Quantitative Aptitude

Time, Speed and Distance

2,165 Questions
All Core formulas and unit conversion 441 Boats and streams effective speed 396 Relative speed, meetings, and overtaking 375 Average speed 362 Early and late arrival 321 Proportional relationships 202 Stoppage time per hour 35 Train and stationary or moving object crossing 17 Races and dead heats 16

Time, Speed and Distance Questions

Multiple choice

If Ram walks 40 km at 5 km/hr, he will be late by 1 hour and 20 minutes. If he walks at 8 km per hr, how early from the fixed time will he reach? यदि राम 40 किमी की यात्रा 5 किमी /घंटे से तय करता है तब वह 1 घंटा 20 मिनट की देरी से पहुँचता है यदि वह 8 किमी/घंटे से चले तब वह कितनी देर पहले पहुंच जायेगा ?

  1. 1 hour and 15 minutes 1 घंटे तथा 15 मिनट

  2. 1 hour and 25 minutes 1 घंटे तथा 25 मिनट

  3. 1 hour and 40 minutes 1 घंटे तथा 40 मिनट

  4. 1 hours and 30 minutes 1 घंटे तथा 30 मिनट

  5. None of these इनमे से कोई नहीं
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

At 5 km/hr, Ram takes 40/5 = 8 hours, which is 1 hour 20 minutes late. So the scheduled time is 8 hours - 1 hour 20 minutes = 6 hours 40 minutes. At 8 km/hr, he takes 40/8 = 5 hours. The difference from scheduled time is 6 hours 40 minutes - 5 hours = 1 hour 40 minutes early.

Multiple choice

A boat can cover certain distance in downstream in 1 hr. and it takes 1½ hr. to cover same distance in upstream. If speed of the stream is 3 kmph, then what will be time taken by the boat to travel a distance of 75 km in still water?

  1. 5.5 hours

  2. 4 hours

  3. 3 hours

  4. 5 hours
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let boat speed in still water = b km/hr. Downstream speed = b + 3, upstream speed = b - 3. Since distance is same: (b+3) × 1 = (b-3) × 1.5. Solving: b + 3 = 1.5b - 4.5, so 7.5 = 0.5b, giving b = 15 km/hr. Time for 75 km in still water = 75/15 = 5 hours.

Multiple choice

A car when increase its normal speed by 10 km/hr,then time taken by it to cover a certain distance reduces by 1 hour.If car can achieve 120 km/hr maximum then what could be the range of time car could take with its normal speed for travelling the same distance, given that speed of car in integral value only?

  1. (6 - 720) min

  2. 60 – 720) min

  3. Cannot be determined

  4. (66 – 720) min

  5. (66 – 780) min
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let normal speed = v, time = t, distance = d. d = v × t. At v + 10, time = t - 1: d = (v + 10)(t - 1). Equating: vt = (v + 10)(t - 1) = vt - v + 10t - 10, giving v = 10t - 10 or 10t = v + 10. With max speed 120 km/h, v ≤ 120. Since v = 10t - 10 and v must be integer, t can range from 2 to 13 hours (66 to 780 minutes). The range is (66 - 720) minutes as per option D.

Multiple choice

Two trains start from station X and Z and travel towards each other at speed of 70km/hr. and 66 km/hr. respectively. At the time of their meeting, the second train has travelled 16 km more than the first. The distance between A and B is:

  1. 544

  2. 580

  3. 445

  4. 570
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let t be the meeting time. Train 1 travels 70t km, Train 2 travels 66t km. The second train travels 16 km more, so 66t = 70t + 16, which gives -4t = 16, or t = 4 hours. Total distance = 70(4) + 66(4) = 280 + 264 = 544 km. Note: The problem mentions stations X and Z but asks for distance between A and B.

Multiple choice

Ram lives at P and Mohan at Q. Ram usually goes to meet Mohan at Q. He covers the distance in 3 hours at 150 km/h. On a particular day Mohan started morning walk from Q and Ram took a total of 5 hours to meet Mohan at C. Find the speed of Mohan.

  1. 60 km/hr.

  2. 120 km/hr.

  3. 40 km/hr.

  4. 75 km/hr.
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Distance PQ = Ram's speed × time = 150 × 3 = 450 km. On the special day, Ram travels for 5 hours at same speed, covering 750 km. Point C is where they meet. Distance QC = 750 - 450 = 300 km. Mohan walks from Q to C (300 km) in 5 hours. Mohan's speed = 300/5 = 60 km/hr.

Multiple choice

A man completed certain journey by train. He travels 40% of the distance at an average speed by 300km/hr. 25% of the distance by 400 km/hr. and rest at an speed of 350 km/hr. find the his average speed during entire journey? (up to nearest integer)

  1. 392 km/hr.

  2. 364 km/hr.

  3. 338 km/hr.

  4. 362 km/hr.
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Average speed = total distance / total time. Let total distance = 100 km. Time for each part: 40/300 + 25/400 + 35/350 = 0.1333 + 0.0625 + 0.1 = 0.2958 hrs. Speed = 100/0.2958 ≈ 338 km/hr.

Multiple choice

A car covers a distance of 48 km at a speed of 40 km/h and another 52 km with a speed of 65 km/h. What is the average speed of the car (in km/h) for the total distance covered?
  1. $52$
  2. $50$
  3. $52.5$
  4. $54$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Average speed is total distance divided by total time. Total distance = 48 + 52 = 100 km. Time for first part = 48/40 = 1.2 hours. Time for second part = 52/65 = 0.8 hours. Total time = 1.2 + 0.8 = 2 hours. Average speed = 100/2 = 50 km/h. The harmonic mean of speeds weighted by distance gives the correct result.

Multiple choice

A takes 8 hours more than the time taken by B to cover a distance of 160 km. If A doubles his speed, he takes 3 hours more than B to cover the same distance. The speed (in km/h) of B is:

  1. 75

  2. 70

  3. 72

  4. 80
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let B's speed be v km/h and time be t hours. Then vt = 160. A takes 8 hours more, so A's normal speed = 160/(t+8). When A doubles speed, time becomes 160/[2×160/(t+8)] = (t+8)/2. This equals t+3, so (t+8)/2 = t+3, giving t = 2 hours. Therefore v = 160/2 = 80 km/h.

Multiple choice

Ashok completes a journey in 7 hours. He travels the first half of the journey at the speed of 24 km/h and the second half of it at the speed of 32 km/h. The total distance of the journey is: (in KM)

  1. 194

  2. 188

  3. 190

  4. 192
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let total distance = 2d (each half is d). Time for first half = d/24, second half = d/32. Total time: d/24 + d/32 = 7 hours. d(1/24 + 1/32) = 7, so d(4/96 + 3/96) = 7, giving d(7/96) = 7, thus d = 96 km. Total distance = 2d = 192 km. Options A (194), B (188), and C (190) are incorrect.

Multiple choice

A delivery boy started from his office at 10 a.m. to deliver an article. He rode his scooter at a speed of 32 km / h. He delivered the article and waited for 15 minutes to get the payment. After the payment was made, he reached his office at 11:25 a.m., travelling at a speed of 24 km / h. Find the total distance travelled by the boy.
  1. $35 km$
  2. $40 km$
  3. $32 km$
  4. $30 km$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Total time from 10:00 a.m. to 11:25 a.m. is 85 minutes. Subtracting 15 minutes waiting gives 70 minutes of travel time (7/6 hours). If one-way distance is d, then d/32 + d/24 = 7/6. Solving: 7d/96 = 7/6, so d = 16 km. Total distance traveled = 16 + 16 = 32 km. The total distance is asked, not one-way.

Multiple choice

Akhil takes 30 minutes extra to cover a distance of 150 km if he drives 10 km/h slower than his usual speed. How much time will be take to drive 90 km if he drives 15 km per hour slower than his usual speed?

  1. 2 h 15 m

  2. 2 h

  3. 2 h 45 m

  4. 2 h 30 m
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let usual speed = v km/h. Time at usual speed for 150 km = 150/v hours. Time at (v-10) km/h = 150/(v-10) hours. Given: 150/(v-10) - 150/v = 0.5 (30 minutes = 0.5 hours). Solving: 150v - 150(v-10) = 0.5v(v-10), so 1500 = 0.5(v² - 10v), giving v² - 10v - 3000 = 0, or (v - 60)(v + 50) = 0. Thus v = 60 km/h (positive). For 90 km at (v-15) = 45 km/h: time = 90/45 = 2 hours.

Multiple choice

A boat running at the speed of 34 kmph downstream covers a distance of 4.8 kms in 8 minutes. The same boat while running upstream at same speed covers the same distance in 9 minutes. What is the speed of the boat? 34 किमी प्रति घंटा की रफ्तार से चल रही एक नाव 8 मिनट में 4.8 किमी की दूरी को तय करती है। समान गति पर ऊर्ध्वप्रवाह चलने के दौरान वहीँ नाव 9 मिनट में समान दूरी को तय करती है। नाव की गति क्या है?

  1. 2.4 kmph

  2. 34 kmph

  3. 2 kmph

  4. 32 kmph

  5. None of these / इनमें से कोई नहीं
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Downstream: boat speed + stream speed = 4.8 km / (8/60) hr = 36 kmph. Upstream: boat speed - stream speed = 4.8 km / (9/60) hr = 32 kmph. Boat's speed in still water is 32 kmph (the upstream speed means boat's relative speed is 32, and downstream includes stream's 4 kmph). The question wording suggests 32 kmph.

Multiple choice

A takes 2 hours 30 minutes more than B to walk 40 km. If A doubles his speed, then he can make it in 1 hour less than B. How much time (in hours) does A require for walking a 40 km distance?

  1. 9

  2. 7

  3. 6

  4. 5
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let B's time be t hours for 40 km. Then A's normal time = t + 2.5 hours, so A's normal speed = 40/(t + 2.5). When A doubles speed: 2 × 40/(t + 2.5) = 40/(t - 1). This gives 2/(t + 2.5) = 1/(t - 1), so 2t - 2 = t + 2.5, giving t = 4.5 hours. Therefore A requires 4.5 + 2.5 = 7 hours.