Coordination Chemistry

Geometrical isomerism requires different spatial arrangements of ligands. [CO(NH3)5NO2]Cl2 is an octahedral complex where all positions are occupied by NH3 or NO2, and it does not allow for cis/trans arrangements that result in distinct isomers.

[Cu(NH3)4]2+ has a dsp2 hybridization, which corresponds to a square planar geometry.

These complexes exhibit ionization isomerism because they produce different ions in solution (Br- vs SO4^2-).

In [Cr(H2O)4Cl2]+, the oxidation state of Cr is calculated as: Cr + 4(0) + 2(-1) = +1, so Cr = +3.

Coordination isomerism occurs when both the cation and anion are complex ions and ligands can be exchanged between them. [Cr(NH3)6][Co(en)3] fits this definition.

[Fe(CN)6]3- involves a strong field ligand (CN-), which causes pairing of electrons, resulting in d2sp3 hybridization.

[Cu(NH3)4]2+ is a square planar complex, which corresponds to dsp2 hybridization for the central copper ion.

this option is correct because , in case of homoneuclear molecule it is easy to calculate the magnetic character through molecular orbital theory . but in case of hetronuclear molecule one  easy method is there to find out the magnetic character . magnetic character in case of hetronuclear molecules . 1. count  the total number of valence electrons if it comes out to be even then it is dimagnetic otherwise paramagnetic . in this case Cl has 7 valence electrons and oxygen has 6 valence electrons . so total number of valence electrons is 7 + 6 x 2 = 19 , which is odd hence this molecule is paramagnetic . and this option is correct  .   

The capped square antiprismatic molecular geometry describes the shape of compounds where nine atoms, groups of atoms, or ligands are arranged around a central atom, defining the vertices of a gyroelongated square pyramid. Example is ReH₉^2-.

ReF₈^- has square antiprismatic molecular geometry (the shape of compounds where eight atoms, groups of atoms, or ligands are arranged around a central atom, defining the vertices of a square antiprism). W(CH₃)₆ has trigonal prismatic geometry (the shape of compounds where six atoms, groups of atoms, or ligands are arranged around a central atom, defining the vertices of a triangular prism). Na[CoCl₂(NH₃)₄] has octahedral geometry. SeF₄ has one lone pair of electrons with distorted trigonal bipyramidal shape. Hence, the representation of codes A - 2, B - 1, C - 4, D - 3 is correct.

This option is correct because in this option, all metal ions are diamagnetic in nature due to absence of unpaired electrons.

This option is correct because the geometry of SF₄ is see-saw due to the presence of 4 bond pairs and one lone pair of electrons (according to  VSEPR theory, its shape is seesaw), while the geometry of CCl₄ is tetrahedral.

This option is correct because the Sc(III) and Ti(IV) are diamagnetic while Pd(II) and Cu(II) are paramagnetic.

Substances like MnO showing antiferromagnetism have a domain structure similar to ferromagnetic substance, but their domains are oppositely oriented and cancel out each other's magnetic moment

  Pseudo alum has the general formula M^IISO₄. M₂^III (SO₄)₃. 24H₂O. So on  comparing we get FeSO₄.Al₂(SO₄)₃.24H₂O is pseudo alum.