of thief
$50t=40t+40(3)$
$\therefore   t=12 hr$
Time taken by police to catch thief $=12 hr$
Distance travelled by dog $=12\times 60$
$=720 km$
$\Rightarrow$   Distance travelled by police + To and from distance by Dog $=720$
Distance travelled by police $=50\times 12$
$=600 km$
$\Rightarrow$   $600+2(\text{from distance by dog})=720$
"Fro" distance (distance from thief to police)="to"distance(distance from police to thief after once it returns)
$600+2(\text{'fro' distance by dog})=720$
$\therefore$ 'fro' distance $=60$
$\therefore$ Total distance towards thief $=600+'to"\ distance$
$=720-$ 'fro' distance
$=660 km$
Multiple choice maths calculations and mental strategies 1 equations from statements forming equations from statements writing mathematical statements

Two birds are flying in opposite directions over the edge of a circle-shaped forest of radius 4 km. Both start off from the same point simultaneously and both have to go to the same nest. Who reaches the nest first?
I. Speed of bird A is 60 km/hr and speed of bird B is 50 km/hr.
II. The nest is diametrically opposite to the starting point of the flight of the two birds, on the circumference of the forest.

  1. If the question can be answered by anyone of the statements alone, but cannot be answered by using the other statement alone.

  2. If the question can be answered by using either statement alone.

  3. If the question can be answered by using both the statements together, but cannot be answered by using either statement alone.

  4. If the question. cannot be answered even by using both the statements together.
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

In the problem statement, the distance is given. 
In the first statement, the speeds are given.
In the second statement, nothing substantial can be concluded.
Since information on the paths of flight is not given, we can not determine which bird reaches first. D,

Multiple choice maths calculations and mental strategies 1 equations from statements forming equations from statements writing mathematical statements

A person walks from his house at a speed of $4$ km/hr and reaches his schools $5$ minutes late. If his speed has been $5$ km/hr, he would have reached $10$ minutes earlier. The distance of the school from his house is

  1. $5$ km
  2. $6$ km
  3. $7$ km
  4. $8$ km
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let the correct time to reach the school be ‘t’ hrs.

Then,the time taken by the man when he wakes at a speed of $4km$ will be ‘t’ hrs+5 mins,

which is nothing but $(t+\dfrac{5}{60})$hrs.

And,the time taken by the man when he walks at 5km/hr will similarly be $(t-\dfrac{10}{60})$hours.

As the distance in both the cases is same,

$4(t+\dfrac{5}{60}$)hrs=$5(t-\dfrac{10}{60})$hrs

$4t+\dfrac{20}{60}$=$5t-\dfrac{50}{60}$

 Therefore$ t=\dfrac{70}{60}$=$\dfrac{7}{6}$hrs

Actual distance=$4(t+\dfrac{5}{60})$

=  $4(\dfrac{70}{60}+\dfrac{5}{60})$

=$4\times \dfrac{75}{60}$=$5kms.$

Multiple choice maths ways to multiply and divide mental multiplication multiplication methods multiplication of numbers

Suresh travelled 1200 km by air which form (2/5) of his trip. One third of the whole trip, he travelled by car and the rest of the journey he performed by train. Find the distance travelled by train. Also, find the speed of the train if the time taken for the train to travel the whole distance is 8 hrs

  1. 1600 km, 350 km/hr

  2. 800 km, 375 km/hr

  3. 1800 km, 300 km/hr

  4. 480 km, 380 km/hr
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Suresh travelled 1200 km by air which form (2/5) of his trip. 
Then total distance of journey=$\frac{5}{2}\times 1200=3000 km$
Suresh travelled $\frac{1}{3}$of journey by car =$\frac{1}{3}\times 3000=1000 km$
Then suresh travelled distance by train =3000-1200-1000=800 km
If whole journey by train in 8 hours 
So speed of train=$\frac{3000}{8}$=375 km/Hr

Multiple choice

Distance= 45km, Time= 5km/hm, Speed= ?

  1. 45km

  2. 5km

  3. 50km

  4. 9km
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Speed is distance divided by time. 45 km / 5 km/h is not the correct way to find speed; however, if the input meant 45km distance and 5 hours time, the speed would be 9 km/h.