Chemistry
Coordination Chemistry
325 Questions
Coordination chemistry focuses on coordination compounds, their structures, and their magnetic properties. The questions cover primary and secondary valencies, ligand types, and geometries of complexes. This topic is heavily tested in chemistry competitive exams and requires a good grasp of molecular structures.
primary and secondary valencycomplex geometriesligand field theorymagnetic properties of complexesisomerism in complexes
Coordination Chemistry Questions
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co-ordination sphere
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chelates
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central metal atom or ion
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complex ion
B
Correct answer
Explanation
Bidentate ligands are often referred to as chelating ligands because they can grab a metal atom in two places. A complex that contains a chelating ligand is called a chelate.
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cationic complex
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anionic complexes
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neutral complex
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None of these
B
Correct answer
Explanation
These complexes carry a negative charge. For example: [Ag (CN)2]-
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[Cr(NH3)6]+3
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[Fe(CN)6] -3
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[Ni(CN)4]2-
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[Fe(CN)6]4-
C
Correct answer
Explanation
This complex is square planar in shape with hybridisation,dsp2 .It is diamagnetic because it has no unpaired electrons.
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XeF2, XeF4
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XeO3, XeO4
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XeF6, XeOF4
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XeO2F2, XeO3F2
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XeF2, XeO3F2
D
Correct answer
Explanation
This option is correct because both XeO2F2, XeO3F2 have the same trigonal bipyramidal structure.
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[Re2Cl8]--
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[Pt(Cl)2(PPh3)2]
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[Co(NH3)4Cl2]
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[Mn2(CO)10]
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None of these
A
Correct answer
Explanation
This option is correct, because two Re atoms have eight electrons will occupy one sigma. Two pi and one delta bonding to form quadruple bonds between two Re atoms, i.e., Re-Re distance short to exist eclipsed form.
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Closo
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Nido
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Hypho
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Arachno
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None of these
D
Correct answer
Explanation
This option is correct because in this carbonyl compound, total electron counts to be 62, and electron used for non skeletal bonding is 48. Therefore skeletal electron pair available for frame work bonding 1/2[62 - 48]=7e pairs, i.e., m = 4, hence occupies (4+3)e pairs, predicted in (m+4) rule.
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[V(CO)6]-
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[Ti(CO)6]--
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[Mn(CO)6]+
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[Cr(CO)6]
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None of these
B
Correct answer
Explanation
This option is correct, because the two excess electron of metal ions shifted towards antibonding MOs of CO ligand resulting CO bond order is very low, due to this fact infrared frequency highly decreases.
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[Mn(CN)2(NH3)4], [Fe(CN)3(H2O)3]
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K2[Co(Cl)2(OH)2(NH3)2], [Zn(H2O)2(Py)2(NO2)2]
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[V(C2H5O)2(en)2], [Ni(CN)2(NH3)4]
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[Fe(CN)3(NH3)3] [Cr(CO)3(Cl)3]
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Both 1 and 2
A
Correct answer
Explanation
This option is correct, because the central metal ions of both the compounds have same (five) unpaired electron in their d-orbitals, on basis of this fact both compounds show the same magnetic moment.
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[Co(NH3)5ONO]2+: pentaamminenitritocobalt(III) ion
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K3[Co(C2O4)3]: potassium trioxalatocobaltate(II)
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[Cr(NH3)6][IrCl6]: hexaamminechromium(III) hexachloroiridate(III)
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[Cr(H2O)5Br]SO4: pentaaquabromochromium(III) sulphate
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[Cu(H2O)4]SO4: tetraaquacopper(II) sulphate
B
Correct answer
Explanation
The correct IUPAC name of K3[Co(C2O4)3] complex is potassium trioxalatocobaltate(III).
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< 0.155 : 2- linear
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0.155 - 0.225 : 3- triangular planar
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0.225 – 0.414 : 4- tetrahedral
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0.414 – 0.732 : 4- square planar
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0.732 – 0.999 : 6- octahedral
E
Correct answer
Explanation
For coordination number 6 the shape is octahedral with limiting radius ratio of 0.414 – 0.732.
The radius ratio 0.732 – 0.999 is limiting for coordination number 8 with cubic shape.
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MnS, NiO, Fe, Co
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Fe, Co, MnO, MnS
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MnS, NiO, Co, Ni
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Fe, Co, Ni, CrO2
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Cr, MnO, MnS, NiO
D
Correct answer
Explanation
Fe, Co, Ni and CrO2 all are ferromagnetic elements/molecules.
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[Pt(NH3)4] [PtCl4] and [PtCl(NH3)3] [PtCl3(NH3)]
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[Co(NH3)6] [Cr(CN)6] and [Cr(NH3)6] [Co(CN)6]
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[Cr(H2O)6]Cl3 and [Cr(H2O)5Cl]Cl2.H2O
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[Co(NO2)(NH3)5]Cl2 and [Co(ONO)(NH3)5]Cl2
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[CoCl2(NH3)4]NO2 and [Co(Cl)(NO2)(NH3)4]Cl
E
Correct answer
Explanation
[CoCl2(NH3)4]NO2 and [Co(Cl)(NO2)(NH3)4]Cl both complexes are ionization isomers.
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[Cr(NH3)6]3+
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[Fe(CN)6]4-
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[Fe(CN)6]3-
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[FeF6]3-
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[Co(NH3)6]3+
A
Correct answer
Explanation
[Cr(NH3)6]3+ has d2sp3 hybridization and 3 lone pairs of electrons.
Hence, the coordination complex has d2sp3 hybridization and maximum number of lone pair of electrons (3).
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B2O3: 3 - plane triangular
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ZnS: 4 - tetrahedral
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NaCl: 6 - octahedral
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CsCl: 6 - octahedral
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CaF2: 8 - cubic
D
Correct answer
Explanation
CsCl has permitted coordination number of 8 with cubic arrangement.
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$e^1 t_2^0 $
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${t_{2g}}^0 {e_g}^1$
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$e^0{t_2}^1$
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${t_{2g}}^1 {e_g}^0$