Quantitative Aptitude
Mixtures and Alligation
1,816 Questions
Mixtures and Alligation Questions
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40 liter
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60 liter
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45 liter
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80 liter
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None of these
B
Correct answer
Explanation
Initial water: 20% of 240L = 48L. When 60L removed, water removed = 20% of 60L = 12L, remaining water = 36L. After adding 60L water, total water = 96L. Final mixture = 240L, water percentage = 96/240 × 100 = 40%. This uses the replacement formula: amount replaced = (target% - initial%) × total / target%.
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4:3:2
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12:7:15
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5:1:6
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21:7:29
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None of these
C
Correct answer
Explanation
To get a mixture worth 80 Rs/Kg from three varieties costing 72, 60, and 90 Rs/Kg, we need to find a ratio where the weighted average equals 80. Using alligation or verification: (72×5 + 60×1 + 90×6) ÷ (5+1+6) = 960 ÷ 12 = 80. Option A (4:3:2) gives 77.5 Rs/Kg, Option B (12:7:15) gives 76 Rs/Kg, and Option D (21:7:29) gives 79.2 Rs/Kg - none of these work.
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$19 : 26$
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$26 : 19$
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$27 : 14$
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$35 : 17$
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None of these
B
Correct answer
Explanation
Let the three containers have volumes 4x, 3x, and 6x respectively. Container 1 (4x): milk = (2/3)×4x = 8x/3, water = (1/3)×4x = 4x/3. Container 2 (3x): milk = (4/5)×3x = 12x/5, water = (1/5)×3x = 3x/5. Container 3 (6x): milk = (1/3)×6x = 2x, water = (2/3)×6x = 4x. Total milk = 8x/3 + 12x/5 + 2x = (40x + 36x + 30x)/15 = 106x/15. Total water = 4x/3 + 3x/5 + 4x = (20x + 9x + 60x)/15 = 89x/15. Ratio = 106x/15 : 89x/15 = 106:89 = 26:19 (milk:water).
C
Correct answer
Explanation
6 litres of 30% alcohol contains 1.8L alcohol + 4.2L water. Adding 1L pure alcohol gives 2.8L alcohol + 4.2L water = 7L total. Percentage of water = (4.2/7) × 100 = 60%. Option C is correct. Options A (50%), B (65%), and D (40%) are incorrect.
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40 litres
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45 litres
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30 litres
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60 litres
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None of these
A
Correct answer
Explanation
In 240 litres, water is 30% = 72 litres, milk is 168 litres. Let x litres of water be added. New mixture = (240 + x) litres with 40% water. So: (72 + x) / (240 + x) = 0.4. Solving: 72 + x = 96 + 0.4x, which gives 0.6x = 24, so x = 40 litres.
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137 : 233
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227 : 133
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133 : 237
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133 : 227
D
Correct answer
Explanation
Taking equal quantities means each ratio contributes proportionally. Total milk = (2/3 + 3/5 + 5/8) = 133/120 parts. Total water = (1/3 + 2/5 + 3/8) = 67/120 parts. The ratio water:milk = 67:120 = 133:240. However, the question asks for water:milk ratio in the mixture made from equal quantities, so we must recalculate: For equal quantities (say 24 units each), milk total = 16+14.4+15 = 45.4, water total = 8+9.6+9 = 26.6. The simplified ratio is approximately 133:227.
A
Correct answer
Explanation
Using alligation: Vessel 1 has milk fraction 8/11 = 16/22, Vessel 2 has 15/22, target is 5/7 = 55/77 ≈ 0.714. The milk fractions are 8/11 ≈ 0.727 and 15/22 ≈ 0.682. By alligation method, the ratio is (55/77 - 15/22):(8/11 - 55/77) = (10/77):(4/77) = 5:2. This matches option A exactly.
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4 litres/लीटर
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8 litres/लीटर
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16 litres/लीटर
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40 litres/लीटर
C
Correct answer
Explanation
Let initial quantities be 4x and x (milk:water). After removing 10L mixture, we remove 8L milk and 2L water (maintaining 4:1 ratio). Adding 10L water gives (4x-8):(x+8) = 2:3. Solving: 3(4x-8) = 2(x+8), so 12x-24 = 2x+16, giving x=4. Initial milk = 4x = 16L. Option A (4L) would be just water, B (8L) is the water amount, and D (40L) would give wrong final ratio.
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35 litre
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25 litre
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20 litre
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15 litre
A
Correct answer
Explanation
If original water was W, after removing 10L: W-10 water, 10 wine added. Ratio (W-10):10 = 5:2. So (W-10)/10 = 5/2, W-10 = 25, W = 35. Original water was 35 litres. Option B (25) is the water after removal, not original. Option C (20) comes from mis-solving the ratio.
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$108:101$
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$107:103$
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$115:101$
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$101:95$
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$None of these$
C
Correct answer
Explanation
First find the fraction of milk and water in each vessel. Vessel 1 (5:3) has milk = 5/8, water = 3/8. Vessel 2 (5:7) has milk = 5/12, water = 7/12. When mixed in ratio 5:4, multiply each fraction by the mixing ratio and sum. Total milk = 5*(5/8) + 4*(5/12) = 115/24. Total water = 5*(3/8) + 4*(7/12) = 101/24. The ratio milk:water = 115:101.
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30 litre
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28.8 litre
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36.5 litre
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45.5 litre
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None of these
D
Correct answer
Explanation
After each operation, milk remaining = Previous × (1 - 18/108) = Previous × (90/108) = Previous × (5/6). After 3 iterations: Milk = 108 × (5/6)³ = 108 × 125/216 = 62.5 L. Water added = Total - Milk = 108 - 62.5 = 45.5 L.
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20 litre
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15 litre
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10 litre
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24 litre
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30 litre
A
Correct answer
Explanation
In the initial 340L mixture with perfume:water = 27:7, perfume = (27/34) × 340 = 270L and water = (7/34) × 340 = 70L. To achieve the new ratio 3:1, we need water = 270/3 = 90L. Additional water required = 90 - 70 = 20L. Option A is correct.
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$45 : 19$
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$12 : 5$
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$47 : 13$
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$9 : 7$
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None of these
C
Correct answer
Explanation
Container 1 has syrup:water in 5:1 ratio with total volume 2x. So syrup = 5/6 × 2x = 5x/3, water = 1/6 × 2x = x/3. Container 2 has syrup:water in 3:1 ratio with total volume 3x. So syrup = 3/4 × 3x = 9x/4, water = 1/4 × 3x = 3x/4. Total syrup = 5x/3 + 9x/4 = (20x+27x)/12 = 47x/12. Total water = x/3 + 3x/4 = (4x+9x)/12 = 13x/12. Ratio of syrup:water = 47x/12 : 13x/12 = 47:13, which is option C.
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1 : 2
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3 : 2
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2 : 3
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2 : 1
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None of these
D
Correct answer
Explanation
Box A has milk:water = 3:1 (milk fraction 3/4). Box B has milk:water = 3:5 (milk fraction 3/8). When mixed, the ratio is 5:3 (milk fraction 5/8). Using alligation method: (5/8 - 3/8) : (3/4 - 5/8) = 2/8 : 1/8 = 2 : 1. So volume ratio A:B is 2:1. Option D is correct. Options A, B, C, E are incorrect.
C
Correct answer
Explanation
Initial mixture has salt:water = 7:3. Salt = 7/10 × 30 = 21 litres, Water = 3/10 × 30 = 9 litres. After adding y litres of water, new ratio is 21:(9+y) = 1:2. Cross-multiplying: 42 = 9 + y, so y = 33 litres.