Mathematics · Physics

Sphere Geometry

157 Questions

Sphere geometry deals with calculating the volume and surface area of round objects. It includes problems on spherical shells, recasting spheres, and understanding radius variations. These mathematical formulas are essential for competitive exam preparation.

Volume of a sphereSurface area calculationsSpherical shellsRadius ratio variationsRecasting spheres

Sphere Geometry Questions

Multiple choice

What is the name of the theorem that states that the surface area of a sphere is equal to 4 pi times the square of its radius?

  1. Pythagorean Theorem

  2. Brahmagupta's Theorem

  3. Euclid's Theorem

  4. Surface Area of a Sphere Formula

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The Surface Area of a Sphere Formula is a well-known formula for finding the surface area of a sphere.

Multiple choice

Brahmagupta's formula for finding the volume of a sphere is:

  1. $V = \frac{4}{3}\pi r^3$
  2. $V = \frac{1}{3}\pi r^3$
  3. $V = \frac{2}{3}\pi r^3$
  4. $V = \frac{3}{4}\pi r^3$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Brahmagupta's formula for finding the volume of a sphere is $V = \frac{4}{3}\pi r^3$.

Multiple choice

Brahmagupta's formula for finding the volume of a sphere is:

  1. $V = \frac{4}{3}\pi r^3$
  2. $V = \frac{1}{3}\pi r^3$
  3. $V = \frac{2}{3}\pi r^3$
  4. $V = \frac{3}{4}\pi r^3$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Brahmagupta's formula for finding the volume of a sphere is $V = \frac{4}{3}\pi r^3$.

Multiple choice

Find the volume of a sphere with radius 5 cm.

  1. 523.6 cm³

  2. 261.8 cm³

  3. 130.9 cm³

  4. 65.45 cm³

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The volume of a sphere is given by V = ½πr³, where r is the radius. In this case, r = 5 cm, so V = ½π(5³) = 523.6 cm³.

Multiple choice

Find the surface area of a sphere with radius 4 cm.

  1. 251.2 cm²

  2. 125.6 cm²

  3. 62.8 cm²

  4. 31.4 cm²

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The surface area of a sphere is given by SA = 4πr², where r is the radius. In this case, r = 4 cm, so SA = 4π(4²) = 251.2 cm².

Multiple choice

A sphere has a radius of 4 cm. What is the volume of the sphere?

  1. 268.08 cm³

  2. 134.04 cm³

  3. 67.02 cm³

  4. 33.51 cm³

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The volume of a sphere is given by V = ½πr³, where r is the radius. In this case, r = 4 cm, so V = ½π(4³) = 268.08 cm³.

Multiple choice

Which mathematical concept is used to calculate the volume of a sphere?

  1. Volume = 4/3πr³

  2. Volume = πr²h

  3. Volume = πd³

  4. Volume = πd²h

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The volume of a sphere is calculated using the formula Volume = 4/3πr³, where r is the radius of the sphere.

Multiple choice

Which mathematical concept is used to calculate the surface area of a sphere?

  1. Surface Area = 4πr²

  2. Surface Area = πr²h

  3. Surface Area = πd²

  4. Surface Area = πd³

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The surface area of a sphere is calculated using the formula Surface Area = 4πr², where r is the radius of the sphere.

Multiple choice

What formula did Dandin provide for the volume of a sphere?

  1. $\frac{4}{3}\pi r^3$
  2. $\frac{1}{3}\pi r^3$
  3. $\frac{2}{3}\pi r^3$
  4. $\pi r^3$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Dandin gave the formula for the volume of a sphere as (\frac{4}{3}\pi r^3).

Multiple choice

A spherical balloon is being inflated with air. If the radius of the balloon is increasing at a rate of 2 cm/s, how fast is the volume of the balloon increasing when the radius is 10 cm?

  1. 320π cubic centimeters per second

  2. 640π cubic centimeters per second

  3. 800π cubic centimeters per second

  4. 1280π cubic centimeters per second

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

We can use calculus to find the relationship between the radius and volume of the balloon, and then differentiate to find the rate of change of volume with respect to time.

Multiple choice

What is Bhaskara II's formula for finding the volume of a sphere?

  1. $\frac{4}{3} * \pi * radius^3$
  2. $\frac{4}{3} * \pi * diameter^3$
  3. $\frac{4}{3} * \pi * radius * diameter^2$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Bhaskara II's formula for finding the volume of a sphere is (\frac{4}{3} * \pi * radius^3).

Multiple choice

Calculate the volume of a sphere with radius 10 cm.

  1. 4/3π(1000) cm^3

  2. 4/3π(100) cm^3

  3. 4/3π(10) cm^3

  4. 4/3π cm^3

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

To find the volume of a sphere, use the formula: Volume = (4/3)πr^3. Substitute the radius r = 10 cm: Volume = (4/3)π(10 cm)^3 = 4/3π(1000) cm^3. Therefore, the answer is 4/3π(1000) cm^3.

Multiple choice

What is the formula for the volume of a sphere?

  1. $V = 4\pi r^3$
  2. $V = \pi r^2$
  3. $V = \frac{4}{3}\pi r^3$
  4. $V = \frac{1}{3}\pi r^2$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The formula for the volume of a sphere is $V = \frac{4}{3}\pi r^3$, where r is the radius of the sphere.

Multiple choice

What is the formula for the surface area of a sphere?

  1. $S = 4\pi r^2$
  2. $S = \pi r^2$
  3. $S = \frac{4}{3}\pi r^2$
  4. $S = \frac{1}{3}\pi r^2$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The formula for the surface area of a sphere is $S = 4\pi r^2$, where r is the radius of the sphere.

Multiple choice

What is the equation of a small circle?

  1. $$x^2 + y^2 + z^2 = r^2$$
  2. $$x^2 + y^2 - z^2 = r^2$$
  3. $$x^2 - y^2 + z^2 = r^2$$
  4. $$x^2 - y^2 - z^2 = r^2$$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The equation of a small circle is $$x^2 + y^2 + z^2 = r^2$$, where r is the radius of the small circle.