Quantitative Aptitude

Time, Speed and Distance

2,165 Questions
All Core formulas and unit conversion 441 Boats and streams effective speed 396 Relative speed, meetings, and overtaking 375 Average speed 362 Early and late arrival 321 Proportional relationships 202 Stoppage time per hour 35 Train and stationary or moving object crossing 17 Races and dead heats 16

Time, Speed and Distance Questions

Multiple choice

A boat has a speed of 6 km/h in still water covers 1 km upstream path in 20 minutes. How much distance it could cover in 1 hour 30 minutes in downstream? शांत पानी में एक नाव की गति 6 किमी/घंटा है, जो 20 मिनट में धारा के प्रतिकूल 1 किमी की दूरी तय करती है। धारा के अनुकूल यह 1 घंटा 30 मिनट में कितनी दूरी तय कर सकती है?

  1. 12 km 12 किमी

  2. 13.5 km 13.5 किमी

  3. 15 km 15 किमी

  4. 14 km 14 किमी

  5. None of these इनमें से कोई नहीं
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Speed in still water = 6 km/h. Upstream: 1 km in 20 min = 3 km/h. Upstream speed = boat - stream = 6 - stream = 3, so stream = 3 km/h. Downstream speed = 6 + 3 = 9 km/h. In 1 hour 30 min (1.5 hours), distance = 9 × 1.5 = 13.5 km.

Multiple choice

Two persons A and B start at the same time from points P and Q and proceed towards each other at the speed of 80 km/hr and 90 km/hr respectively. When both meet at a point in between, B was found to have travelled 180 km more than A. Find the total distance between points P and Q.
  1. $2560 km$
  2. $2890 km$
  3. $2550 km$
  4. $3060 km$
  5. $None of these$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let t be the time until meeting. Distance by A = 80t, Distance by B = 90t. B travels 180 km more: 90t - 80t = 180, so 10t = 180, t = 18 hours. Total distance = 80(18) + 90(18) = (80 + 90) × 18 = 170 × 18 = 3060 km. Option D is correct.

Multiple choice

Due to inclement weather, an airplane reduced its speed by 300 km/hr, and reached the destination of 1200 km late by 2hrs. Then the schedule duration of the flight was- खराब मौसम के कारण, एक हवाई जहाज ने अपनी गति 300 किमी/घंटा कम कर दी, और 1200 किमी के गंतव्य पर 2 घंटे की देरी से पहुंचा। तब उड़ान की निर्धारित अवधि थी-

  1. 1 hour 1 घंटा

  2. 1.5 hours 1.5 घंटे

  3. 2 hours 2 घंटे

  4. 2.5 hours 2.5 घंटे

  5. None of these इनमें से कोई नहीं
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

माना निर्धारित समय = t घंटे, सामान्य गति = S km/hr। दूरी = 1200 km। S = 1200/t, S-300 = 1200/(t+2)। हल करने पर t = 2 घंटे प्राप्त होता है। यह समय, गति और दूरी का प्रश्न है जिसे समीकरण बनाकर हल किया जाता है। गति कम होने से समय बढ़ता है।

Multiple choice

A person travels a distance of 300 km and then returns to the starting point. The time taken by him for the outward journey is 5 hours more than the time taken for the return journey. If he returns at a speed of 10 km/h more than the speed of going, what is the average speed (in km/h ) for the entire journey?

  1. 15

  2. 24

  3. 20

  4. 30
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let outward speed = v and time = t. Then vt = 300 and (v+10)(t-5) = 300. Solving: v = 20 km/h (t=15h), return speed = 30 km/h (t=10h). Average speed = total distance/total time = 600/25 = 24 km/h. Average speed for equal distances is harmonic mean, not arithmetic mean.

Multiple choice

A boat running upstream takes 6 hours 30 minutes to cover a certain distance and it takes 3 hours 30 minutes less to cover the same distance running downstream. The ratio of speed downstream to the speed upstream is
  1. $13:6$
  2. $19:7$
  3. $17:8$
  4. $11:5$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Upstream time = 6.5 hours, downstream time = 3 hours (6.5 - 3.5). Distance same, so speed downstream: speed upstream = time upstream: time downstream = 6.5:3 = 13:6. Downstream speed = boat + current, upstream = boat - current. Ratio 13:6 matches this relationship.

Multiple choice

Two cars start from the same place at the same time at right angles to each other. Their speeds are 54 km/h and 72 km/h, respectively. After 20 seconds, the distance between them will be: दो कारें एक ही स्थान से एक ही समय पर एक दूसरे से समकोण पर चलना शुरू करती हैं। इनकी गति क्रमशः 54 किमी/घंटा और 72 किमी/घंटा है। 20 सेकंड के बाद, उनके बीच की दूरी होगी:

  1. 480 m 480 मीटर

  2. 540 m 540 मीटर

  3. 720 m 720 मीटर

  4. 500 m 500 मीटर

  5. 750 m 750 मीटर
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Cars move at right angles, so distance forms hypotenuse of right triangle. Speeds: 54 km/h = 15 m/s, 72 km/h = 20 m/s. In 20 seconds: distances traveled are 300 m and 400 m. Distance between them = sqrt(300² + 400²) = sqrt(90000 + 160000) = sqrt(250000) = 500 m. This is a 3-4-5 triangle (300, 400, 500).

Multiple choice

A boat rows 36 km of a river towards upstream in 9 hours. How long will it take to cover the same distance downstream, if the speed of current is one-fifth the speed of the boat in still water?

  1. 4 hours

  2. 3 hours

  3. 4.5 hours

  4. 6 hours
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let the boat's speed in still water be 5x km/hr. Then current speed = x km/hr. Upstream speed = 5x - x = 4x km/hr. Distance = 36 km, time = 9 hours, so 4x = 36/9 = 4, giving x = 1. Boat speed = 5 km/hr, current = 1 km/hr. Downstream speed = 5 + 1 = 6 km/hr. Time downstream = 36/6 = 6 hours. Option D is correct.

Multiple choice

The speed of train A is 16 km per hour less than the speed of train B. To cover a distance of 384 km, B takes 4 hrs less time than A. What is the speed (in km/hr) of train B?

  1. 50

  2. 45

  3. 48

  4. 32
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let B's speed = x km/h. Then A's speed = (x - 16) km/h. Time for A = 384/(x-16), time for B = 384/x. B takes 4 hours less: 384/(x-16) - 384/x = 4. Solving: 384x - 384(x-16) = 4x(x-16). 384x - 384x + 6144 = 4x² - 64x. 4x² - 64x - 6144 = 0. x² - 16x - 1536 = 0. (x - 48)(x + 32) = 0. x = 48 (positive). B's speed = 48 km/h.

Multiple choice

A policeman saw a thief from a distance of 400m and started running towards him. If the speed of the policeman and the thief are 30 km/hr and 22 km/hr respectively. Find the distance covered by the thief before caught.

  1. 1.1 km

  2. 1.5 km

  3. 500 metres

  4. 780 metres
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Relative speed = 30 - 22 = 8 km/hr. Time to catch the thief = 0.4 km ÷ 8 km/hr = 0.05 hr = 3 minutes. In this time, thief travels: 22 × 0.05 = 1.1 km. Option B (1.5 km) ignores the relative speed concept. Option C (500m) uses incorrect time calculation. Option D (780m) is an arithmetic error.

Multiple choice

Two places R and S are 800 km apart from each other. Two persons start from R towards S at an interval of 2 hours, where A leaves from R for S before B. The speeds of A and B are 40 km/h and 60 km/h respectively. B overtakes A at M, which is on the way from R to S. What is the distance from R, where B overtakes A?

  1. 260 km

  2. 235 km

  3. 240 km

  4. 300 km
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

A starts 2 hours before B, covering 40 × 2 = 80 km head start. B's relative speed over A is 60 - 40 = 20 km/h. Time for B to catch A = 80/20 = 4 hours. Distance from R where B overtakes A = B's speed × time = 60 × 4 = 240 km. Options A (260 km), B (235 km), and D (300 km) don't satisfy the catch-up condition.

Multiple choice

Ajay covers certain distance with his own speed but when he reduced his speed 10 km/h, his time duration for the journey increased by 40 hours while if, he increases speed by 5 km/h from his original speed, he takes 10 hours less than the original time taken. Find the distance covered by him.

  1. 1000 km

  2. 1200 km

  3. 1500 km

  4. 1800 km
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let original speed = v, distance = d, time = t = d/v. From reduced speed: d/(v-10) = d/v + 40. From increased speed: d/(v+5) = d/v - 10. Solving gives v = 20 km/h, d = 1500 km. The answer correctly sets up and solves the system of equations relating speed, time, and distance.

Multiple choice

A man swimming in a river which flows 2.5 kmph finds that in a given time he can swim thrice as far with the stream as he can against it. How many distance he will cover in 8 hours against the current?

  1. 14 km

  2. 20 km

  3. 15 km

  4. 16 km

  5. none of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let swimmer's speed in still water be x kmph. Downstream speed = x+2.5, upstream speed = x-2.5. Since distance with stream is 3 times distance against it in the same time: (x+2.5) = 3(x-2.5), giving x+2.5 = 3x-7.5, so 2x = 10 and x = 5 kmph. Against the current, speed = 5-2.5 = 2.5 kmph. In 8 hours, distance = 2.5×8 = 20 km.

Multiple choice

Sunil can row a boat 20 km upstream in 1 hour 15 minutes. If the speed of the current of the river is 2 kmph, then how much time will it take to row the boat 30 km downstream?

  1. 1 h 10 m

  2. 1 h 45 m

  3. 1 h 30 m

  4. 1 h 20 m
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let boat speed in still water = b kmph. Upstream speed = b-2 covers 20km in 1.25 hours, so b-2 = 20/1.25 = 16 kmph, giving b = 18 kmph. Downstream speed = b+2 = 20 kmph. Time for 30km downstream = 30/20 = 1.5 hours = 1h 30m. Option A uses wrong speed. Option B adds time instead of calculating speed. Option D uses incorrect formula.

Multiple choice

A boat travels in a still water with a speed of 16 kmph while the rate of the flowing water is 4 kmph. Find the distance travelled in upstream by the boat in 20 minutes. एक नाव शांत पानी में 16 किमी प्रति घंटे की गति से यात्रा करती है जबकि बहते पानी की दर 4 किमी प्रति घंटे है। 20 मिनट में नाव द्वारा धारा के प्रतिकूल तय की गई दूरी ज्ञात कीजिए।

  1. 4 Km 4 किमी

  2. 3 Km 3 किमी

  3. 6 km 6 किमी

  4. 9 km 9 किमी

  5. None of these इनमें से कोई नहीं
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Upstream speed = boat speed in still water - stream speed = 16 - 4 = 12 kmph. Time = 20 minutes = 20/60 = 1/3 hour. Distance = speed × time = 12 × (1/3) = 4 km. Option A is correct.

Multiple choice

A boat travels in a still water with a speed of 12 kmph while the rate of the flowing water is 4 kmph. Find the distance travelled in upstream by the boat in 40 minutes

  1. 5.33 km

  2. 4 km

  3. 2 km

  4. Can't determined

  5. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Speed of boat in still water = 12 kmph. Rate of flowing water = 4 kmph. Upstream speed = boat speed - water speed = 12 - 4 = 8 kmph. Time given = 40 minutes = 40/60 hours = 2/3 hours. Distance = Speed × Time = 8 × (2/3) = 16/3 km = 5.33 km. This matches option A exactly.