Mathematics · Quantitative Aptitude
Algebraic Expressions and Polynomials
292 Questions
Algebraic expressions and polynomials form the foundation of algebra, involving variables, constants, and mathematical operations. This topic is heavily tested in the quantitative aptitude sections of SSC, banking, and state exams. Use these questions to practice expanding, factoring, and simplifying various polynomial expressions.
Expanding algebraic expressionsFactoring polynomialsAlgebraic identitiesFinding common factorsSimplifying numerical statements
Algebraic Expressions and Polynomials Questions
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One divided by the number of distinct values of a column.
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Zero divided by the number of distinct values of a column.
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Zero divided by the number of distinct values of a row.
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One divided by the number of distinct values of a Rrow.
A
Correct answer
Explanation
Filter factor (or selectivity) is a measure used by query optimizers to estimate the fraction of rows that satisfy a predicate. For an equality predicate on a column with a uniform distribution, it is calculated as 1 divided by the number of distinct values (NDV).
A
Correct answer
Explanation
The caret symbol (^) in many programming languages (including C, C++, Java, C#) represents the bitwise XOR operator. 14 in binary is 1110 and 23 is 10111. XORing these: 01110 XOR 10111 = 11001, which equals 25 in decimal. Note: Option C (6) would be the result if this were subtraction.
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1
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1+2
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3ABAC
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None of the above
B
Correct answer
Explanation
The FIELD function extracts a substring between two occurrences of a delimiter. FIELD("+1+2+3ABAC", "+", 2, 4) means: find the substring between the 2nd and 4th occurrences of "+". The delimiters are at positions: 1st at 0, 2nd at 2, 3rd at 4, 4th at 6. The substring between positions 2 and 4 is "1+2".
Let f (w, x, y, z) = $\sum$(0,4,5,7,8,9,13,15). Which of the following expressions is/are NOT equivalent to f?
P. x’y’z’ + w’xy’ + wy’z + xz
Q. w’y’z’ + wx’y’ + xz
R. w’y’z’ + wx’y’ + xyz + xy’z
S. x’y’z’ + wx’y’ + w’y
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P only
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Q and S
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R and S
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S only
Let f (w, x, y, z) = $\sum$(0,4,5,7,8,9,13,15). Which of the following expressions is/are NOT equivalent to f?
P. x’y’z’ + w’xy’ + wy’z + xz
Q. w’y’z’ + wx’y’ + xz
R. w’y’z’ + wx’y’ + xyz + xy’z
S. x’y’z’ + wx’y’ + w’y
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P only
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Q and S
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R and S
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S only
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BC'D' + A'C'D + AB'D
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ABC' + ACF + B'C'D
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ACD' + A'BC' + AC'D'
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A'BD + ACD' + BCD'
The dual of the expression derived in the following table is
|
|
$C$ |
$\bar C$ |
| $\bar A$ |
$\bar B$ |
0 |
0 |
| $\bar A$ |
$ B$ |
1 |
1 |
| $\bar A$ |
$\bar B$ |
1 |
1 |
| $A$ |
$\bar B$ |
0 |
1 |
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$X = AC + B$
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$X = A\bar B$
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$X = AB\bar C$
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$X = AB + ABC + A\bar B$
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BC' D' + A'C'D + AB'D
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ABC' + ACD + B'C'D
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ACD' + A' BC' + AC'D'
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A'BD + ACD' + BCD'
A
Correct answer
Explanation
On solving above k-map we get $AB’D+C’D+BC’D’$
So Ans is (1).
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a + a * (b - c) + (b - c) *d
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a + a × (b - c) + (b - c) * (e/f)
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a*a + (b - c) + (b - c) * (e/f)
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a + a* (b - c) + (b + c) * (e/f)
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(X + Y + Z) (X + Y + $\bar{Z}$) (X + Y + $\bar{Z}$) ($\bar{X}$ + Y + $\bar{Z}$)
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(X + $\bar{Y}$ + Z) ($\bar{X}$ + Y + $\bar{Z}$) ($\bar{X}$ + $\bar{Y}$ + Z) ($\bar{X}$ + $\bar{Y}$ + $\bar{Z}$)
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(X + Y + Z) ($\bar{X}$ + Y + $\bar{Z}$) (X + $\bar{Y}$ + Z) ($\bar{X}$ + $\bar{Y}$ + $\bar{Z}$)
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(X + $\bar{Y}$ + $\bar{Z}$) (X + Y + Z) (X + $\bar{Y}$ + Z) (X + Y + Z)
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$(\bar{X} + \bar{Y}+ \bar{Z}).(\bar{X} + Y + Z).(X + \bar{Y}+\bar{Z})$
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$(X + Y + Z).(X + \bar{Y} + \bar{Z}).(\bar{X} + Y + Z)$
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$(\bar{X} + \bar{Y} + Z).(\bar{X} + y + \bar{Z}). (X + \bar{Y}+ Z).(X + Y + \bar{Z}).(X + Y + Z)$
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$( X + y + \bar{Z}) . (\bar{X} + Y + Z). (\bar{X} + Y + \bar{Z}).(\bar{X} + \bar{Y}+ \bar{Z})$
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{(de)2 + (abc)2}/ abcde
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{(de)2 - (abc)2}/ abcde
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{(de)2 - (abc)2}/ abde
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{(de)2 - (abc)2}/ de
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{(de)2 - (abc)2}/ abc
B
Correct answer
Explanation
Given expression is (abc/de).
Additive inverse of the given expression is (- abc/de).
Thus, abc/de - abc/de = 0
Multiplicative inverse of the given expression is (de/abc).
Thus, abc/de x de/abc = 1
So, the required sum of additive inverse and multiplicative inverse = - abc/de + de/abc
= {(de)2 - (abc)2}/ abcde
A
Correct answer
Explanation
Factors of 15 = 1, 3, 5, 15
Factors of 20 = 1, 2, 4, 5, 10, 20
Greatest common factor = 5
Factors of 5 are = 1 and 5
So, factors of 5 are 2 in numbers.
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28xy + 26 + 37x + 21y
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28xy + 26 + 37y + 21x
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28xy + 25 + 35y + 20x
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28xy + 25 + 35x + 20y
D
Correct answer
Explanation
(7x + 5) (4y + 5)
= 28xy + 35x + 20y + 25 (Using Foil)
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u2 - uv + v2
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u2 - 2uv + v2
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u2 + 2uv + v2
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u2 - 2uv - v2
B
Correct answer
Explanation
(u - v) (u - v)
= u2 - uv - uv + v2 (Using Foil)
= u2 - 2uv + v2