Quantitative Aptitude · Mathematics

Mensuration and Costing

74 Questions

Mensuration and costing questions combine geometric calculations with practical expenses like painting, fencing, and carpeting. They are highly relevant for quantitative aptitude tests in SSC and state exams. Solving these requires accuracy in applying area and volume formulas.

painting and plastering costfencing and levelingsurface area calculationvolume of solids

Mensuration and Costing Questions

Multiple choice

What will be the total cost of flooring and painting of master bedroom?

Directions: Study the following information and answer the question that follows.

A house is to be constructed which will have a master bedroom, a guest room, a children room, a kitchen, a drawing room, a living room and bathrooms attached to the master bedroom and the drawing room. The height of all the rooms is supposed to be 14 m. The area of the house comprises of the master bedroom measuring 15 m x 12 m, the guest room measuring 12 m x 12 m, the children room measuring 9 m x 12 m, the kitchen measuring 12 m x 6 m, the drawing room measuring 15 m x 15 m, the living room measuring 13 m x 13 m and bathrooms measuring 8 m x 7 m. The rooms, if they have area less than 100 sq. m, are to be painted with plastic paint and floored with vitrified tiles. The rooms with area greater than 100 sq. m are to be painted with rich textured emulsion and floored with marble. The rate of marble flooring is Rs. 300 per sq. m and that of vitrified tiles is Rs. 150 per sq. m. The price of painting with plastic paint is Rs. 120 per sq. m and that with rich textured emulsion is Rs. 280 per sq. m. No ceiling is to be painted unless asked in the question.

  1. Rs. 117720

  2. Rs. 238680

  3. Rs. 159840

  4. Rs. 265580

  5. Rs. 265680
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Flooring area of master bedroom = 15 m x 12 m = 180 sq. m x Marble flooring at Rs. 300 per sq. m = Rs. 54000. Painting area of master bedroom = 15 m x 14 m (Height of the room) x 2 (Two walls of the same size) + 12 m x 14 m (Height of the room) x 2 (Two walls of the same size) = 420 sq. m + 336 sq. m = 756 sq. m x Cost of rich textured emulsion at Rs. 280 per sq. m = Rs. 211680 Hence, total cost of flooring and painting = Rs. 54000 + Rs. 211680 = Rs. 265680

Multiple choice

What is the ratio of expenditure on plastic paint to that of rich textured emulsion paint?

Directions: Study the following information and answer the question that follows.

A house is to be constructed which will have a master bedroom, a guest room, a children room, a kitchen, a drawing room, a living room and bathrooms attached to the master bedroom and the drawing room. The height of all the rooms is supposed to be 14 m. The area of the house comprises of the master bedroom measuring 15 m x 12 m, the guest room measuring 12 m x 12 m, the children room measuring 9 m x 12 m, the kitchen measuring 12 m x 6 m, the drawing room measuring 15 m x 15 m, the living room measuring 13 m x 13 m and bathrooms measuring 8 m x 7 m. The rooms, if they have area less than 100 sq. m, are to be painted with plastic paint and floored with vitrified tiles. The rooms with area greater than 100 sq. m are to be painted with rich textured emulsion and floored with marble. The rate of marble flooring is Rs. 300 per sq. m and that of vitrified tiles is Rs. 150 per sq. m. The price of painting with plastic paint is Rs. 120 per sq. m and that with rich textured emulsion is Rs. 280 per sq. m. No ceiling is to be painted unless asked in the question.

  1. 56 : 9

  2. 9 : 56

  3. 8091 : 50176

  4. 99 : 896

  5. 161280 : 1003520
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Rooms to be painted with Plastic Paint's are Kitchen and the two bathrooms. Hence, total cost of plastic paint = Paint cost of Kitchen + Paint cost of two bathrooms. = Rs.60480 + Rs.100800 = Rs.161280.Rooms to be painted with rich textured emulsion paint's are Master Bedroom, Guest room, Children room, Drawing room and living room. Hence, total cost of rich textured emulsion paint = Paint cost of Master bedroom + Paint cost of Guest room + Paint cost of children room + Paint cost of Drawing room + Paint cost of living room. = Rs.211680 + Rs.188160 + Rs.164640 + Rs.235200 + Rs.203840 = Rs.1003520.So, the ratio of expenditure on Plastic Paint to Rich textured emulsion paint = 161280:1003520 = 9:56.

Multiple choice

If a table top is to be polished at the rate of Rs. 12 per sq. cm, then how much will it cost to polish a table top with dimensions 34 cm * 15 cm?

  1. Rs. 6100

  2. Rs. 1176

  3. Rs. 6120

  4. Rs. 42.5

  5. Rs. 12006
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Length of the table top = 34 cm Breadth of the table top = 15 cm Area of the table top to be polished = length * breadth                                                         = 34 cm * 15 cm                                                       = 510 sq.cm Cost of polishing 1 sq.cm area = Rs. 12  Cost of polishing 510 sq.cm = Rs.(12 * 510) = Rs. 6120

Ans. Rs. 6120

Multiple choice

A window frame 4 m long and 2 m wide is installed in a wall that has length 15 m and breadth 10 m. What will be the total cost of painting the wall if it costs Rs. 3.50 for 1 square metre?

  1. Rs. 497

  2. Rs. 500

  3. Rs. 553

  4. Rs. 133

  5. Rs. 450
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

This is the right answer because:- Length of the window frame = 4m Breadth of the window frame = 2m Area of the window frame = Length * Breadth = 4m * 2m => 8 square meters Length of the wall = 15 m Breadth of the wall = 10 m Area of the wall = Length * Breadth                      = 15 m * 10 m                      =>150 square meters Area to be painted = Area of wall -Area of window frame                                   = 150 sq. m - 8 sq.m                                  = 142 sq.m Cost of painting 1 sq. m = Rs. 3.50 Cost of painting 142 sq.m = Rs. 142 * 3.50                                                 => Rs.497

Ans. Rs. 497

Multiple choice

Sapna is standing on a rectangular floor with a breadth of 50 m. She decides to get it covered with marble tiles. How many tiles would be required to cover the floor area of 45000 sq. m, if each tile measures 50 m x 5 m?

  1. 56 tiles

  2. 175 tiles

  3. 180 tiles

  4. 192 tiles

  5. 900 tiles
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Length of the tile = 50 m Breadth of the tile = 5 m Area of each tile = Length x breadth             =>50 m x 5 m             =250 sq. m Area to be covered = 45000 sq. m Number tiles of required = Area to be covered /Area of each marble tile                                              = 45000/250                                              = 180 tiles

Multiple choice maths area of complex plane figures 2d and 3d figures

Size of a tile is $9$ inches by $9$ inches. The number of tiles needed to cover a floor of $12$ feet by $18$ feet is

  1. $384$
  2. $32$
  3. $24$
  4. $216$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Number of tiles$\displaystyle =\dfrac{Area\, of\, floor}{Area\, of\, 1 tile}$


$\displaystyle =\dfrac{12\times 12\times 18\times 12}{9\times 9}=384$

Multiple choice maths measurement (length) conversion of length using decimals in units of length define weight and units of weight how much does it weigh?

Expenditure incurred in cultivating a square field at the rate of Rs. $170$ per hectare is Rs. $680$. What would be the cost of fencing the field at the rate of Rs. $3$ per meter?

  1. Rs. $2400$
  2. Rs. $3600$
  3. Rs. $3000$
  4. Rs. $2000$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
Total cost of cultivation$=$Rs.$680$
Cost per hectare$=$Rs. $170$
$\therefore $Area of cultivation$=\cfrac { 680 }{ 170 } =4$ hectare$=4\times { 10 }^{ 4 }m^2$
Now, field's shape is square, therefore area $=side \times side$
$\Rightarrow 4\times { 10 }^{ 4 }={ (side) }^{ 2 }$
$\Rightarrow $ side$=\sqrt { 4\times { 10 }^{ 4 } } =200m$
Perimeter of field$=4\times 200=800m$
$\therefore $ Cost of fencing $800m=$ Rs.$\left( 3\times 800 \right) =$ Rs.$2400$
Multiple choice maths how big? how heavy? measuring volume volume of solids volume of cube and cuboid

A wall of length $10$ m was to be built across an open ground. The height of the wall is $4$ m and thickness of the wall is $24$ cm. If this wall is to be built up with bricks whose dimensions are $24$ cm $\times 24$ cm $\times 24$ cm, how many bricks would be required?

  1. $500$
  2. $556$
  3. $695$
  4. $704$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Since the thickness of wall and brick is same, we only need to figure out the area of the wall, which on dividing with the area of brick will give us the number of bricks.

But the standard procedure lies 
Number of Bricks$=\quad \dfrac { Volume\ of\ wall }{ Volume\ of\ brick } =\dfrac { 10\times 4\times 0.24\ m^{ 3 } }{ 0.24\times 0.24\times 0.24\ m^{ 3 } } =694.44$


Closest integer is taken as answer because come as a whole , so, $695$ is the answer.

Multiple choice maths perimeter and area of rectilinear figures region enclosed by a plane figure area of square and rectangle mensuration-i (area)

The length and breadth of a room are in the ratio of 3 : 2. Its height is equal to half of its length. If the cost of carpeting the floor at Rs. 4.00 per m$^2$ is Rs. 216, then the area offour walls (in m$^2$) is

  1. 135

  2. 140

  3. 125

  4. 120
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let the length and breadth be 2x and 3x respectively. Then, floor area $= 6x^2$ sq.m. 
Cost of flooring at the rate of Rs. 4.00 per $m^2 = $ Rs. 216
$\therefore 6x^2 \times 4 = 216$
or $x^2 = 9$
or $x = 3$
$\therefore $ Length = 3x = 9m
Breadth = 2x = 6m
and Height $= \displaystyle \frac{1}{2} \times$ Length = 4.5 m
$\therefore $ Area of four walls = 2(length $\times$ height + breadth $\times$ height)
$=2 [9 \times 4.5 + 6 \times 4.5] = 135 m^2$

Multiple choice maths perimeter and area converting between units of areas the metric system metric system

The area of a square playground is $256.6404$ square metres. Find the length of one side of the playground.

  1. $16.04$ metres
  2. $16.02$ metres
  3. $16.06$ metres
  4. $16.08$ metres
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let side of square play ground be x

Then area of square play ground will be $x^2$
According to question

$x^2 = 256.6404 m^2$

$x = \sqrt{256.6404} m$

$x = \dfrac{\sqrt{2566404}}{\sqrt{10000}} m$

$= \dfrac{1602}{100}$

Hence side of square is $16.02 m$

Option (B)