Quantitative Aptitude
Mixtures and Alligation
1,816 Questions
Mixtures and Alligation Questions
A
Correct answer
Explanation
Initial mixture is 68 litres with ratio 11:6 (water:spirit). Water = (11/17)*68 = 44, Spirit = (6/17)*68 = 24. We want a new ratio 4:3 by adding x amount of spirit. 44 / (24+x) = 4/3. 132 = 96 + 4x. 36 = 4x, so x = 9.
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12:7:7
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7:12:7
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7:7:12
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12:12:7
A
Correct answer
Explanation
Using the allegation method for three quantities: compare 480, 576, 696 with 564. Differences are 84, 12, 132. Simplifying the ratio of these differences leads to 12:7:7.
C
Correct answer
Explanation
Rates: A=1/30, B=1/20, C=1/10. In 3 minutes: A fills 3/30=1/10, B fills 3/20, C fills 3/10. Total filled = 1/10 + 3/20 + 3/10 = 2/20 + 3/20 + 6/20 = 11/20. The proportion of R (from C) is (3/10) / (11/20) = (6/20) / (11/20) = 6/11.
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121:63
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122:59
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121:59
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121:95
C
Correct answer
Explanation
Total alcohol = 10*(2/3) + 10*(3/4) + 10*(3/5) = 20/3 + 30/4 + 30/5 = 6.66 + 7.5 + 6 = 20.16. Total water = 10*(1/3) + 10*(1/4) + 10*(2/5) = 3.33 + 2.5 + 4 = 9.83. Ratio = 20.16 / 9.83. Using fractions: (400+450+360)/60 : (200+150+240)/60 = 1210/60 : 590/60 = 121:59.
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12 litres
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13 litres
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10 litres
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8 litres
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9 litres
C
Correct answer
Explanation
Initial: A+W=60, A-W=12. Solving gives A=36, W=24. Let x be water added: 36 / (24+x) = 18/17. 36*17 = 18(24+x). 2*17 = 24+x. 34 = 24+x, so x=10.
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4 : 3
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16 : 9
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3 : 4
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8 : 13
B
Correct answer
Explanation
Initial milk = 120. After 1st replacement: Milk = 120 * (1 - 24/120) = 120 * 0.8 = 96. After 2nd replacement: Milk = 96 * 0.8 = 76.8. Water = 120 - 76.8 = 43.2. Ratio = 76.8 : 43.2 = 768 : 432 = 16 : 9.
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4 litres, 8 litres
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6 litres, 6 litres
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5 litres, 7 litres
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7 litres, 5 litres
B
Correct answer
Explanation
Can 1: 25% water (1/4). Can 2: 50% water (1/2). Target: 12L with 3:5 water to milk ratio, which is 3/8 water (37.5%). Using alligation: (1/2 - 3/8) : (3/8 - 1/4) = (1/8) : (1/8) = 1:1. Total 12L means 6L from each.
B
Correct answer
Explanation
Let the ratio of water to soda be x:1. Cost of soda = 12. Cost of water = 0. Total cost = 12. Selling price = 13.75. Profit = 25%, so Cost * 1.25 = 13.75. Cost = 13.75 / 1.25 = 11. Using the mixture rule: (12*1 + 0*x) / (1+x) = 11. 12 = 11 + 11x, so 11x = 1, x = 1/11.
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100 ml
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150 ml
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200 ml
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300 ml
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500 ml
C
Correct answer
Explanation
Let initial alcohol be 3x and water be 2x. Total = 5x. Adding 200 ml of 1:1 solution means adding 100 ml alcohol and 100 ml water. New ratio: (3x + 100) / (2x + 100) = 4/3. 9x + 300 = 8x + 400 => x = 100. Initial water = 2x = 200 ml.
B
Correct answer
Explanation
Initial alcohol = 40% of 5 = 2 liters. Total volume becomes 5 + 1 = 6 liters. New concentration = 2 / 6 = 1/3 = 33.33% or 33 1/3%.
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6 9/13%
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7 9/13%
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7 6/13%
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7 5/13%
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10%loss
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10%profit
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20%profit
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20%loss
C
Correct answer
Explanation
Cost price of 1kg of mix = (10+15)/2 = 12.5. Selling price = 15. Profit = 15 - 12.5 = 2.5. Profit percentage = (2.5 / 12.5) * 100 = 20%.
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55 litres
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60 litres
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40 litres
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50 litres
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45 litres
B
Correct answer
Explanation
Initial: 60L, 40% sugar = 24L sugar, 36L water. Add x L sugar. New sugar = 24+x. New total = 60+x. (24+x)/(60+x) = 0.7. 24+x = 42 + 0.7x. 0.3x = 18. x = 60.
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24 litres
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32 litres
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40 litres
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20 litres
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None of these
B
Correct answer
Explanation
Initial: 48G, 144R (Total 192). Remove D: (48-D/4)G, (144-3D/4)R. Add 32G, 48R: (80-D/4)G, (192-3D/4)R. Total mixture = 192-D+80 = 272-D. Glycerin % = (80-D/4)/(272-D) = 0.3. 80-0.25D = 81.6 - 0.3D. 0.05D = 1.6. D = 32.