Multiple choice

A vessel contains 60 L mixture of sugar and water in which percentage of sugar is 40%. How much sugar should be added to it, so that percentage of sugar become 70%?

  1. 55 litres

  2. 60 litres

  3. 40 litres

  4. 50 litres

  5. 45 litres
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Initial: 60L, 40% sugar = 24L sugar, 36L water. Add x L sugar. New sugar = 24+x. New total = 60+x. (24+x)/(60+x) = 0.7. 24+x = 42 + 0.7x. 0.3x = 18. x = 60.

AI explanation

The vessel contains 60 litres of mixture with 40% sugar, meaning there is 24 litres of sugar and 36 litres of water. Let x be the amount of sugar added, so the new sugar quantity is 24 + x. Since water remains 36 litres and must equal 30% of the new total, 36 = 0.30(24 + x + 36). Solving 36 = 0.30(60 + x) yields 120 = 60 + x, so x = 60 litres.

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