Mensuration Questions

Multiple choice
  1. Statement (1) alone is sufficient, but statement (2) alone is not sufficient.

  2. Statement (2) alone is sufficient, but statement (1) alone is not sufficient.

  3. Both statements (1) and (2) together are sufficient, but neither of them alone is sufficient.

  4. Both the statements alone are sufficient.

  5. Both statements (1) and (2) together are not sufficient.

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Perimeter = 2(L+B) = 320, so L+B = 160. Statement 1: L = 1.6667B = 5/3 B. 5/3 B + B = 160 -> 8/3 B = 160 -> B=60, L=100. Area = 6000. Statement 2: Area = 6000. Both allow finding dimensions and thus cost.

Multiple choice
  1. A

  2. B

  3. C

  4. D

  5. E

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Statement II provides the radius of the sphere (since surface area of a sphere is 4*pi*r^2 and two hemispheres have total surface area 3*pi*r^2 = area of circle with radius 21, which is pi*21^2). This allows calculation of the volume. Statement I involves a cylinder with unknown dimensions, so it is insufficient.

Multiple choice
  1. Quantity : I > Quantity : II

  2. Quantity : I ≥ Quantity : II

  3. Quantity : I < Quantity : II

  4. Quantity : II ≥ Quantity : I

  5. Quantity I = Quantity II or relation can't be established

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Quantity I: TSA of cone = pi*r*(r+l) = 1848. With l = r + 25, pi*r*(2r+25) = 1848. Solving for r gives r=14, l=39, h=sqrt(39^2-14^2)=sqrt(1325) approx 36.4. Volume I approx 7470. Quantity II: Sphere volume = 310464 = 4/3*pi*R^3, so R^3 = 74088, R=42. Cylinder h=42, r=28. Volume II = pi*28^2*42 approx 103683. Thus I < II.

Multiple choice
  1. 1025 and 8 minutes and 25 seconds.

  2. 2050 and 15 minutes and 45 seconds.

  3. 2070 and 17 minutes and 15 seconds.

  4. 1035 and 8 minutes and 37.5 seconds.

  5. 465 and 3 minutes and 47.5 seconds.

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Volume of cuboid = l * l * 3.14l = 3.14l^3. Volume of cube = l^3. Total volume = 4.14l^3. Half volume = 2.07l^3. Jugs needed = 2.07l^3 / 0.001l^3 = 2070. Time = 2070 * 0.5 seconds = 1035 seconds = 17 minutes and 15 seconds.

Multiple choice
  1. Rs. 3,16,80,000

  2. Rs. 4,25,60,000

  3. Rs. 6,33,60,000

  4. Rs. 7,42,80,000

  5. Rs. 2,98,20,000

Reveal answer Fill a bubble to check yourself
A Correct answer
Multiple choice
  1. Statement (1) alone is sufficient, but statement (2) alone is not sufficient.

  2. Statement (2) alone is sufficient, but statement (1) alone is not sufficient.

  3. Both statements (1) and (2) together are sufficient, but neither statement alone is sufficient.

  4. Each statement alone is sufficient.

  5. Statements (1) and (2) together are not sufficient.

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Surface area of a cone = pi*r*(r + l). We need both radius (r) and slant height (l). Statement 1 gives r, Statement 2 gives l. Both are needed.

Multiple choice
  1. Quantity I > Quantity II

  2. Quantity I < Quantity II

  3. Quantity I ≥ Quantity II

  4. Quantity I ≤ Quantity II

  5. Quantity I = Quantity II or relationship cannot be established

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let width be w, length be w+6. Area = w(w+6) = w^2 + 6w. Perimeter = 2(2w+6) = 4w+12. Given w^2 + 6w = 5(4w+12) + 60 => w^2 + 6w = 20w + 120. w^2 - 14w - 120 = 0 => (w-20)(w+6) = 0. So w=20, l=26. Quantity I: (20+5)(26-1) = 25*25 = 625. Quantity II: 26(20+4) = 26*24 = 624. 625 > 624.

Multiple choice
  1. 3,66,000

  2. 2,27,000

  3. 2,70,000

  4. 3,60,000

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let length be L and width be W. Area LW = 135000. Cost = 300L + 150L + 150W + 150W = 450L + 300W. To minimize, use AM-GM: 450L + 300W >= 2 * sqrt(450L * 300W) = 2 * sqrt(135000 * 135000) = 2 * 135000 = 270000.

Multiple choice
  1. The data in statement I alone is sufficient to answer the question, while the data in statement II alone is not sufficient to answer the question

  2. The data in statement II alone is sufficient to answer the question, while the data in statement I alone is not sufficient to answer the question

  3. The data either in statement I alone or in statement II alone is sufficient to answer the question

  4. The data given in both statements I and II together are not sufficient to answer the question

  5. The data given in both statements I and II together are necessary to answer the question.

Reveal answer Fill a bubble to check yourself
D Correct answer
Multiple choice

Passage

Directions: Read the information carefully to answer the question that follows. The premises of a school are to be renovated. The renovation is in terms of flooring. Certain areas are to be floored either with marble or wood. All classrooms/halls and pantry are rectangular. The area to be renovated comprises of a big hall measuring 25 m × 25 m, principal's room measuring 13 m × 17 m, a pantry measuring 14 m × 13 m, a recordkeeping cum server room measuring 21 m × 13 m and locker area measuring 29 m × 21 m. The total area of the school is 2000 square metres. The cost of wooden flooring is Rs. 100 per square metre and the cost of marble flooring is Rs. 150 per square metre. The locker area, recordkeeping cum server room and pantry are to be floored with marble. The principal's room and the hall are to be floored with wood. No other area is to be renovated in terms of flooring.

If the remaining area of the school is to be carpeted at a rate of Rs. 110/- per square metre, then how much will be the increment in the total cost of renovation of school premises?

  1. Rs. 8900

  2. Rs. 9900

  3. Rs. 7900

  4. Rs. 8500

  5. None of these

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Renovated areas: Hall (625), Principal (221), Pantry (182), Server (273), Locker (609). Total renovated = 1910. Remaining area = 2000 - 1910 = 90. The question asks for the increment in cost for this remaining area if carpeted at 110/sqm. 90 * 110 = 9900.

Multiple choice

Passage

Directions: The question given below is followed by three statements (A), (B) and (C). You have to determine which statement(s) is/are sufficient/necessary to answer the question. Mark your answer as per these codes: (a) (A) and (B) together are sufficient. (b) Either (A) or (B) is sufficient. (c) Only (B) is sufficient. (d) Either (B) alone or (A) and (C) together are sufficient. (e) All are necessary to answer the given question.

The cost of flooring a rectangular plot is Rs. 30 per square metre and its area is 1/3rd the area of a circular field. What will be the total cost of flooring the rectangular plot? (A) The length of the rectangular plot is 42 m. (B) The diameter of the circular field is 42 m. (C) The breadth of the rectangular plot is 3 less than 1/3rd of its length.

  1. a

  2. b

  3. c

  4. d

  5. e

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

To find the cost, we need the area of the rectangular plot. We know Area_rect = 1/3 * Area_circle. Statement (B) gives the diameter of the circle, allowing us to find its area. Statement (A) gives the length of the rectangle. With area and length, we can find the breadth. Statement (C) provides a relationship between length and breadth. Using (B) and (C) is sufficient, or (A) and (B) is sufficient.

Multiple choice

Passage

Directions: Study the following information carefully and answer the given question. There is a solid cylinder of radius R cm and height h cm. The height of cylinder is 21 cm more than the radius of cylinder. The ratio of the total area of the solid cylinder to the curved surface area of cylinder is 3 : 2. This solid cylinder is cut along vertical axis in N equal pieces. Later it was found that the total surface area has increased by 5292 sq.cm.

Find the radius (R) of the cylinder.

  1. 35 cm

  2. 30 cm

  3. 42 cm

  4. 21 cm

  5. 28 cm

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let R be radius, h = R + 21. Total surface area (TSA) = 2*pi*R*(R+h) = 2*pi*R*(2R+21). Curved surface area (CSA) = 2*pi*R*h = 2*pi*R*(R+21). Ratio TSA/CSA = (2R+21)/(R+21) = 3/2. Solving gives 4R + 42 = 3R + 63, so R = 21.

Multiple choice

Passage

Read the following information carefully to answer the questions Rohit have some articles which are in the form of different structures. These are cylindrical, conical, and spherical. Other than solid conical structure, all two are of both types i.e., hollow as well as solid. Volume of a conical article is three times of the volume of a solid cylindrical article while radius of a solid spherical article is half than that the radius of a conical article. Outer radius of hollow cylindrical article is same as radius of solid spherical article while average of outer radius and inner radius of hollow cylindrical article is equal to radius of solid cylindrical article. Height of cylindrical, conical and hollow cylindrical article is same i.e. 14cm Number of solid spherical article is 1/5 of total number of article Rohit have. Number of hollow spherical article is 150% more than number of conical article. Ratio between numbers of solid cylindrical article to number of conical article is 3:2. Total number of hollow cylindrical article is 40% of total numbers of article Rohit have and also ‘20’ more than the total number of solid spherical article Rohit have. Volume of a hollow spherical article is 33,957 cm 3 whose inner radius is half of its outer radius. Volume of a hollow spherical article is 5.25 time of volume of conical article.

Find the curved surface area of one hollow cylindrical article?

  1. 661 cm2

  2. 1232 cm2

  3. 826 cm2

  4. 521 cm2

  5. 1016 cm2

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Curved surface area of hollow cylinder = 2πRh, where R is outer radius and h is height. The inner surface is not counted in 'curved surface area'. With given dimensions, this equals 1232 cm².

Multiple choice

Passage

In the given questions, two quantities are given, one as ‘Quantity 1’ and another as ‘Quantity 2’. You have to determine relationship between two quantities and choose the appropriate option:

Quantity I: The diagonal of the square is 24√2 cm. The area of the square is? Quantity II: The perimeter of the square is 96 cm. Then the area of the square is?

  1. Quantity I> Quantity II

  2. Quantity I< Quantity II

  3. Quantity II ≥ Quantity I

  4. Quantity II ≤ Quantity I

  5. Quantity I = Quantity II or Relation cannot be established

Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Quantity I: Diagonal = 24√2 cm. For a square, diagonal = a√2, so a = 24 cm. Area = a² = 576 cm². Quantity II: Perimeter = 96 cm, so 4a = 96 and a = 24 cm. Area = a² = 576 cm². Both quantities equal 576 cm², so the relationship is 'Quantity I = Quantity II' (or E: cannot be established when E means equal).

Multiple choice
  1. Quantity I > Quantity II

  2. Quantity I ≥ Quantity II

  3. Quantity II > Quantity I

  4. Quantity II ≥ Quantity I

  5. Quantity I = Quantity II or Relation cannot be established

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Quantity I: Square area = 7200, so rectangle area = 7200/4 = 1800. Length:breadth = 9:8, so dimensions are 45×40. Sum = 85cm. Quantity II: Tank area = 300×488 = 146400. Remaining area = 12000, so circle area = 146400 + 12000 = 158400. Using πr² = 158400, r = √(158400/π) ≈ 224.5cm. Since 85 < 224.5, Quantity II > Quantity I, so answer is C.