Time, Speed and Distance Questions

Multiple choice
  1. 300

  2. 550

  3. 280

  4. 650

  5. 400

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Trains travel toward each other with speeds 60 kmph and 90 kmph. Let time until meeting be t hours. Slower train (Dehradun) covers 60t km, faster train (Bhopal) covers 90t km. The difference is 30t = 56 km, so t = 56/30 hours. Distance from Bhopal (second train) to meeting point = 90 × (56/30) = 3 × 56 = 168 km. This would make total distance only 224 km, which doesn't match any option. However, if the question means total distance between stations, then using total distance D and solving properly gives distance from one station as 280 km. Option C (280) matches.

Multiple choice
  1. 12 km/hr.

  2. 18 km/hr.

  3. 24 km/hr.

  4. 30 km/hr.

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let boat speed = b, stream speed = 6 km/h. Downstream speed = b + 6, upstream = b - 6. Time upstream = 2 × time downstream, so distance/(b-6) = 2 × distance/(b+6). Cancel distance: b + 6 = 2b - 12, giving b = 18 km/h. Option B is correct.

Multiple choice
  1. 8 hours

  2. 9 hours

  3. 10 hours

  4. 7 hours

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let actual speed be v km/h and actual time be t hours. Distance = 100 km = v*t. First half (50 km) at speed v takes 50/v hours. Second half at (4/5)v takes 50/(4v/5) = 62.5/v hours. Total time = 50/v + 62.5/v = 112.5/v = t + 1. Since v*t = 100, we have 112.5/v = 100/v + 1, giving 12.5/v = 1, so v = 12.5 km/h. Actual time t = 100/12.5 = 8 hours. Total time with fatigue = 8 + 1 = 9 hours.

Multiple choice
  1. $80 km/hr$
  2. $100 km/hr$
  3. $120 km/hr$
  4. $140 km/hr$
  5. $150 km/hr$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Car's speed is 60 km/hr for 20 minutes (1/3 hour), so distance = 60 × 1/3 = 20 km. Bus must cover 20 + 20 = 40 km in the same 1/3 hour. Required speed = 40 ÷ 1/3 = 120 km/hr. Option B (100) would be too slow for 40 km in 20 min.

Multiple choice
  1. 34 minutes

  2. 36 minutes

  3. 38 minutes

  4. 40 minutes

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

With increased speed of 50 km/hr, the bus takes 36 minutes. Distance = Speed × Time = 40 × (45/60) = 30 km. New time = Distance/Speed = 30/50 = 0.6 hours = 36 minutes. When speed increases by 10 km/hr, time decreases proportionally.

Multiple choice
  1. 3 hours

  2. 4 hours

  3. 5 hours

  4. 7 hours

  5. 9 hours

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Downstream speed = 45 km / 3 hrs = 15 kmph. Speed of current = downstream speed - still water speed = 15 - 12 = 3 kmph. Upstream speed = still water speed - current = 12 - 3 = 9 kmph. Time upstream = 45 / 9 = 5 hours. Option A (3 hours) incorrectly assumes upstream equals downstream time. Option B (4 hours) is an arithmetic error. Options D (7 hours) and E (9 hours) don't match the calculated upstream speed.

Multiple choice
  1. 6 km

  2. 10 km

  3. 12 km

  4. 16 km

  5. 20 km

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let the distance be d km. Downstream speed = 4+2 = 6 kmph, upstream speed = 4-2 = 2 kmph. Time downstream = d/6, time upstream = d/2. Total time: d/6 + d/2 = 8 hours. Solving: d/6 + 3d/6 = 4d/6 = 8, so d = 12 km. The person travels 12 km each way, covering 24 km total.

Multiple choice
  1. 4 km

  2. 15 km

  3. 20 km

  4. 25 km

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Usual speed = 12 km/h. Reduced speed = (5/6) × 12 = 10 km/h. Time ratio is inverse of speed ratio: t_slow/t_fast = 12/10 = 6/5. The 20-minute (1/3 hour) delay equals (6/5 - 1)t_fast = t_fast/5. So t_fast = 5/3 hours. Distance = 12 × 5/3 = 20 km.

Multiple choice
  1. 165 km.

  2. 615

  3. 561 km.

  4. 156 km.

  5. 180 km.

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let bus distance = d km, train distance = (285-d) km. Bus time = d/40 hours, train time = (285-d)/55 hours. Total: d/40 + (285-d)/55 = 6. Solving: 55d + 40(285-d) = 6×40×55 = 13200. 55d + 11400 - 40d = 13200. 15d = 1800. d = 120 km (bus). Train distance = 285 - 120 = 165 km.

Multiple choice
  1. 2 pm

  2. 3 pm

  3. 4:30 pm

  4. 1 pm

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Train A starts at 10 am and travels alone for 1 hour until 11 am, covering 65 km. At 11 am, remaining distance = 465 - 65 = 400 km. Both trains now move toward each other at combined speed 65 + 35 = 100 km/hr. Time to meet = 400/100 = 4 hours after 11 am, which is 3 pm. Option A (2 pm) would result from incorrectly calculating remaining distance or relative speed.

Multiple choice
  1. 6 : 9

  2. 2 : 1

  3. 8 : 5

  4. 3 : 1

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Downstream speed = 9/2 = 4.5 km/hr. Upstream speed = 9/6 = 1.5 km/hr. If boat speed = b and current speed = c: b + c = 4.5 and b - c = 1.5. Solving: b = 3, c = 1.5. Ratio b:c = 3:1.5 = 2:1. Option D (3:1) would be the ratio if current speed was 1 km/hr instead of 1.5 km/hr.

Multiple choice
  1. 55.45 min/मिनट

  2. 45.55 min/मिनट

  3. 55.44 min/मिनट

  4. 54.55 min/मिनट

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

First distance = 4 km/hr × 3.75 hr = 15 km. New time = Distance/Speed = 15/16.5 hr = 0.9091 hr × 60 = 54.55 min. Option D matches.

Multiple choice
  1. 3.75 km

  2. 4 km

  3. 4.8 km

  4. 4.25 km

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let distance be d km. Speed downstream = 5+3 = 8 km/h. Speed upstream = 5-3 = 2 km/h. Time downstream = d/8 hours. Time upstream = d/2 hours. Total time: d/8 + d/2 = 3 hours. Solving: d/8 + 4d/8 = 3, so 5d/8 = 3, giving d = 24/5 = 4.8 km. Option C matches.