Number Series

The difference between two consecutive terms is an odd number starting from 9. (9, 11, 13, 15, 17, 19) So, 25 should be replaced by 26, in the sequence.

 In each term  except 427 sum of first and last digit is equal to the middle digit.

Each term of the series is the product of the preceding two terms. So, 5000 is wrong and must be replaced by (50 x 500)  i.e 25000

Except 21, all others are even numbers.

In each term, except 383, the product of first and third digit is equal to the middle digit.

 Subtract 20, 25, 30, 35, 40, 45 from successive terms. So, 0 is wrong, it should be -5.

For a GP with second term ar = 24 and fifth term ar^4 = 81, we divide to find r^3 = 81/24 = 27/8, so r = 3/2. Then a = 24/r = 24/(3/2) = 16. The series is 16, 16×(3/2), 16×(3/2)^2, ... = 16, 24, 36, 54, 81,...

It is the correct option. First term = 2 Second term = 1/4*(23) = 2 Third term = 1/4*(23) = 2 Fourth term = 1/4*(23) = 2 So, each term of the given sequence is 2 only. So, option (2) is correct.

The difference pattern of the series is 3, 5, 7,.... . Hence, the next term is 26 (17 + 9).

The series has difference pattern:- 4, 6, 8, 10, 12 ......... Hence, the next term is 42 (30 + 12).

The terms of the series can be obtained by subtracting 8 and 16 alternatively from the successive terms. Hence, the required term is 27 (43 - 16).

Each term in the series is the product of the digits of the preceeding term. Thus, 6 × 6 = 36, 3 × 6 = 18 and so on. Therefore, next term = 1 × 8 = 8

This is an A.P series with common difference 3. Therefore, the next term is 20 (17 + 3).

The series has a difference pattern:- 1, 2, 3, 4...... So, the next term is 16 (11 + 5). 

The series follows the difference pattern of 4, 8, 12, 16, 20............. Therefore, the next term is  61 (41 + 20).