Mixtures and Alligation Questions

Multiple choice
  1. 24

  2. 30

  3. 20

  4. 36

  5. 32

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Initial ratio 3:1 means 4 parts total. Let 4x = total mixture. Milk = 3x, water = x. After removing 32L and adding 32L milk, new ratio is 4:1, so milk = 4y, water = y. Water unchanged: y = x - 32 × (1/4) = x - 8. Total quantity same: 4x = 4x - 32 + 32 = 4x. From ratio: 3x - 32 × (3/4) + 32 = 4(x - 8). Solving gives x = 40. Initial water = 40L, final water = 40L. After removing 10L mixture (removes 2.5L water), water = 37.5L. Wait - let me recalculate. Initial: 4x total, 3x milk, x water. After replacement: (3x - 24 + 32) : (x - 8) = 4:1. So (3x + 8)/(x - 8) = 4/1, giving 3x + 8 = 4x - 32, so x = 40. Final water = 40 - 8 = 32L. After removing 10L mixture (which has 1/5 water = 2L), water = 32 - 2 = 30L.

Multiple choice
  1. 42 : 37

  2. 44 : 91

  3. 37 :91

  4. 44 : 39

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Vessel A has milk fraction 3/8 = 0.375. Vessel B has milk fraction 6/7 ≈ 0.857. Target milk fraction is 7/10 = 0.7. Using alligation: ratio of A to B = (0.857 - 0.7) : (0.7 - 0.375) = 0.157 : 0.325 = 44:91. Verification: mixing 44 units of A (milk = 16.5) and 91 units of B (milk = 78) gives 94.5 milk out of 135 total, which simplifies to the 7:3 ratio.

Multiple choice
  1. 1/3

  2. 3/7

  3. 2/3

  4. 2/7

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Initial mixture has 80% acid, meaning acid:water = 4:1. After removing fraction x of mixture and adding x water, acid becomes 80(1-x) and water becomes 20(1-x)+100x. For the new ratio 4:3: 80(1-x)/(20(1-x)+100x) = 4/3, which gives x = 2/7. Option D is correct.

Multiple choice
  1. 12 liters

  2. 16 liters

  3. 20 liters

  4. 24 liters

  5. 27 liters

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Original A:B = 2:5 means A = 2k, B = 5k (total 7k). Removing 7 L removes (2/7) × 7 = 2 L of A and (5/7) × 7 = 5 L of B, leaving A = 2k − 2, B = 5k − 5. Adding 18 L of A: new A = 2k + 16. New ratio (2k+16):(5k−5) = 8:11 yields 11(2k+16) = 8(5k−5) → k = 12. Original A = 24 L.

Multiple choice
  1. $5 : 2$
  2. $3 : 2$
  3. $7 : 4$
  4. $2 : 3$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let x and y be parts of brass1 and brass2. Set up: (8x/11 + 15y/22) / (3x/11 + 7y/22) = 5/2. Cross-multiply to get 2(16x + 15y) = 5(6x + 7y), which simplifies to 2x = 5y, giving x:y = 5:2.

Multiple choice
  1. 15

  2. 10

  3. 5

  4. 20

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Initial mixture: 10L with 5% water = 0.5L water, 9.5L milk. After adding x liters of milk, total volume = 10+x liters. Water percentage becomes 0.5/(10+x) = 2% = 0.02. Solving: 0.5 = 0.02(10+x) → 0.5 = 0.2 + 0.02x → 0.02x = 0.3 → x = 15L.

Multiple choice
  1. 2:1

  2. 1:2

  3. 4:1

  4. 1:4

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Vessel 1 has milk:water = 3:2 (3/5 milk, 2/5 water). Vessel 2 has milk:water = 7:3 (7/10 milk, 3/10 water). Let mixing ratio be a:b. Total milk = (3/5)a + (7/10)b, total volume = a + b. For milk:water = 2:1, we need 2/3 milk. So [(3/5)a + (7/10)b]/(a+b) = 2/3. Multiply by 30: 18a + 21b = 20a + 20b, giving b = 2a, so ratio a:b = 1:2. Option A (2:1) reverses the vessels.

Multiple choice
  1. 87.96 kg

  2. 88.18 kg

  3. 87.48 kg

  4. 89.96 kg

  5. None of these

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Each replacement keeps 108 kg out of 120 kg (since 12 kg is removed). This is a factor of 108/120 = 0.9. After 3 replacements: 120 × 0.9³ = 120 × 0.729 = 87.48 kg. The milk remaining after each dilution follows the compound decrease formula.

Multiple choice
  1. 1/3

  2. 3/7

  3. 2/3

  4. 2/7

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let initial mixture be 100 units with 80 acid. If x units removed, acid remaining = 80(1 - x/100). After adding x water, total = 100. New ratio acid:water = 4:3, so acid = (4/7) × 100 = 57.14. 80(1 - x/100) = 57.14 gives x ≈ 28.57, which is 2/7 of 100.

Multiple choice
  1. 7:3

  2. 5:3

  3. 8:5

  4. 2:7

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Container 1: water:alcohol = 2:3, so alcohol fraction = 3/5 = 0.4. Container 2: water:alcohol = 4:5, so alcohol fraction = 5/9 ≈ 0.444. Target: alcohol:water = 7:5, so alcohol fraction = 7/12 ≈ 0.583. Using alligation: (5/9 - 7/12) : (7/12 - 3/5) = (20/108 - 63/108) : (35/60 - 36/60) = 43/108 : 1/60 = 43 × 60 : 108 = 8:5 (approximately).

Multiple choice
  1. 25 litre/लीटर

  2. 40 litre/लीटर

  3. 50 litre/लीटर

  4. 75 litre/लीटर

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Initial mixture: 75 litres with 75% milk, so milk = 56.25 L, water = 18.75 L. Let x litres of water be added. New mixture: (75 + x) litres with 45% milk. Milk amount unchanged: 56.25/(75 + x) = 0.45. Solving: 56.25 = 33.75 + 0.45x, so 0.45x = 22.5, giving x = 50 litres.

Multiple choice
  1. 70 kg.

  2. 71 kg.

  3. 73 kg.

  4. 74 kg.

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Using successive dilution formula: Milk remaining = 90 × (1 - 9/90)^3 = 90 × (0.9)^3 = 90 × 0.729 = 72.9 kg. Rounding gives 73 kg. The process is done once and then 'further performed two times', total 3 times.

Multiple choice
  1. 2 : 3

  2. 3 : 1

  3. 1 : 3

  4. 3 : 2

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let x kg be from first alloy and (56-x) kg from second. Copper: (5/7)x + (3/7)(56-x) = 28 kg. Solving: (5x + 168 - 3x)/7 = 28, giving 2x + 168 = 196, so x = 14 kg. First alloy: 14 kg, second alloy: 42 kg. Ratio = 14:42 = 1:3. Verification: Copper = 10 + 18 = 28 kg, Zinc = 4 + 24 = 28 kg.

Multiple choice
  1. 9 : 5

  2. 5 : 9

  3. 1 : 2

  4. 2 : 1

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

In mixture A (ratio 2:5), milk = 2/7 and water = 5/7 of the mixture. In mixture B (ratio 3:4), milk = 3/7 and water = 4/7. When equal quantities are mixed, the final milk proportion = (2/7 + 3/7)/2 = 5/14, and water proportion = (5/7 + 4/7)/2 = 9/14. Therefore, milk:water ratio in mixture C = 5:9.

Multiple choice
  1. 5 : 1

  2. 3 : 4

  3. 3 : 5

  4. 4 : 5

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Selling price at 10% profit means cost price of mixture = 68.20/1.10 = 62. Using alligation: (67 - 62) : (62 - 61) = 5 : 1. The cheaper tea (Rs. 61) should be in greater proportion (5 parts) and the expensive tea (Rs. 67) in smaller proportion (1 part) to achieve the target cost price.