Chemistry
Coordination Chemistry
319 Questions
Coordination chemistry focuses on coordination compounds, their structures, and their magnetic properties. The questions cover primary and secondary valencies, ligand types, and geometries of complexes. This topic is heavily tested in chemistry competitive exams and requires a good grasp of molecular structures.
primary and secondary valencycomplex geometriesligand field theorymagnetic properties of complexesisomerism in complexes
Coordination Chemistry Questions
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[Cr (NH3)6] Cl3
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[Cr (NH3)6] [CO (en)3]
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[CO (en)2 Cl2] Cl
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[COCl2 (en)2] SO4
B
Correct answer
Explanation
Coordination isomerism occurs when both the cation and anion are complex ions and ligands can be exchanged between them. [Cr(NH3)6][Co(en)3] fits this definition.
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[COF6]3-
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[CO (NH3)6]3+
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[Fe (CN)6]3-
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[Cr (NH3)6]3+
C
Correct answer
Explanation
[Fe(CN)6]3- involves a strong field ligand (CN-), which causes pairing of electrons, resulting in d2sp3 hybridization.
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sp3 hybidized
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dsp2 hybridized
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sp3 d hybridized
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sp3 d2 hybridized
B
Correct answer
Explanation
[Cu(NH3)4]2+ is a square planar complex, which corresponds to dsp2 hybridization for the central copper ion.
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Cr+2, Ti+3 and V+3
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Cu+2, Sc+3 and V+2
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Sc+3, Ti+4 and Zn+2
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Fe+2, Fe+3 and Co+2
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Ti+4, Ni+2 and Zn+2
C
Correct answer
Explanation
This option is correct because in this option, all metal ions are diamagnetic in nature due to absence of unpaired electrons.
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All are paramagnetic.
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All are diamagnetic.
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Sc(III) and Ti(IV) are paramagnetic and Pd(II) and Cu(II) are diamagnetic.
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Sc(III) and Ti(IV) are diamagnetic while Pd(II) and Cu(II) are paramagnetic.
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None of these
D
Correct answer
Explanation
This option is correct because the Sc(III) and Ti(IV) are diamagnetic while Pd(II) and Cu(II) are paramagnetic.
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primary valencies satisfied by anions only
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secondary valencies satisfied by the donor molecules
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coordination number
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all of these
D
Correct answer
Explanation
In coordination complexes, the central metal atom/ion exhibits primary valency (oxidation state) satisfied by anions and secondary valency (coordination number) satisfied by ligands (donor molecules). Since all these properties are characteristic of metal complexes, 'all of these' is correct.
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Fe3O4
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MgFe2O4
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MnO
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CrO2
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NaCl
C
Correct answer
Explanation
Substances like MnO showing antiferromagnetism have a domain structure similar to ferromagnetic substance, but their domains are oppositely oriented and cancel out each other's magnetic moment
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KMn(SO4)2. 12H2O
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KCr(SO4)2. 12H2O
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NH4Fe(SO4)2. 12H2O
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FeSO4.Al2(SO4)3. 24H2O
D
Correct answer
Explanation
Pseudo alum has the general formula MIISO4. M2III (SO4)3. 24H2O. So on comparing we get FeSO4.Al2(SO4)3.24H2O is pseudo alum.
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Only 1
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Only 2
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Only 3
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Both 1 and 2
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Both 2 and 3
A
Correct answer
Explanation
Coordination number of iron in cytochrome complex is 6. So, this is the correct answer.
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Only 1 and 3
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Only 2 and 4
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Only 1 and 2
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Only 2 and 3
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Only 3 and 4
A
Correct answer
Explanation
This option is correct because in the complexes [Fe(H2O)6]2+ and [CrF6]3-, the water and halogen are low field ligands, so both of them forms high spin complexes.
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[Co(en)3]3+
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[Co(H2O)6]3+
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[Co(CN)6]3-
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[Co(NH3)6]3+
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[CoCl6]3-
C
Correct answer
Explanation
This option is correct because CN- is one of the strongest field ligands. Crystal field splitting will be highest in [Co(CN)6]3-.
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Central metal atoms/ions in coordination complexes are Lewis acids.
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The secondary valency represents oxidation number of the central metal ion.
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Ligands are Lewis bases.
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Coordination number of cobalt in the compound [Co(ox)3]3- is 6.
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Oxidation number of cobalt in complex ion [CoCl2(en)2]+ is +3
B
Correct answer
Explanation
The secondary valency represents coordination number of the central metal ion.
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[PtCl4]2- and [ZnCl4]2-
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[Ni(CN)4]2- and [CoCl4]2-
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[ZnCl4]2- and [Ni(CN)4]2-
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[CoCl4]2- and [PtCl4]2-
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[PtCl4]2- and [Ni(CN)4]2-
E
Correct answer
Explanation
The d8 ions form square planar complexes with strong field ligands. For example [Ni(CN)4]2- .
All the complexes of Pt(II) and Au(II) are square planar. For example [PtCl4]2-
Thus, this option is correct.
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Only 1
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Only 2
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Only 3
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Only 2 and 3
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All of these
B
Correct answer
Explanation
- The complex has a square planar shape.
- CN- is a strong-field ligand.
- The d electron configuration for Ni2+ is d8.
- The splitting energy is large.
Therefore, the complex is low spin.
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Only 1 and 2
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Only 2 and 3
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Only 1 and 3
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Only 3
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All of these
D
Correct answer
Explanation
- The complex has an octahedral shape.
- F is a weak-field ligand.
- The d electron configuration for Fe3+ is d5.
- The splitting energy is small.
- Inner d orbitals will take part in hybridisation (sp3d2 hybridisation).
Therefore, the complex is outer orbital complex.