Mathematics · Physics
Sphere Geometry
157 Questions
Sphere geometry deals with calculating the volume and surface area of round objects. It includes problems on spherical shells, recasting spheres, and understanding radius variations. These mathematical formulas are essential for competitive exam preparation.
Volume of a sphereSurface area calculationsSpherical shellsRadius ratio variationsRecasting spheres
Sphere Geometry Questions
What is the formula for the volume of a sphere with radius (r)?
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\(\frac{4}{3}\pi r^3\)
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\(\frac{1}{3}\pi r^3\)
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\(\pi r^3\)
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\(2\pi r^3\)
A
Correct answer
Explanation
The volume of a sphere is given by the formula (\frac{4}{3}\pi r^3), where (r) is the radius of the sphere.
What is the formula for the surface area of a sphere with radius (r)?
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\(4\pi r^2\)
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\(2\pi r^2\)
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\(\pi r^2\)
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\(\frac{1}{2}\pi r^2\)
A
Correct answer
Explanation
The surface area of a sphere is given by the formula (4\pi r^2), where (r) is the radius of the sphere.
What is the formula for the volume of a hemisphere with radius (r)?
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\(\frac{1}{2}\cdot\frac{4}{3}\pi r^3\)
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\(\frac{1}{2}\cdot\pi r^3\)
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\(\frac{2}{3}\pi r^3\)
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\(\pi r^3\)
A
Correct answer
Explanation
The volume of a hemisphere is given by the formula (\frac{1}{2}\cdot\frac{4}{3}\pi r^3), where (r) is the radius of the hemisphere.
What is the general formula for the Madhava series for the volume of a sphere?
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$$V = \frac{4}{3}\pi r^3 = \frac{4}{3}\pi r^3 \left(1 - \frac{1}{3} + \frac{1}{5} - \frac{1}{7} + \cdots\right)$$
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$$V = \frac{4}{3}\pi r^3 = \frac{4}{3}\pi r^3 \left(1 - \frac{1}{3} + \frac{1}{5} - \frac{1}{7} + \cdots\right)$$
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$$V = \frac{4}{3}\pi r^3 = \frac{4}{3}\pi r^3 \left(1 - \frac{1}{3} + \frac{1}{5} - \frac{1}{7} + \cdots\right)$$
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$$V = \frac{4}{3}\pi r^3 = \frac{4}{3}\pi r^3 \left(1 - \frac{1}{3} + \frac{1}{5} - \frac{1}{7} + \cdots\right)$$
A,B,C,D
Correct answer
Explanation
The general formula for the Madhava series for the volume of a sphere is $$V = \frac{4}{3}\pi r^3 = \frac{4}{3}\pi r^3 \left(1 - \frac{1}{3} + \frac{1}{5} - \frac{1}{7} + \cdots\right)$$.
What is the formula for calculating the radius of a Hill Sphere?
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$R_H = (1 + m/3M)^{1/3} a$
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$R_H = (1 + m/M)^{1/3} a$
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$R_H = (1 + 3m/M)^{1/3} a$
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$R_H = (1 + m/M)^{2/3} a$
A
Correct answer
Explanation
The formula for calculating the radius of a Hill Sphere is $R_H = (1 + m/3M)^{1/3} a$, where $R_H$ is the radius of the Hill Sphere, $m$ is the mass of the orbiting body, $M$ is the mass of the central body, and $a$ is the distance between the two bodies.
What is the formula for the volume of a sphere, as given by Bhaskara II?
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$\text{Volume} = \frac{4}{3} \times \pi \times \text{radius}^3$
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$\text{Volume} = \frac{3}{4} \times \pi \times \text{radius}^3$
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$\text{Volume} = \frac{1}{3} \times \pi \times \text{radius}^3$
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$\text{Volume} = \frac{2}{3} \times \pi \times \text{radius}^3$
A
Correct answer
Explanation
Bhaskara II's formula for the volume of a sphere is $\text{Volume} = \frac{4}{3} \times \pi \times \text{radius}^3$. This formula is still used today in geometry.
What was the Babylonian method for calculating the volume of a sphere?
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The Babylonian Method
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The Volume of a Sphere Formula
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The Pythagorean Theorem
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The Surface Area of a Sphere Formula
A
Correct answer
Explanation
The Babylonians had a method for calculating the volume of a sphere that involved using a series of approximations to find the solution.
What was the Babylonian method for calculating the surface area of a sphere?
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The Babylonian Method
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The Surface Area of a Sphere Formula
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The Pythagorean Theorem
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The Volume of a Sphere Formula
A
Correct answer
Explanation
The Babylonians had a method for calculating the surface area of a sphere that involved using a series of approximations to find the solution.
What is Bhaskara II's formula for the volume of a sphere?
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$$V = \frac{4}{3}\pi r^3$$
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$$V = \pi r^2h$$
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$$V = \frac{1}{3}\pi r^2h$$
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$$V = \frac{1}{2}\pi r^2h$$
A
Correct answer
Explanation
Bhaskara II's formula for the volume of a sphere is given by $$V = \frac{4}{3}\pi r^3$$, where $$r$$ is the radius of the sphere.
Find the volume of a sphere with radius (r = 5 cm).
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\(100\pi cm^3\)
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\(200\pi cm^3\)
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\(300\pi cm^3\)
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\(400\pi cm^3\)
C
Correct answer
Explanation
To find the volume of a sphere, we can use the formula: (Volume = \frac{4}{3}\pi r^3). Plugging in the value of (r = 5 cm), we get: (Volume = \frac{4}{3}\pi (5 cm)^3 = \frac{4}{3}\pi (125 cm^3) = 300\pi cm^3).
What is the formula for the volume of a sphere?
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V = 4/3πr^3
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V = πr^2h
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V = πr^3
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V = 2πr^3
A
Correct answer
Explanation
The formula for the volume of a sphere is V = 4/3πr^3, where V is the volume, π is a mathematical constant approximately equal to 3.14, and r is the radius of the sphere.
What is Brahmagupta's rule for finding the volume of a sphere?
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The volume of a sphere is equal to four-thirds the product of its radius and its surface area.
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The volume of a sphere is equal to two-thirds the product of its radius and its surface area.
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The volume of a sphere is equal to one-third the product of its radius and its surface area.
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The volume of a sphere is equal to half the product of its radius and its surface area.
A
Correct answer
Explanation
Brahmagupta's rule for finding the volume of a sphere states that the volume of a sphere is equal to four-thirds the product of its radius and its surface area.
What is Brahmagupta's rule for finding the volume of a sphere?
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$V = \frac{4}{3} \pi r^3$
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$V = \frac{2}{3} \pi r^3$
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$V = \pi r^3$
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$V = 2 \pi r^3$
A
Correct answer
Explanation
Brahmagupta's rule for finding the volume of a sphere states that $V = \frac{4}{3} \pi r^3$.
What is the formula for finding the volume of a sphere with radius (r)?
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\(\frac{4}{3}\pi r^3\)
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\(\frac{1}{3}\pi r^3\)
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\(\frac{2}{3}\pi r^3\)
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\(\frac{3}{4}\pi r^3\)
A
Correct answer
Explanation
The formula for finding the volume of a sphere with radius (r) is (\frac{4}{3}\pi r^3).
What is the formula for finding the surface area of a sphere with radius (r)?
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\(4\pi r^2\)
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\(2\pi r^2\)
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\(3\pi r^2\)
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\(\pi r^2\)
A
Correct answer
Explanation
The formula for finding the surface area of a sphere with radius (r) is (4\pi r^2).