Mathematics · Quantitative Aptitude
Algebraic Expressions and Polynomials
275 Questions
Algebraic expressions and polynomials form the foundation of algebra, involving variables, constants, and mathematical operations. This topic is heavily tested in the quantitative aptitude sections of SSC, banking, and state exams. Use these questions to practice expanding, factoring, and simplifying various polynomial expressions.
Expanding algebraic expressionsFactoring polynomialsAlgebraic identitiesFinding common factorsSimplifying numerical statements
Algebraic Expressions and Polynomials Questions
C
Correct answer
Explanation
1^0 = 1 (any non-zero number to power 0 is 1). 0^1 = 0. 0^0 is undefined/indeterminate in mathematics, but sometimes defined as 1 in combinatorics contexts. 1^1 = 1. If we treat 0^0 as 1: 1 + 0 + 1 + 1 = 3, which matches option C.
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A^2 + B^2 + 2xAxB
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A^2 + B^2 - 2xAxB
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A^2 + B^2
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NO IDEA
A
Correct answer
Explanation
The square of a binomial (A+B)^2 is calculated as (A+B)(A+B) = A^2 + AB + BA + B^2, which simplifies to A^2 + B^2 + 2AB. Option 407806 is the standard mathematical identity.
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A^2 + B^2 + 2xAxB
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A^2 + B^2 - 2xAxB
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A^2 - B^2
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(A-B)X(A+B)
B
Correct answer
Explanation
The algebraic identity (A - B)² expands to A² - 2AB + B², which can be written as A² + B² - 2AB. This is derived by multiplying (A - B)(A - B) using the distributive property. Option A incorrectly shows +2AB instead of -2AB.
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A^3+B^3+2AB(A+B)
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A^3+B^3+3AB(A+B)
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A^3+B^3+2AB(A^2+B^2)
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A^3+B^3+AB(A^2+B^2)
B
Correct answer
Explanation
The expansion of (A + B)³ is A³ + 3A²B + 3AB² + B³, which can be factored as A³ + B³ + 3AB(A + B). This is a standard algebraic identity. Option A incorrectly uses 2AB instead of 3AB, while options C and D have incorrect structures.
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A^3-B^3-3xAxB(A-B)
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A^3+B^3+3xAxB(A-B)
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A^3+B^3-3xAxB(A+B)
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A^3+B^3+3xAxB(A+B)
A
Correct answer
Explanation
The algebraic expansion of (A-B)^3 is A^3 - B^3 - 3AB(A-B). This can also be written as A^3 - 3A^2B + 3AB^2 - B^3. Option 407822 correctly represents the factored form of the subtraction terms.
D
Correct answer
Explanation
The product contains the term (x - x) because the sequence goes from a to z. Since (x - x) = 0, the entire product is 0. The highest power of x in the resulting constant 0 is 0.
C
Correct answer
Explanation
Remember that any non-zero number raised to the power 0 equals 1: 5^0 = 1, 1^15 = 1, 8^0 = 1, 1^23 = 1. So 1 + 1 - 1 - 1 = 0. Option C is correct. A common mistake is forgetting that 1 raised to any power is still 1.
C
Correct answer
Explanation
Calculate each term: 2^2 = 4, 5^2 = 25, 2 x 2 x 5 = 20. Sum: 4 + 25 + 20 = 49. This is the expansion of (a + b)^2 = a^2 + b^2 + 2ab where a = 2 and b = 5, so (2 + 5)^2 = 49. Option C is correct.
D
Correct answer
Explanation
One factor is 0^6. Any non-zero number raised to any positive power is still non-zero, but when multiplied by 0, the entire product becomes 0. Option D is correct. The other terms (5^3 = 125, 3^4 = 81, 1^5 = 1) don't matter once 0 appears.
C
Correct answer
Explanation
For quadratic ax²+bx+c=0, sum of roots = -b/a = -2/4 = -1/2, product = c/a = 1/4. Their sum is -1/2+1/4 = -1/4. This uses Vieta's formulas for root relationships.
D
Correct answer
Explanation
This is identical to question 115619. For 4x²+2x+1=0: sum of roots = -2/4 = -1/2, product = 1/4. Adding gives -1/4, consistent with Vieta's formulas for quadratic equations.
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n(n+1)/2
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n(n+1)(2n+1)/6
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[n(n+1)]^2
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all of the above
B
Correct answer
Explanation
The formula for the sum of the squares of the first n natural numbers (1^2 + 2^2 + ... + n^2) is given by n(n+1)(2n+1)/6. The other options represent the sum of n numbers or the sum of cubes.
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1
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1+2
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3ABAC
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None of the above
B
Correct answer
Explanation
The FIELD function extracts a substring between two occurrences of a delimiter. FIELD("+1+2+3ABAC", "+", 2, 4) means: find the substring between the 2nd and 4th occurrences of "+". The delimiters are at positions: 1st at 0, 2nd at 2, 3rd at 4, 4th at 6. The substring between positions 2 and 4 is "1+2".
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{(de)2 + (abc)2}/ abcde
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{(de)2 - (abc)2}/ abcde
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{(de)2 - (abc)2}/ abde
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{(de)2 - (abc)2}/ de
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{(de)2 - (abc)2}/ abc
B
Correct answer
Explanation
Given expression is (abc/de).
Additive inverse of the given expression is (- abc/de).
Thus, abc/de - abc/de = 0
Multiplicative inverse of the given expression is (de/abc).
Thus, abc/de x de/abc = 1
So, the required sum of additive inverse and multiplicative inverse = - abc/de + de/abc
= {(de)2 - (abc)2}/ abcde
A
Correct answer
Explanation
Factors of 15 = 1, 3, 5, 15
Factors of 20 = 1, 2, 4, 5, 10, 20
Greatest common factor = 5
Factors of 5 are = 1 and 5
So, factors of 5 are 2 in numbers.