Physics

Rotational and Circular Motion

235 Questions

Rotational and circular motion examines the dynamics of objects moving in circular paths or rotating around an axis. Key concepts include angular momentum, torque, moment of inertia, and centripetal force. This is a highly scoring topic in the physics section of competitive exams.

Angular momentumCentripetal forceMoment of inertiaRolling objectsGyroscopic effect

Rotational and Circular Motion Questions

Multiple choice
  1. 2 $\omega_2$VQ/P; direction of VQ/P rotated by 90o in the direction of $\omega_2$
  2. $\omega_2$VQ/P; direction of VQ/P rotated by 90o in the direction of $\omega_2$
  3. 2 $\omega_2$ VQ/P; direction of VQ/P rotated by 90o opposite to the direction of $\omega_2$
  4. $\omega_2$VQ/P; direction of VQ/P rotated by 90o opposite to the direction of $\omega_2$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Multiple choice
  1. x(t) = cos t, y(t) = sint

  2. x(t) = cos t, y(t) = 2 sint

  3. x (t) $\frac{1}{2}$ + cos(t) = 1 +, y(t) = 2 sint
  4. x(t) $\frac{1}{2}$ + cos (t) = 1 +, y(t) = sint
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Correct option is (3). $d_{max} = \sqrt{\frac{5}{4} + 1}\\ \hspace{0.9cm} = \sqrt{\frac{9}{4}}\\ \hspace{0.9cm} = 1.5 \hspace{0.5cm} \Rightarrow d_{D, max} = 1.5$

Multiple choice
  1. $\frac{1}{2 \pi} \sqrt{\frac{k}{m}}$
  2. $\frac{1}{2 \pi} \sqrt{\frac{2k}{m}}$
  3. $\frac{1}{2 \pi} \sqrt{\frac{2k}{3m}}$
  4. $\frac{1}{2 \pi} \sqrt{\frac{3k}{2m}}$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Therefore, natural frequency of vibration of the system is, $$\int_n = \frac{\omega_n}{2 \pi} = \frac{1}{2 \pi} \sqrt{\frac{2k}{3m}}$$

Multiple choice
  1. 568; 342 N

  2. 565; 381 N

  3. 440; 342 N

  4. 480; 356 N

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

$\text{Now we have to find cutting force $(F_c)$ and frictional force $(f_t)$from merchant's theory,}\\ \hspace{1cm}2\phi+\beta-\alpha=90^0 \\ \hspace{3cm}\beta=90^0+\alpha-2\phi \\ \hspace{3cm}=90^0+7-2\times28=41^0$