Multiple choice

Directions: A solid consists of a cuboid having length and breadth each equal to 'l' m and the height of the cuboid is 3.14l m. This cuboid is surmounted on a cubical solid of side 'l' m. If it takes around 1 cylindrical jug to fill 0.001 l3 m3. How many jugs would be needed to fill half of the volume of the whole solid. Also, find out how much time it would take to fill the half of the whole volume, if it fills 0.001 l3 m3 in 0.5 seconds.

  1. 1025 and 8 minutes and 25 seconds.

  2. 2050 and 15 minutes and 45 seconds.

  3. 2070 and 17 minutes and 15 seconds.

  4. 1035 and 8 minutes and 37.5 seconds.

  5. 465 and 3 minutes and 47.5 seconds.
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Volume of cuboid = l * l * 3.14l = 3.14l^3. Volume of cube = l^3. Total volume = 4.14l^3. Half volume = 2.07l^3. Jugs needed = 2.07l^3 / 0.001l^3 = 2070. Time = 2070 * 0.5 seconds = 1035 seconds = 17 minutes and 15 seconds.

AI explanation

The total volume of the solid is found by adding the cuboid volume of 3.14l^3 and the cube volume of l^3, giving 4.14l^3, so half of this volume is 2.07l^3. Dividing this half volume by the jug capacity of 0.001l^3 shows that 2070 jugs are needed. Since filling 0.001l^3 takes 0.5 seconds, filling 2.07l^3 takes 1035 seconds, which is 17 minutes and 15 seconds.

Keep practicing — related questions